Answer:
The current in the circuit is 0.15 Ampere
Explanation:
The given parameters of the cell are;
The electromotive force (e.m.f.) of the cell, E = 1.5 V
The resistance of the cell, r = 2.5 ohm
The resistance of the ammeter = 0.5 ohm
The resistance of the resistor = 7.0 ohm
The formula for the e.m.f., E of a cell is given as follows;
e.m.f. E = I·(R + r)
Where;
I = The current in the circuit
R = The sum of the resistances in the circuit = 7.0 Ω + 0.5 Ω + 2.5 Ω = 10 Ω
Therefore, we have;
[tex]The \ current \ in \ the \ circuit, \ I = \dfrac{E}{R + r}[/tex]
Substituting the known values, gives;
[tex]I = \dfrac{1.5 \ V}{7 \ \Omega + 0.5 \ \Omega + 2.5 \ \Omega} = \dfrac{1.5 \ V}{10 \ \Omega} = 0.15 \ A[/tex]
The current in the circuit, I = 0.15 Ampere.
A 5.0 kg chunk of putty moving at 10m/s collides and sticks to a 7.0 kg bowling ball that is initially at rest.What is the total momentum of the bowling ball and the putty after they collide?
Answer:
Total momentum = 50kgm/s
Explanation:
Given the following data;
Mass, M1 = 5kg
Mass, M2 = 7kg
Velocity, V1 = 10m/s
Velocity, V2 = 0m/s (since it's at rest).
To find the total momentum;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
[tex] Momentum = Mass * Velocity [/tex]
The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.
Total momentum = M1V1 + M2V2
Substituting into the equation, we have;
Total momentum = 5*10 + 7*0
Total momentum = 50 + 0
Total momentum = 50 kgm/s
Therefore, the total momentum of the bowling ball and the putty after they collide is 50 kgm/s.
A bobsled has a momentum of 4000 kg•m/s to the south. Friction on the
track reduces its momentum to 2500 kg•m/s to the south. What impulse is
applied to the bobsled by the friction?
Answer:
1500 north
Explanation:
Answer: 1500 north
Explanation:
Impulse is change of momentum. Since the numbers are already in units of momentum, you just need to subtract one from the other to find the impulse. 4000 - 2500 = 1500. Because the bobsled is traveling south and slowing down, the impulse will be in the opposite direction, or north.
1500 north.
What is the mass of the object if it exerted a
force of 62.2 Newtons and has an acceleration
of 15.3 m/s2?
Answer:
The object has an approximate mass of 4.06 kilograms.
Explanation:
Force is equal to mass times acceleration, so all we need to do is divide the force provided by the acceleration provided.
[tex]m = \frac{62.2N}{15.3 \frac{m}{s^2}}\\\\m = \frac{62.3kg\frac{m}{s^2}}{15.3 \frac{m}{s^2}}\\\\m = \frac{62.2kg}{15.3}\\\\m = 4.06kg[/tex]
Look at the atoms below
a. Atom W: 9 protons and 9 neutrons
b. Atom X: 8 protons and 9 neutrons
c. Atom Y: 9 protons and 9 neutrons
d. Atom Z: 9 protons and 10 neutrons
Which ones below are isotopes of each other and why?
element z are isotopes because number of netron are different and number of protons are same
An empty airplane with a mass of 200,000 kg must have a speed of 82 m/s to achieve takeoff. Once it is fully loaded, the airplane has a mass of 350,000 kg. It has 3200 m of runway. a) How much force is needed to get the full airplane safely in the air?
b) How much runway would the empty airplane use if its engines generated the same force?
Answer:
a) A force of 367718.75 newtons is needed to get the full airplane safely in the air.
b) The empty airplane would need a runway of 1828.571 meters.
Explanation:
a) This problem can be solved by using the Work-Energy Theorem, which states that work needed by the airplane to get minimum speed is equal to its change in translational kinetic energy, both measured in joules. The resulting formula is presented below:
[tex]F\cdot \Delta s = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})[/tex] (1)
Where:
[tex]F[/tex] - Minimum net force, measured in newtons.
[tex]\Delta s[/tex] - Runway length, measured in meters.
[tex]m[/tex] - Mass of the airplane, measured in kilograms.
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the airplane, measured in meters per second.
