A football player kicks a ball with an initial velocity of 25 m/s at an angle of 53 degrees above the horizontal. The vertical component of the initial velocity of the ball

Answers

Answer 1

Answer:

20 m/s

Explanation:

initial velocity, u= 25m/s

u has two components. one in horizontal and in one vertical.

so,

u sin theta = vertical component.

=> u sin theta = 25× 4/5

= 20 m/s


Related Questions

Desde un rascacielos de 300 m de altura se lanza un objeto con una velocidad inicial de 50 m/s. Calcula el tiempo que transcurre hasta que llega al suelo y con qué velocidad llega en cada uno de los casos: a) Si se lanza verticalmente hacia arriba. b) Si se lanza verticalmente hacia abajo. c) Si se lanza horizontalmente (En este caso calcular también la distancia al edificio cuando llega al suelo) d) Si se lanza con un ángulo de 30o (Calcular también distancia al edificio)

Answers

Answer:

a) t = 14.2 s ,  v = -92 m / s , b) v = - 59.16 m / s ,   t = 0.916 s

c)  t = 7.75 s ,   x = 387.5 m

d) t = 10.64 s , x = 463.9 m ,   v = 92.2 m / s

Explanation:

This is an exercise in kinematics, suppose we take the upward direction as positive

a) is thrown up vertically.

Let's use the equation

          y = y₀ + v₀ t - ½ g t²

When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²

         0 = y₀ + v₀t - ½ g t²

         ½ 10 t² - 50 t - 300 = 0

Let's solve the quadratic equation

         t² - 10 t - 60 = 0

         t = [10 ±√ (10² + 4 60)] / 2

         t = [10 ± 18.4] / 2

         t₁ = 14.2 s

         t₂ = -4.2 s

since time must be a positive quantity, the correctors result t = 14.2 s

the speed at this point is

         v = v₀ - g t

         v = 50 - 10 14.2

         v = -92 m / s

the sign indicates that the body is going down

b) in this case the initial velocity is vo = -50 m / s

let's calculate the velocity on the ground

    v² = v₀² - 2g (y-y₀)

    v² = 50 2 - 2 10 ((0- 300)

    v² = 3500

     

    v = + - 59.16 m / s

as the body is going down the correct sign is the negative

    v = - 59.16 m / s

the time it takes to arrive is

        v = v₀ - g t

        t = (v₀ - v) / g

        t = (-50 + 59.16) / 10

        t = 0.916 s

c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0

         y = y₀ + v₀ t - ½ g t²

         0 = 300 + 0 - ½ 10 t²

         t = √ (2 300/10)

         t = 7.75 s

the horizontal displacement at this time is

 

        x = v₀ₓ t

        x = 50 7.75

        x = 387.5 m

d) as it is thrown with an angle let's find each component of the velocities

      v₀ₓ = v₀ cos 30

      [tex]v_{oy}[/tex] = v₀ sin 30

       v₀ₓ = 50 cos 30 = 43.3 m / s

       v_{oy} = 50 sin 30 = 25 m / s

we look for the time of descent

     y = y₀ + v_{oy} t - ½ g t²

     0 = y₀ + v_{oy} t - ½ g t²

     0 = 300 + 25 t - ½ 10 t²

     t² - 5t - 60 = 0

   we solve the second degree equation

     t = [5 ±√ (5² + 4 60)] / 2

     t = [5 ± 16.28] / 2

     t₁ = 10.64 s

     t₂ = -5.64 s

since the time must be positive the result is t = 10.64 s

the range on the x axis is

       x = v₀ₓ t

       x = 43.6 10.64

       x = 463.9 m

the ground speed is

      v_{y} = [tex]v_{oy}[/tex] - g t

      v_{y} = 25 - 10 10.64

      v_{y} = -81.4 m / s

speed is

       v = √ (v₀ₓ² + v_{y}²)

       v = √ (43.3² + 81.4²)

       v = 92.2 m / s

how can you show that pressure increases with the increase of force?​

Answers

Answer:

...........................

Pressure is defined as Force/area
So what do you think?

Which describes an interaction within the musculoskeletal system?

