A cheery tree is 6 feet tall. A palm is 3 times as tall as the cherry tree. Which model represents this problum

Answer:

speed = 78 miles per hour

Step-by-step explanation:

Speed is distance divided by time

speed = 234 miles / 3 hours

speed = 78 miles per hour

Answer:

98?

Step-by-step explanation:

Answer:

Step-by-step explanation:

First,

7 times 8 = 7 × 8 = 56

Then,

The product divided by 2 = 56 ÷ 2 = 28

Hence,

The required answer is 28

Answer:

The answer is LINEAR EQUATIONS

Step-by-step explanation:

Hope you have a great day :)

Answer:

its not loading

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

90°

Step-by-step explanation:

It's simple, the angle of a line is 180°

∠EFG=90°

Line GD-∠EFG=180°-90°=90°

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Answer:

4/5 of a fruit bar

Step-by-step explanation:

Answer:

7776pi cubic inches

Step-by-step explanation:

Answer:

Step-by-step explanation:

Step-by-step explanation:

Thanks, so cube root of 512 is 8 and reciprocal of 0.4 is 2.5 then:

8 : 2.5 / divide both by 2.5 to get:

3.2 : 1 that's my answer right?

The correct form of the ratio of cube root of 512: reciprocal of 0.4 is 3.2:1

It is a number y such that y to the power 3 is equal to x.

We have to find the ratio of cube root of 512 and the reciprocal of 0.4  which will be as follows

cube root of 512:  reciprocal of 0.4

8: 1/0.4

8=2.5

dividing by 2.5

3.2 : 1

Hence the ratio will be 3.2 :1 of cube root of 512 and the reciprocal of 0.4

Learn more about cube root at https://brainly.com/question/310302

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Answer:

[tex](a)\ Pr = \frac{2}{5}[/tex]

[tex](b)\ Pr = \frac{9}{20}[/tex]

[tex](c)\ E(Orange) = 100[/tex]

[tex](d)\ E(Orange) = 62.5[/tex]

Step-by-step explanation:

Solving (a): Theoretical probability of green or yellow

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 5[/tex] --- i.e. 5 sections

[tex]Yellow = 1[/tex]

[tex]Green = 1[/tex]

So, the probability is:

[tex]Pr = P(Yellow)\ or\ P(Green)[/tex]

[tex]Pr = \frac{Yellow}{n} + \frac{Green}{n}[/tex]

[tex]Pr = \frac{1}{5} + \frac{1}{5}[/tex]

Take LCM

[tex]Pr = \frac{1+1}{5}[/tex]

[tex]Pr = \frac{2}{5}[/tex]

Solving (b): Experimental probability of green or yellow

Here, we consider the result of the experiment

From the attached image, we have:

[tex]n= 40[/tex] --- i.e. 40 spins

[tex]Yellow = 12[/tex]

[tex]Green = 6[/tex]

So, the probability is:

[tex]Pr = P(Yellow)\ or\ P(Green)[/tex]

[tex]Pr = \frac{Yellow}{n} + \frac{Green}{n}[/tex]

[tex]Pr = \frac{12}{40} + \frac{6}{40}[/tex]

Take LCM

[tex]Pr = \frac{12+6}{40}[/tex]

[tex]Pr = \frac{18}{40}[/tex]

Simplify

[tex]Pr = \frac{9}{20}[/tex]

Solving (c): Expectation of orange outcomes in a spin of 500 times, theoretically.

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 5[/tex] --- i.e. 5 sections

[tex]Orange = 1[/tex]

So, the probability of having an outcome of orange in 1 spin is:

[tex]Pr = P(Orange)[/tex]

[tex]Pr = \frac{Orange}{n}[/tex]

[tex]Pr = \frac{1}{5}[/tex]

In 500 spins, the expectation is:

[tex]E(Orange) = Pr * 500[/tex]

[tex]E(Orange) = \frac{1}{5} * 500[/tex]

[tex]E(Orange) = 100[/tex]

Solving (c): Expectation of orange outcomes in a spin of 500 times, base on experiments.

