Answer:
It takes 1.14 s to move the box 4.20 m.
Explanation:
Using Newton's second law we have:
[tex]Fcos(35)-F_{f}=ma[/tex]
[tex]Fcos(35)-\mu mg=ma[/tex]
F is the force exerted and m the mass of the books
[tex]Fcos(35)-\mu mg=ma[/tex]
[tex]477cos(35)-(0.58*315)=\frac{315}{9.81}a[/tex]
So, the books accelerate at:
[tex]a=6.48\: m/s^{2}[/tex]
We know that the initial velocity is zero, so using the kinematic position equation, we have:
[tex]x=\frac{1}{2}at^{2}[/tex]
So, we just need to solve the equation for t.
[tex]4.2=\frac{1}{2}6.48t^{2}[/tex]
[tex]t=\sqrt{\frac{2*4.2}{6.48}}[/tex]
Taking the positive value of t:
[tex]t=1.14\: s[/tex]
Therefore, it takes 1.14 s to move the box 4.20 m.
I hope it helps you!
A gas has an initial volume of 2.5 L at a temperature of 275 K and a pressure of 2.1 atm. The pressure of the gas increases to 2.7 atm, and the temperature of the gas increases to 298 K. What is the final volume of the gas, rounded to the nearest tenth? 2.1 L 2.5 L 2.7 L 3.0 L
Answer:
2.10L
Explanation:
Given data
V1= 2.5L
T1= 275K
P1= 2.1atm
P2= 2.7 atm
T2= 298K
V2= ???
Let us apply the gas equation
P1V1/T1= P2V2/T2
substitute into the expression we have
2.1*2.5/275= 2.7*V2/298
5.25/275= 2.7*V2/298
Cross multiply
275*2.7V2= 298*5.25
742.5V2= 1564.5
V2= 1564.5/742.5
V2= 2.10L
Hence the final volume is 2.10L
3. The pressure at the bottom of the ocean is great enough to crush submarines with steel walls that are 10 centimeters thick. Suppose a submarine is at a depth of 1,000 meters. The weight of water above each square meter of the submarine is 9,800,000 newtons.
Answer:
just awnsered this one your awnser is the the second option
Answer:
answer one
Explanation:
The angle between the incident ray and the reflected ray from a mirror is 720.
Find the angle of incidence.
Answer:
when a ray of light is incident normally on a plane mirror the angle between incident and reflected ray is 0 degree or 180 degree
Explanation:
Anyone knows this ???
Answer:
JUST A MINUTE KAPENG MAINIT
what is the wavelength of the wave
Explanation:
it is equal to the speed (v) of a wave train in a medium divided by its frequency (f): λ = v/f. Waves of different wavelengths.
Answer:
It is measured in the direction of the wave. Description: Wavelength is the distance from one crest to another, or from one trough to another, of a wave (which may be an electromagnetic wave, a sound wave, or any other wave).
What is the main reason people and bears slip and fall on ice, be careful when outside in the snow/ice.
Answer:
Both ice and snow have a lower coefficient of friction in comparison with grass, wood or pavement.
Explanation:
The main reason why people and bears, slip and fall on ice/snow is that both ice and snow have a lower coefficient of friction in comparison with grass, wood or pavement. We present below a comparative chart of coefficients of friction associated with different materials:
Material Coefficient of Friction - Static
Ice/Snow 0.05 - 0.3
Wood 0.2 - 0.6
Asphalt 0.5 - 0.7
Grass 0.3 - 0.5
Consider the differences between a horseshoe magnet and a bar magnet. Is the attraction or repulsion going to be stronger or weaker between two horseshoe magnets or two bar magnets, as shown here? How would that influence the density of magnetic field lines?
Answer and Explanation:
A horseshoe-shaped magnet, that is, a "U" shape, has stronger attraction and repulsion capacities than that presented by a bar-shaped magnet. This is because the lines of the magnetic field on the "U" magnet are more dense and therefore promote a stronger magnetic field. This strong magnetic field exists because in a "U" shaped magnet, the magnetic poles are on the same plane, allowing a better fluctuation of the lines of the magnetic field.
3. Gather data: Use the values above to fill in the first row of the table. Then run your own experiments to fill
in the last two rows.
f
d.
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h.
h,
ร”
S
d
de
2.0
h;
h.
2.0
s.
2.0
S
f
2.0
15
10
30
Answer:
urjshsus uevus e survey dydvd dydvdyd d dgdv gdyr yrgdvv yth yrhvthr
Explanation:
ydgdydvd yd dv ydvr dyve dysdvdyr gdvr
Look at the diagram provided. What would be the mechanical energy at Point #4?
Answer:
18000 J
Explanation:
From the question given above, the following data were obtained:
At point 4:
Mass of cart = 600 Kg
Velocity of cart (v) = 7.745 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 600 × 7.745²
KE = 300 × 7.745²
KE ≈ 18000 J
Therefore, the mechanical energy of the cart at point 4 is 18000 J
According to Newton's second law equation, what is the relationship between net force applied and the acceleration of the object
Acceleration is inversely proportional to the net force
if acceleration goes up forces goes down
if acceleration goes down mass goes down
Acceleration is directly proportional to the net force
Answer:
Acceleration is directly proportional to the net force
Explanation:
The net force acting on an object is given by :
F = ma
Where
m is mass
and
a is acceleration
It can be seen that the relation between the net force and the acceleration is direct i.e. as the acceleration increases, the net force will increase. Hence, the correct option is (d).