Answers

Answer:

The musculoskeletal system involves the complex interactions of muscles, bones, and connective tissues.

When a muscle contracts, a bone will move. When a bone contracts, a muscle will move. When a ligament contracts, a tendon will move.

Answer:

A. when a muscle contracts , a bone will move

Explanation

thats the correct answer to this question on edg2021 :)

b) A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to
buy the watch?
indir

Answers

Answer:

rs 900

Explanation:

the process is given

A tennis ball is beaten downward with an initial speed of 5 m/s.
How fast, in m/s, is the ball falling after 3 seconds (neglect air
friction, so g = 9.8 m/s2)?

a 34.4
b 34.4
C 9.8
d 9.8
e 5

Answers

Answer:

34.4m/s

Explanation:

Step one:

given data

initial speed u= 5m/s

time t= 3seconds

acceleration due to gravity g= 9.8m/s^2

Required:

the final velocity v

Step two:

applying the first equation of motion

v=u+gt-----------we used + because the ball is falling with gravity

v=5+9.8*3

v=5+29.4

v=34.4

The final velocity is 34.4m/s

Answer:

-34.4

Explanation:

the person above had the right approach but it would be negative as it is in a downwards motion

An object moves along the grid through the points A, B, C, D, E, and Fas shown below.

Find the distance covered by the moving object.

The object moves 3 km to the East, turns North for 1 km, turns west for 1.5 km, moves

north 0.5 km, and finally turns east for 0.5 km.

Answers

Answer:

Total distance = 6.5 km

Explanation:

Let the distance be denoted by the vectors drawn from A, B, C, D, E, and F.

Then the distance covered can be calculated by adding the vectors in the direction given.

Total distance = 3km + 1km+ 1.5km+ 0.5km+ 0.5km

Total distance = 6.5 km

If we were to find the displacement ( shortest distance) then the head to tail rule would be applied using the vectors.


When we describe both the speed and direction of motion, we are
descriting its acceleration.
True
False

Answers

Answer:

True

Explanation:

18. How much force would it take to push another, larger friend who has a mass of 70 Kg to accelerate
at the same rate of 4 m per sec every sec

Answers

Answer:

280N

Explanation:

f = mass x acceleration

A car is driving down the road at 35 m/s when the driver slams on the brakes. The car stops in a distance of 75 meters. The braking force necessary to do this is 9,800 Newtons. How much work do the brakes perform stopping the car?

Answers

Answer:

If the car is initially travelling at u m/s, then the stopping distance d m travelled by ... the speed of the car at the instant the brakes are applied. ... Common usage will force us to depart from this later in the notes. ... The history of these equations is not absolutely clear, but we do have some ... Newton (1642–1727) and Leibniz.

Explanation:

hope this helped

State the career function of production engineering​

Answers

Answer:

Production Engineering defines and works out how the product will be manufactured and/or assembled on the production line including design of packaging, ensuring the right quantity of components/products are delivered and aligned to support the speed of the production line.

Explanation:

Answer:

Production Engineers are responsible for supervising and improving production at plants and factories. They support engineering teams, draw up safety protocols, report issues to the Manager, and develop strategies to improve efficiency and profit.

Explanation:

a motorcycle starts from rest covers 200 meter distance in 6 second calculate final velocity and acceleration​

Answers

Explanation:

s = ut + 1/2 a t^2

200 = 0 * 6 + 1/2 * a * (6)^2

200 = 1/2 * a * 36

200 = 18 a

a = 200/18

a= 11.1m/sec^2

v = u + at

v = 0 + 11.1 * 6

v = 66.6m/s

hope it helps you

Pitch describes how high or low a sound is. The pitch of a sound is most dependent upon the of the sound wave.
A.
amplitude
B.
rarefaction
C.
frequency
D.
wavelength

Answers

Answer: C. Frequency

Answer:

The answer is C

Explanation:

Please simplify and write the below paragraph.
The field lines due to a current in a
circular coil become straight and
perpendicular to the plane of the coil
at the centre. This is because at every
point of circular loop the concentric
circles representing the magnetic field
become larger and larger as we move
away from the wire.