If we know that [tex]m = 350000\,kg[/tex], [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 82\,\frac{m}{s}[/tex] and [tex]\Delta s = 3200\,m[/tex], then the minimum net force needed by the airplane to get itself safely in the air:
[tex]F = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot \Delta s}[/tex]
[tex]F = \frac{(350000\,kg)\cdot \left[\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (3200\,m)}[/tex]
[tex]F = 367718.75\,N[/tex]
A force of 367718.75 newtons is needed to get the full airplane safely in the air.
b) If we know that [tex]m = 200000\,kg[/tex], [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 82\,\frac{m}{s}[/tex] and [tex]F = 367718.75\,N[/tex], then the length of the runway is:
[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F}[/tex]
[tex]\Delta s = \frac{(200000\,kg)\cdot \left[\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (367718.75\,N)}[/tex]
[tex]\Delta s = 1828.571\,m[/tex]
The empty airplane would need a runway of 1828.571 meters.
A cart falls from a track with an acceleration of 10 m/s2 (which is always the acceleration due to gravity). If it falls for 9 seconds before hitting the ground, what is it’s velocity at impact? (show work plz)
Answer:
90m/s
Explanation:
Given parameters:
Acceleration = 10m/s²
Time of fall = 9s
Unknown:
Final velocity = ?
Solution:
We can assume that the cart falls from rest.
Initial velocity = 0m/s
Using
v = u + gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 0 + 10 x 9 = 90m/s
Answer:
90m/s
Explanation:
Who was the most famous member of the Underground Railroad?
Answer:
Harriet Tubman
Explanation:
Answer:
Harriet Tubman
Explanation:
She was an abolitionist and fought for women's rights.
Harriet was also the first woman to lead a combat assault.
A dog playing fetch starts at rest and accelerates at 4.5m/s2 north. It takes the dog 7 seconds to catch the ball. What was the speed of the dog when he caught the ball?
Answer:
31.5m/s
Explanation:
Given the following
acceleration a = 4.5m/s²
Time t= 7secs
Required
Final speed v = ?
Using the equation of motion
v = u+at
v = 0+4.5(7)
v = 31.5m/s
Hence the speed of the dog is 31.5m/s
As the hot gas from a space shuttle is released downward, what does this cause to happen?
A. The shuttle will explode.
B. Negligible force on the shuttle.
C. Downward force on the shuttle.
D. Upward force on the shuttle
Answer:
D. Upward force on the shuttle
Explanation:
The hot gas from space shuttles released downward causes an upward force on the shuttle and propels it up the more.
This hot gas is produced from super cooled oxygen and hydrogen tanks within the shuttle. The upward force on the shuttle allows the craft to escape the gravitational pull of the earth on the shuttle Special level of rapid acceleration must be attained for the shuttle to escape the earth pull.I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52 m/s at a height of 40 m when the fish wiggles free and fall back toward the ocean. How fast is the fish moving when it hits the water?
Answer:
28.1 m/s
Explanation:
[tex]u_x[/tex] = Initial velocity of the fish = 1.52 m/s
y = Height of the bird = 40 m
[tex]a_y[/tex] = Acceleration in y axis = [tex]9.81\ \text{m/s}^2[/tex]
[tex]u_y[/tex] = Initial velocity in y axis = 0
[tex]y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}[/tex]
[tex]v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}[/tex]
The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction [tex]u_x=v_x=1.52\ \text{m/s}[/tex]
Resultant velocity is given by
[tex]v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}[/tex]
The fish is moving at a velocity of 28.1 m/s when it hits the water.
What is the gravitational force of attraction between a 55 kg boy and a 40 kg girl if they are 0.10 meters apart?
Answer:
[tex]1.5\cdot 10^{-5}\:\mathrm{N}[/tex]
Explanation:
Newton's Law of Gravitation is given as:
[tex]F=G\frac{m_1m_2}{r^2}[/tex], where [tex]G[/tex] is gravitational constant [tex]6.67\cdot 10^{-11}[/tex] and [tex]r[/tex] is the distance between their centers of mass.
Therefore, the gravitational force between them is:
[tex]F=6.67\cdot 10^{-11}\frac{55\cdot40}{0.1^2}= \fbox{$1.5\cdot 10^{-5}\:\mathrm{N}$}[/tex] (two significant figures).
Rosa wants to determine how long it will take her to drive from her house to her grandmother’s house 20km away. Her average speed is 10km/hr. What formula do you use?
A. S=D/T
B. D=SxT
C. T=D/S
D. T=S/D
Answer:
C, T=D/S
Explanation:
A jet aircraft is traveling at 262 m/s in horizontal flight. The engine takes in air at a rate of 85.9 kg/s and burns fuel at a rate of 3.92 kg/s. The exhaust gases are ejected at 921 m/s relative to the aircraft. Find the thrust of the jet engine. Answer in units of N Find the delivered power. Answer in units of W.