HELP ME PLS
when your sence becomes sharper what is that
a.respitory system
b.circulatery system
c.nervouse system
d.muskeler and skeletal system
Answer:
it will option C ,hope it helps
Answer:
nervous system is your answer
What are the three physical things that can reduce the chances of injury while catching a fastball.
Answer:
Breaking bones, injuring tendons, bruising
Explanation:
b) Include this table on your slide:
Mass of Object 1 Mass of Object 2 (kg)
(kg)
Gravitational Force
(N)
1 x 1020
1 x 1020
1 x 1040 G
3 x 1020
1 x 1020
3 x 100 G
2 x 1020
2 x 1020
4 x 10"G
20
3 x 1020
4 x 10
12 x 10 G
c) Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force
between them. Be sure to:
Describe the scenario.
Explain the table headings to introduce the data in the table.
Use the data to show a trend.
Summarize the information from the table in a sentence, showing the relationship between
the masses of objects and the gravitational force between the objects.
d) Place text in the notes section below the slide explaining the information presented on it. This text
will act as the script for your presentation.
e) Remember to save your work.
Answer:
hryrbrhrururjrn djbrr he dvhd the ry rhr
urur
Explanation:
jrurhr dye dhrb the yd rhd due sh dgd eye rh
Answer:
I dont know i was looking for the same answer for my project
Explanation:
calculate the change in gravitational potential energy of a stone of mass 0.55 kg as it falls through a distance of 2.7 m. ignore air resistance (mention formula)
Answer:
14, 85 J
Explanation:
The formula of potential Energy (P.E.) is
P.E. = m * g * h, where m is the mass in kilograms, g is the acceleration due to gravity (about 10 m / [tex]s^{2}[/tex] at the surface of the earth) and h is the height in meters.
Here P.E. is 0,55 kg * 10 m/s * 2,7 m = 14, 85 J
what is the si unit of loudness of sound
Answer:
We know that loudness is directly proportional to amplitude and SI unit of amplitude is Decibel So unit of loudness is decibel
Answer:
volume
Explanation:
the si unit of sound is volume
why is sun called a source of light??
Answer:
because he give heat and energy
How many electrons would be needed to give a cobalt atom (that has 27 protons and 28 neutrons) a net charge of zero?
Answer:
The answer would be 123
On planet Q, g = 2.24 m/s2. If the mass of planet Q is 8.96
1021 kg, what is the radius of planet Q?(G = 6.67 * 10-11 N
(m/kg))
a
8.95 x 1032 m
b 5.17 x 10 m
C 1.26 108 m
d 9.23 x 1024 m
e
4.72 x 106 m
Answer:
5.17 x 10^5
Explanation
The correct answer is (b) [tex]5.17*10^{5}m[/tex]
Let us consider an object of mass m on the planet Q.
On planet Q, let the acceleration due to gravity be g = 2.24 m/[tex]s^{2}[/tex]
Mass of the planet is M = [tex]8.96*10^{21} kg[/tex]
Let its radius be R
and the universal gravitational constant G = [tex]6.67*10^{-11} m/kg[/tex]
Gravitational Force acting on the object:
[tex]mg=\frac{GMm}{R^{2} }[/tex]
[tex]R=\sqrt{\frac{GM}{g} } \\R=\sqrt{\frac{6.67*10^{-11}*8.96*10^{21} }{2.24} }\\R=5.17*10^{5} m[/tex] is the radius of the planet Q.
Learn more about gravitational force:
https://brainly.com/question/17531377
pls help i’ll give brainliest if you give a correct answer!!
Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of 0.32 m?
Answer:
Average speed=1.5 m/s
Frequency of pendulum=93.75Hz
Explanation:
We are given
Frequency, [tex]f=0.100Hz[/tex]
Average wavelength =[tex]\lambda=15m[/tex]
Speed of pendulum, [tex]v=30m/s[/tex]
Wavelength, [tex]\lambda'=0.32m[/tex]
We have to find the average speed and frequency of pendulum.
We know that
Speed,[tex]v=\lambda f[/tex]
Using the formula
Average speed,[tex]v=15\times 0.1=1.5m/s[/tex]
Hence, the average speed =1.5m/s
Frequency, [tex]f=\frac{v}{\lambda'}[/tex]
Using the formula
[tex]f=\frac{30}{0.32}[/tex]
[tex]f=93.75Hz[/tex]
Hence, the frequency of a pendulum=93.75Hz
Who is farther from home at 4 minutes?
Answer:
lil's sister
hope this helps pls mark brainliest
What is the displacement of a car in 50 s if it is travelling with a velocity of 25 m/s?