Here, we consider the spinner itself

From the attached image, we have:

[tex]n= 40[/tex] --- i.e. 40 spins

[tex]Orange = 5[/tex]

So, the probability of having an outcome of orange is:

[tex]Pr = P(Orange)[/tex]

[tex]Pr = \frac{Orange}{n}[/tex]

[tex]Pr = \frac{5}{40}[/tex]

[tex]Pr = \frac{1}{8}[/tex]

In 500 spins, the expectation is:

[tex]E(Orange) = Pr * 500[/tex]

[tex]E(Orange) = \frac{1}{8} * 500[/tex]

[tex]E(Orange) = 62.5[/tex]

Step-by-step explanation:

for mixed number to a improper fraction you take the whole number and times that by the denominator and add the numeriator

for example

[tex]8 \frac{3}{8} [/tex]

8 x 8 = 64

64 + 3 = 67

and after you get your last number (67) you put that over your original denominator which is 8 so it would be

[tex] \frac{67}{8} [/tex]

for the improper to mixed you see how many times you denominator goes into your numerator

another example is

[tex] \frac{13}{7} [/tex]

7 goes into 13 twice so your whole number is 2 and you have a remaining 1 so it would look like

[tex]2 \frac{1}{7} [/tex]

Answer:

A) 9/4

B) 67/8

C) 17/6

D) 9/2

E) 16/3

F) 127/12

G) 37/4

H) 41/6

Q) Whole Number: 1 Fraction: 6/7

R) Whole Number: 4 Fraction: 1/2

S) Whole Number: 1 Fraction: 8/9

T) Whole Number: 2 Fraction: 1/3

U) Whole Number: 2 Fraction: 3/7

V) Whole Number: 3 Fraction: 1/3

W) I am not 100% sure for this one but I think it's right.

Mixed Number - Whole Number: 1 Fraction: 5/8

Improper fraction - 13/8

Step-by-step explanation:

With improper fractions the first thing that you want to do is multiply the whole number with the denominator (the number on the bottom of the fraction), then add the numerator (the number on the top of the fraction). You also want to keep the denominator the same in both fractions.

When working with converting mixed fractions into improper fractions it is kind of the opposite, but it is a little harder to explain. Let's take letter Q as an example. If you know that you cannot divide the numerator and the denominator in anyway to make a whole number, the whole number will become a one and the numerator is how many are left. so in this case the answer for Q would be 1 6/7, 1 being the whole number and 6 from 6+7=13. now let's look at letter R, you know you can divide 2 four times into 9, the whole number will be 4 and the fraction will be 1/2, 4x2+1=9. You can also double check that you did it right by turning it back into a improper fraction from the mixed number state by multiplying the denominator with the whole number, then adding the numerator. Hope that made sense, send me a DM if you need more help!

Answer:

a) SAT score = 1075

b) ACT score = 19.2.

c) ACT score = 27.9.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

(A) If a student gets an SAT score that is the 51-percentile, find the actual SAT score

SAT scores have mean 1070 and standard deviation 204, so [tex]\mu = 1070, \sigma = 204[/tex]

51th percentile means that Z has a p-value of 0.51, so Z = 0.025. The score is X. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.025 = \frac{X - 1070}{204}[/tex]

[tex]X - 1070 = 0.025*204[/tex]

[tex]X = 1075[/tex]

SAT score = 1075.

(B) What would be the equivalent ACT score for this student?

ACT scores have mean of 19.1 and standard deviation of 5.2, which means that [tex]\mu = 19.1, \sigma = 5.2[/tex]. The equivalent score is X when Z = 0.025. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.025 = \frac{X - 19.1}{5.2}[/tex]

[tex]X - 19.1 = 0.025*5.2[/tex]

[tex]X = 19.2[/tex]

ACT score = 19.2.

(C) If a student gets an SAT score of 1417, find the equivalent ACT score.

Z-score for the SAT:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1417 - 1070}{204}[/tex]

[tex]Z = 1.7[/tex]

Equivalent score on the ACT:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.7 = \frac{X - 19.1}{5.2}[/tex]

[tex]X - 19.1 = 1.7*5.2[/tex]

[tex]X = 27.9[/tex]

ACT score = 27.9.

Answer:

[tex]P(Work | Senior) = 0.14[/tex]

Step-by-step explanation:

Given

The attached table

Required

[tex]P(Work | Senior)[/tex]

This is calculated using:

[tex]P(Work | Senior) = \frac{P(Work \ n\ Senior)}{P(Senior)}[/tex]

This gives:

[tex]P(Work | Senior) = \frac{n(Work \ n\ Senior)}{n(Senior)}[/tex]

From the table:

[tex]n(Work \ n\ Senior) = 5[/tex]

[tex]n(Senior) = 25 + 5+ 5 = 35[/tex]

So:

[tex]P(Work | Senior) = \frac{5}{35}[/tex]

[tex]P(Work | Senior) = 0.14[/tex]

Answer:

14%

Step-by-step explanation:

add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).

Answer:

He can lift 160 pounds

Step-by-step explanation:

125 (from last year) + 35 (more pounds) = 160 (total pounds)

125 + 35 = 160

Answer:

Step-by-step explanation:

1/48 + 5/6    

The LCD of 48 and 6 is 48 so we have:

1/48 + 40/48

= 41/38

Answer:

41/48

Step-by-step explanation:

Answer:

The father is 42 years old and the son is 12 years old.