Answer:
[tex]F_T=60132.52N[/tex]
[tex]P=15814852.76W[/tex]
Explanation:
From the question we are told that
Velocity of aircraft [tex]V=263m/s[/tex]
Engine air intake rate [tex]\triangle M_a=85.9kg/s[/tex]
Fuel burn rate [tex]\triangle M_f =3.92kg/s[/tex]
Velocity of exhaust gas [tex]V_e =921m/s[/tex]
Generally the Mass change rate of Rocket is mathematically given by
[tex]\triangle M = \triangle M_a+\triangle M_f[/tex]
[tex]\triangle M= 85.9+3.92[/tex]
[tex]\triangle M=89.82kg/s[/tex]
Generally the Trust of the rocket is given mathematically by
[tex]F_T=(\triangle M *V_e)-(dM_a/dt)*(V)[/tex]
[tex]F_T=(89.82 *921)-(85.9)*(263)[/tex]
[tex]F_T=60132.52N[/tex]
Generally the Rocket's delivered power is mathematically given by
Delivered power P
[tex]P=V*F_T[/tex]
[tex]P=263*60132.52N[/tex]
[tex]P=15814852.76W.[/tex]
Free Online Typing...
Kami Schoolo... ►
DECISION MAKING SCENARIOS.docx
+
100%
DECISION MAKING SCENARIOS
DIRECTIONS: Read each scenario and then follow the steps to the DECIDE process to see what
you would do if you were placed in each situation.
Scenario #1: You are a freshman and an only child whose parents have demanding careers
and little time to spend at home. You are left home alone a lot and have friends over for parties
all the time. The parties can sometimes get out of hand, but so far, you haven't been caught.
Recently, your friends have challenged you to take them for a ride in your parent's car but you
don't have your license yet. However, you'd like to do it.
DEFINE THE PROBLEM:
EXPLORE THE ALTERNATIVES:
1.
Answer:
and what us the question
5
A cyclist travels 125 km in 5 hours. How fast is the cyclist moving?
Answer:
25 km/h
Explanation:
speed=distance÷time
125÷5=speed
125÷5=25 (then add units)
320 joules of work were done by a force of 80 newtons. Over what
distance was the force applied?
44m
80m
4m
40m
Answer:
[tex]4\:\mathrm{m}[/tex]
Explanation:
The formula for work is given as [tex]W=F\Delta x[/tex] where [tex]F[/tex] is force applied and [tex]\Delta x[/tex] is displacement.
Rearranging this equation, we have:
[tex]\Delta x=\frac{W}{F}[/tex].
Plugging in given values, we get:
[tex]\Delta x=\frac{W}{F}=\frac{320}{80}=\fbox{$4\:\mathrm{m}$}[/tex].
Answer:
The answer is 4m
Explanation:
hope this helps!
Polar dissolves
A. nonpolar
B. polar
C. all molecules
D. none of the above
Polar substances are likely to dissolve in polar solvents.
Your answer is B.
someone please help with this
Answer:
The new force is 2/3 of the original force
Explanation:
Coulomb's Law
The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]
Where:
[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]
q1, q2 = the objects' charge
d= The distance between the objects
Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:
[tex]\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}[/tex]
Factoring out 2/3:
[tex]\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}[/tex]
Substituting the original force:
[tex]F'=\frac{2}{3}F[/tex]
The new force is 2/3 of the original force
PLEASE ANSWER ILL GIVE YOU BRAIN!!!!
Answer:
I think the first two one is 70 the second on is 14
I hope this helps if I’m wrong I’m sorry
Explanation:
substances found in the food that the body needs
Answer:
There are six major nutrients: Carbohydrates (CHO), Lipids (fats), Proteins, Vitamins, Minerals, Water.
Explanation:
A spaceship is traveling at 24,000 m/sec. At T=5 sec, the rocket trusts are turned on. At T=55 sec, the spaceship reaches a speed of 29,500 m/sec. Whats the spaceships acceleration?
Answer:
480m/s²
Explanation:
Acceleration is the change in velocity of a body with respect to time;
Acceleration = change in velocity/change in time
change in velocity = 29,500 - 24,000
change in velocity= 5,500
Change in time = 55 - 5
change in time = 50secs
Substitute into the formula;
spaceships acceleration = 24000/50
spaceships acceleration = 480 m/s²
Hence the spaceships acceleration is 480m/s²
a) Las siglas M. RU significan
Answer:
Ver la explicación a continuación.