Answers

Field lines become straight and perpendicular because every point of circular loop the concentric circles become larger and larger as we move away from the wire.

Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East.

What distance did she cover? Please include the number and unit.

What was the magnitude of her displacement? Please include the number and unit.

What was the direction of her displacement? Please abbrieviate (N, S, E, W, etc.)

Answers

Explanation:

Given that,

Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East. At first she traveled North and then East. They are perpendicular to each other.

Total path traveled = distance covered by an object

D = 7 km + 5 km = 12 km

Shortest path covered = Displacement

[tex]d=\sqrt{7^2+5^2} \\\\d=8.6\ km[/tex]

For direction :

[tex]\tan\theta=\dfrac{d_y}{d_x}\\\\\tan\theta=\dfrac{7}{5}\\\\\theta=\tan^{-1}(\dfrac{7}{5})\\\\\theta=54.46^{\circ}[/tex]

She is moving in the direction of 54.46 degrees.

A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
Answer Quick plz!

Answers

Answer:

Explanation:

14

If a rock is dropped from the top of a tower at the front of it and takes 3.6 seconds to hit the ground. Calculate the final velocity of the penny in m/s. What is the height of the tower?

Answers

Answer:

35.28m/s; 63.50m

Explanation:

Given the following data;

Time, t = 3.6 secs

Since it's a free fall, acceleration due to gravity = 9.8m/s²

Initial velocity, u = 0

To find the final velocity, we would use the first equation of motion;

[tex] V = u + at[/tex]

Substituting into the equation, we have;

[tex] V = 0 + 9.8 * 3.6[/tex]

V = 35.28m/s

Therefore, the final velocity of the penny is 35.28m/s.

To find the height, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Substituting the values into the equation;

[tex] S = 0(3.6) + \frac {1}{2}*9.8*(3.6)^{2}[/tex]

[tex] S = 0 + 4.9*12.86[/tex]

[tex] S = 0.5 *36[/tex]

S = 63.50m

Therefore, the height of the tower is 63.50m.

What is the net force (including direction and magnitude) acting on the object on the above left?

Answers

Answer:

Explanation:

the net force on the right left is 25 N and is directed upward

the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero

i hope this will help you

The net force on the right left is 25 N and is directed upward.

The net force on the left one is zero because 200 N force act upward and 200 N force act downward so both cancel each other and net force is zero.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

By looking at both figure we get idea of net force after calculation,

The net force on the right left is 25 N and is directed upward.

The net force on the left one is zero because 200 N force act upward and 200 N force act downward so both cancel each other and net force is zero.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ2

Which refers to the ratio of output work to input work of a machine expressed as a percent?

total work
wattage
efficiency
power

Answers

Answer: C.) Efficiency

Explanation: Edge 2020 good luck ^__^

Can any kind soul help me please​

Answers

Explanation:

Hey there!

Given;

Mass of the Earth (M) = 6.0*10^24kg.

Radius of Earth (R) = 6400km = 6400*1000= 6.4*10^6.

Gravitational constant (G) = 6.67*10^-11Nm^2/kg^2.

Height from surface of Earth (h) = 350km= 3.5*10^5m

Gravity (g) = ?

We have;

[tex]g = \frac{G.M}{ {(R + h)}^{2} } [/tex]

Where "G" is gravitational constant, "M" is mass of earth, "g" is acceleration due to gravity, "h" height from surface of Earth.

Keep all values.

[tex]g = \frac{6.67 \times {10}^{ - 11} \times 6.0 \times {10}^{24} }{ (6.4 \times {10}^{6} + 3.5 \times {10}^{5} )^2} [/tex]

[tex]or \: g = \frac{40.002\times {10}^{13} }{ (6.4\times {10}^{6} + 3.5*10^5)^2} [/tex]

g = 8.7m/s^2

Therefore, gravity from distance 350km above the Earth's surface is 8.7m/s^2.

Hope it helps...

Chuck Is driving from Chicago to Miami, in one hour he drives 120 km. What is Chuck’s average velocity?

Answers

Answer:

Chuck's average speed is 60.