Answer:
v =25 m/s
time= 50 s
Velocity =Displacement/Time
Displacement = Velocity × Time
S = 25×50
s=1250m
Explanation:
v =25 m/s
time= 50 s
Velocity =Displacement/Time
Displacement = Velocity × Time
what is mass in physics
Answer:
Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.
Explanation:
pls mark as brainliest
Answer:
Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.
Explanation:
Hope that helps! :)
Question 5: Which object traveled at a faster speed? (Make sure to show your
work!!)
Object A: 65 miles in 13 minutes
Object B: 125 miles in 25 minutes
Answer: objects A and B have the same speed.
Explanation:
Speed = distance divided by time.
Object A: 65 miles in 13 minutes
Speed (A) = 65 miles divided by 13 minutes
Speed (A) = 5 miles per minute
Object B: 125 miles in 25 minutes
Speed (B) = 125 miles divided by 25 minutes
Speed (B) = 5 miles per minute
Thus, objects A and B have the same speed.
What will happen in the next moment for the girl on the swing?
1.Fill in wether quantities will increase, decrease, or stay the same.
2. Support your answer in the table below
Answer:
Increase, same, same
Explanation:
A hockey puck, with an initial velocity of 65 km/h [W], ricochets off the boards. After 0.76 s in contact with the boards, its final velocity is 47 km/h [E]. Determine the acceleration of the puck.
Answer:
a = 40.937 m / s²
Explanation:
For this exercise let's use the relationship between momentum and momentum variation
I = Δp
F t = m v_f - mv₀
F = m (v_f -v₀) / t
let's reduce the magnitudes to the SI system
v_f = 47 km / h (1000m / 1 km) (1h / 3600 s) = 13.056 m / s
v₀ = - 65 km / h = -18.056 m / s
the negative sign is bearing the speed is west
let's calculate
F = m (13.056 + 18.056) / 0.76
F = m 40.937
now we can use Newton's second law
F = m a
m 40.937 = m a
a = 40.937 m / s²
Sam, whose mass is 60 Kg, is riding on a 5.0 kg sled initially traveling at 8.0 m/s. He
brings the sled to a stop in 4.0 seconds. What amount of force is applied to the sled in
bringing it to a stop?
===============================================================
Explanation:
We'll need the acceleration first.
The initial speed (let's call that Vi) is 8.0 m/sThe final speed (Vf) is 0 m/s since Sam comes to a complete stop at the end.This happens over a duration of t = 4.0 secondsThe acceleration is equal to the change in speed over change in time
a = acceleration
a = (change in speed)/(change in time)
a = (Vf - Vi)/(4 seconds)
a = (0 - 8.0)/4
a = -8/4
a = -2
The acceleration is -2 m/s^2, meaning that Sam slows down by 2 m/s every second. Negative accelerations are often associated with slowing down. The term "deceleration" can be used here.
Here's a further break down of Sam's speeds at the four points of interest
At 0 seconds, he's going 8 m/sAt the 1 second mark, he's slowing down to 8-2 = 6 m/sAt the 2 second mark, he's now at 6-2 = 4 m/sAt the 3 second mark, he's at 4-2 = 2 m/sFinally, at the 4 second mark, he's at 2-2 = 0 m/sNext, we'll apply Newton's Second Law of motion
F = m*a
where,
F = force appliedm = massa = accelerationWe just found the acceleration, and the mass is fairly easy as all we need to do is add Sam's mass with the sled's mass to get 60+5.0 = 65 kg
So the force applied must be:
F = m*a
F = 65*(-2)
F = -130 newtons
This force is negative to indicate it's pushing against the sled's momentum to slow Sam down.
The magnitude of this force is |F| = |-130| = 130 newtons
Which of the following correctly lists the parts of the water cycle?
Question 7 options:
Evaporation, condensation, temperature, precipitation, collection
Condensation, build-up, runoff, precipitation, collection
Runoff, precipitation, evaporation, melting, condensation
Evaporation, condensation, precipitation, runoff, collection
evaporation, condensation, precipitation, runoff, collection
A student swings a 5.0 Kg pail of water in a vertical circle of radius 1.3m. What is the minimum speed at the top of the circle if the water is not to spill from pail.
Answer:
v = 3.57 m / s
Explanation:
Let's use Newton's second law in the upper part of the circle, with the minimum speed so that the water does not rest on the circle, that is, the normal is zero
W = m a
acceleration is centripetal
a = v² / r
let's substitute
mg = m v² / r
v = [tex]\sqrt{r g }[/tex]
let's calculate
v = [tex]\sqrt{1.3 \ 9.8}[/tex]ra 1.3 9.8
v = 3.57 m / s
When the comet passes close to the sun, it has a visible tail. Typically, the comet is only visible for a matter of days while it may be invisible for years. Why does the comet spend so little time close to the sun?
Answer:
The comet is locked in the Sun's gravity. as it falls deeper in the gravity we'll, its velocity increases. As is travels closer to the Sun, it is trying to break away, but cannot. This transforms into a sideways movement that produces a tight turn. It races further out of the gravity well, and sheds velocity.