Explanation:
En física estas siglas significan movimiento rectilíneo uniforme, es decir es el tipo de movimiento donde la velocidad es constante. La velocidad no cambia con el tiempo.
Este tipo de movimiento se puede describir con la siguiente ecuación.
[tex]x=x_{0}+v*t[/tex]
Donde:
x = posición final [m]
xo = posición inicial [m]
v = velocidad [m/s]
t = tiempo [s]
A 1.0-kilogram rubber ball traveling east at 4.0 meters per second hits a wall and bounces back toward the west at 2.0 meters per second. Compared to the kinetic energy of the ball before it hits the wall, the kinetic energy of the ball after it bounces off the wall is
Answer:
8 J and 2 J
Explanation:
Given that,
Mass of the rubber ball, m = 1 kg
Initial speed of the rubber ball, u = 4 m/s (in east)
Final speed of the rubber ball, v = -2 m/s (in west)
We need to find the kinetic energy of the ball before it hits the wall, the kinetic energy of the ball after it bounces off the wall.
Initial kinetic energy,
[tex]K_i=\dfrac{1}{2}mv^2\\\\K_i=\dfrac{1}{2}\times 1\times (4)^2\\\\K_i=8\ J[/tex]
Final kinetic energy,
[tex]K_f=\dfrac{1}{2}mv^2\\\\K_f=\dfrac{1}{2}\times 1\times (2)^2\\\\K_f=2\ J[/tex]
So, the initial kinetic energy is 8 J and the final kinetic energy is 2 J.
The kinetic energy of the ball after it bounces off the wall is 2.0 Joules.
The kinetic energy of an object is the energy that is in motion or performing work. It can be expressed by using the formula:
[tex]\mathbf{K.E = \dfrac{1}{2}mv^2}[/tex]
The mass of the object(rubber ball) = 1.0 kgThe initial speed of the rubber ball before the collision = 4.0 m/sThe final speed of the rubber ball after the collision = - 2.0 m/sThe Kinetic energy of the ball after the collision and when it bounces off the wall is computed as:
[tex]\mathbf{K.E = \dfrac{1}{2} \times 1 \times 2.0^2}[/tex]
K.E = 2.0 Joules
Learn more about kinetic energy here:
https://brainly.com/question/8101588
Gamma radiation is composed of neutrons and protons.
A. True
B. False
Answer:
false
Explanation:
Answer:
The answer is B false
Explanation:
Gamma radiation is not composed of both neutrons and protons.
Derive Isothermal process through ideal gas.( derive it numerically)
Explanation:
Hope it helps..........
1) Which of the following is not a type of energy?
A: Thermal
B: Potential
C: Kinetic
D: Frictional
HELP ME ASAP PLZZ
Which of the following is not a measurement taken by a radiosonde?
a. atmospheric composition
b. atmospheric pressure
c. wind speed
d. wind direction
Answer:
A atmospheric composition
A car starts from rest and accelerates at a constant rate of 3.5 m/s2. What is the car’s velocity after the car has traveled 800 m?
Answer:
Attached is the answer
Explanation:
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Using equation of motion, initial velocity u = 0 and acceleration a = 3.5 unit and distance travelled is 800 m.
v² = u² + 2as
v² = 0 + 2*3.5*800
v² = 5600
v = 74.83 m/sec
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
To learn more about velocity refer to the link
brainly.com/question/18084516
#SPJ2
Explain how we perceive objects as they are
pls help, I will mark u as the brainliest
The lens present in our eyes forms a real and inverted image on the retina. The optic nerves carry this image from the retina to the brain. The brain then processes this info to generate clear and virtual images. That's how we perceive objects as they are.
When the image is formed on our "Retina", the light sensitive cells of our Retina gets activated and they generate electric signals. These signals are send to brain by the optic nerves. The brain interprets the electric signals in such a way that we see an image in erect and of the same size as the object... MÅRK ÅS THE ẞRÅÏÑLÏËST.......
Which statement about plant and animal cells is true?
A. Both have a cell wall to give them support.
B. Both have a large vacuole to store water.
C. Both use mitochondria to release energy.
D. Both use chloroplasts to store energy.
Answer:
C. Both use mitochondria to release energy
Explanation:
Plant cells have a cell wall, a large vacuole and chloroplasts but animal cells do not.