Meteorites are of three kinds: stones, irons, and stony irons. Each
corresponds to a different part of planet formation. The stones resemble
pieces of planetary crust and mantle, the irons the planet cores, and the
stony irons the transitional area between core and mantle. In some stony
irons, translucent crystalline structures interpenetrate with opaque mantle
rock Collectors sometimes cut stony irons into thin slices and illuminate
them from one side for a gorgeous stained glass effect. Only one per cent
of all meteorites are stony irons. Five per cent are irons, and the remaining
ninety-four per cent are stones. The main function of the paragraph is to:
identify the three kinds of meteorites and provide information about each kind,
describe the chemical structure of the different types of rock found within the
meteorites classified as stones
explain why some meteorites contain both crystalline structures and opaque mantle
rock
list common ways collectors display pieces of meteorites.

Answers

Answer:

cookie

Explanation:

What are the ways of heat transfer?

Answers

Answer:

Conduction, Convection and Radiation

Explanation:

Hope this helps!

Conduction radiation and convection

what is displacement and distance

Answers

Answer:

Displacement is how far you are between your initial and finishing position.

Distance is how far you went.

Explanation:

For example, using a baseball field... if the sides are each 100 m..

A batter runs to third base... what is his displacement and distance?

Since the batter ran to 3rd base, it means he ran 300 m to get to 3rd base but his displacement is 100 m becuase that's how far they are from home plate. (which was their starting position)

So the answer to my example above would be:

Distance: 300 m

Displacement: 100 m

I hope this helped you.

Guys plz help answer this!!1

Answers

Answer:

its false for sure, its water that becomes to glucose

Two blocks are connected as shown in the diagram below. Assume that the ramp is frictionless. Draw the force diagram for the block on the ramp

x-apple-ql-id://72E64017-DA83-43AB-B493-EDC462018E16/x-apple-ql-magic/35856A40-E2D1-4A5F-A1C7-B39A61D6F3E7.pdf

What is the x-component of the force of gravity acting on the block on the ramp?
What is the acceleration of the block?

Answers

Answer:

diagram: see image, x-component: 84.3 N, acceleration: 4.38 m/s^2

Explanation:

(see image for further explanation)

what was the temperature changes in Celsius degrees if it is
changed from 44°F to -56°F?

Answers

Answer:

so, the answer is 56 whole number if round it, or 55.6(round it to 10th decimal)

Explanation:

(formula, idk it is wrong or right)   °C =°F - 32 then / 1.8000

44°F =  6.6666666667°C

-56°F = -48.888888889°C

So, if u want whole number as the answer

it is something like 6.6666666667°C +  48.888888889°C = 55.5555555557 °C

so, so, the answer is 56 whole number if round it, or 55.6(round it to 10th decimal)

I will mark brainliest !!

Answers

Answer:

i think its b

Explanation:

Identify the 3 types of energy transfer shown in the diagram.

Answers

Answer:

1.Conduction.

2.Convection.

3.Radiation.

Explanation:

I'm sure it's correct

Can any kind soul help me​

Answers

Answer:

2917.4 m/s

Explanation:

From the question given above, the following data were:

Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth

Radius (r) of the Moon = 1737 Km

Escape velocity (v) =?

Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:

Gravitational acceleration of the earth = 9.8 m/s²

Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth

= 0.25 × 9.8 = 2.45 m/s²

Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:

1 Km = 1000 m

Therefore,

1737 Km = 1737 Km × 1000 m / 1 Km

1737 Km = 1737000 m

Thus, 1737 Km is equivalent to 1737000 m

Finally, we shall determine the escape velocity of the rocket as shown below:

Gravitational acceleration of the Moon (g) = 2.45 m/s²

Radius (r) of the moon = 1737000 m

Escape velocity (v) =?

v = √2gr

v = √(2 × 2.45 × 1737000)

v = √8511300

v = 2917.4 m/s

Thus, the escape velocity is 2917.4 m/s

Can someone please help me with this, this question goes with my second most recent question.​

Answers

The ship will speed up while the engine is firing.

Whatever speed it has when the engine cuts off, it will continue at that speed (and in a straight line) from then on, because there's no force acting on it, so it can't have any acceleration.

That's the 3rd choice.

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