A gardener has a flower pot that he wants to fill with dirt. The flower pot has a radius of 8 cm at its opening and a radius of 7 cm at its base. The flower pot has a height of 10 cm.

Part A:
Provide an estimate for the amount of dirt, in cubic centimeters, that the gardener will need to completely fill the flower pot.

Part B:
Explain how you determined your answer.

Part A: The approximate volume of the frustum is [tex]1769cm^3[/tex].

Part B: How the answer was determined was to view the flower pot as a frustum of a cone, and apply the formula in calculating the volume of the flower-pot.

The flower pot has the shape of a conical frustum (See the attached image). The volume of the frustum is given by

[tex]F = \frac{\pi y}{3}(R^2+Rr+r^2)[/tex]

where

[tex]y=\text{height of the frustum}=H-h=10cm\\R=\text{radius of larger cone}=8cm\\r=\text{radius of smaller cone}=7cm[/tex]

substituting the values of [tex]y[/tex], [tex]R[/tex] and [tex]r[/tex] into the frustum formula and using [tex]\pi\approx 3.14[/tex]

[tex]F = \frac{\pi y}{3}(R^2+Rr+r^2)\\\\=\frac{\pi\times 10 }{3}(8^2+8\times 7+7^2)\\\\=\frac{10\pi}{3}(64+56+49)\\\\=\frac{1690\pi}{3}\\\\\approx 1769cm^3[/tex]

the approximate volume of the frustum is [tex]1769cm^3[/tex]

Learn more about the volume of a frustum here: https://brainly.com/question/14177094

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