Step-by-step explanation:

Since three years ago the sum of the ages of father and his son was 48 years, and three years hence father's age will be three times that of his are his, to find the present ages of the father and his are his, the following calculations must be performed:

F + S = 48

F + 6 + S + 6 = 3S

34 + 14 = 48 /// 34 + 6 = 40 --- 14 + 6 = 20 (x 3 = 60)

38 + 10 = 48 /// 38 + 6 = 44 --- 10 + 6 = 16 (x 3 = 48)

40 + 8 = 48 /// 40 + 6 = 46 --- 8 + 6 = 14 (x 3 = 42)

39 + 9 = 48 /// 39 + 6 = 45 --- 9 + 6 = 15 (x 3 = 45)

39 + 3 = 42

9 + 3 = 12

Therefore, the father is 42 years old and the son is 12 years old.

Answer:

2, 3, 4 (up to down)

Step-by-step explanation:

Rational: can be terminating, repeating, in a fraction

Irrational: Not terminating (ending), doesn't repeat (o.33333....), and you can't put it in a fraction

Hope this helps!!

p.s. brainliest plz

Answer:

[tex]6.7159[/tex]

Step-by-step explanation:

[tex]\mu=48.8\\n=35\\\bar{x}=53.8\\\sigma=4.4\\\alpha=1\%=0.01[/tex]

Null and alternative hypothesis :

[tex]H_0:\mu=48.8\\H_a:\mu>48.8[/tex]

Test statistic,

[tex]t=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]\Rightarrow t=\frac{53.8-48.8}{\frac{4.4}{\sqrt{35}}}[/tex]

[tex]\Rightarrow t=\frac{5\times 5.91}{4.4}[/tex]

[tex]\Rightarrow t=6.715[/tex]

Test statistic [tex]t=6.715[/tex]

[tex]P-[/tex]value [tex]=P(t>6.715)[/tex]

[tex]P-[/tex] value [tex]=0.0001[/tex]  by the p- table

Significance level [tex]0.01[/tex]

         [tex]p-[/tex]value [tex]<0.01[/tex]

  We reject [tex]H_0[/tex]

Answer:

The nth term is 27 - 30(n-1) or can be simplified to 57 - 30n.

Step-by-step explanation:

This is an arithmetic sequence (ie. each term equals the previous term with a constant value added (or subtracted from it)

T1 = 27

T2 = -3 = T1 - 30 = 27 - 30

T3 = -33 = T2 -30 = 27 -30 - 30=27-30X(2)

T4= -63 = T3 - 30 =27-30X(2)-30=27-30X(3)

In general, the nth term of this sequence:

S(n) = 27 - 30X(n-1)

Answer:

the answer is c

Step-by-step explanation:

Answer: 14 units

Step-by-step explanation:

Answer:

≈ 0.52

Step-by-step explanation:

P( head ) = 2/3 , P( tail ) = 1/3

when a head is tossed ; Gambler A wins $1

when a tail is tossed : Gambler B wins $1

Determine the P( Gambler A wins the game ) if he starts with I dollars

Assuming I = $1

n = 5

p ( head ) = P( winning ) = 0.66

p( losing ) = 0.33

applying the conditional probability in Markov which is ;

Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁

P( 1) = 0.66P₂ + 0.33P₀

resolving the above using with Markov probability

P( 1 ) = 0.51613

hence the probability of Gambler A winning the game if he starts with $1

≈ 0.52

Answer:

13 minutes

Step-by-step explanation:

The reason why it is 13 minutes is because you subtract 10:41 AM from 10:28 AM and you get 13 minutes.

Answer:

13

Step-by-step explanation:

41-28= 13

the hours don't change so you just need to subtract the minutes

Given:

The given sum is:

[tex]\sum _{k=4}^9(5k+3)[/tex]

To find:

The expanded form and find the sum.

Solution:

We have,

[tex]\sum _{k=4}^9(5k+3)[/tex]

The expanded form of given sum is:

[tex]\sum _{k=4}^9(5k+3)=(5(4)+3)+(5(5)+3)+(5(6)+3)+(5(7)+3)+(5(8)+3)+(5(9)+3)[/tex]

[tex]\sum _{k=4}^9(5k+3)=(20+3)+(25+3)+(30+3)+(35+3)+(4+3)+(45+3)[/tex]

[tex]\sum _{k=4}^9(5k+3)=23+28+33+38+43+48[/tex]

[tex]\sum _{k=4}^9(5k+3)=213[/tex]

Therefore, the correct option is C.