A dog sits 1.50m from the center of the merry-go-around and revolves at a tangential speed of 1.80m\s. If the dog’s mass is 18.5kg, what is the magnitude of the centripetal force on the dog?


A) 25.53n
B) 32.51n
C) 39.96n
D) 42.55n

Answers

Answer 1

Answer:

39.96 N

Further explanation:

Given

radius=R=1.5 m

Tangential speed =v=1.80m\s

mass of the dog=18.5 kg

Required

The magnitude of the centripetal force

Analysis

Use Centripetal force formula :

[tex]]\large{\boxed{\bold{F= \frac{mv^2}{R}}}[/tex]

F = centripetal force , N  

m = mass , Kg  

v = linear velocity/tangential  , m/s  

r = radius , m  

Solution

[tex]\tt F=\dfrac{18.5\times 1.8^2}{1.5}\\\\F=39.96~N[/tex]

Paraphrase

The magnitude of the centripetal force on the dog : 39.96 N


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Answer:

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Answers

Answer:

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