A blood bank needs 8 people to help with a blood drive. 19 people have volunteered. Find how many different groups of 8 can be formed from the 19 volunteers.

Answers

Answer 1

75,582 different groups of 8 can be formed from the 19 volunteers.

In this case, we want to calculate C(19, 8), which represents the number of ways to choose 8 volunteers from a set of 19 volunteers.

The formula for combinations is given by:

C(n, r) = n! / (r!(n-r)!)

Using this formula,

C(19, 8) = 19! / (8!(19-8)!)

C(19, 8) = 19! / (8!11!)

C( 19, 8) = 19 x 18 x 17 x 16 x 15 x 14 x 13 x 12 / 8 x7 x6 x 5x 4 x 3 x 2

C( 19, 8) = 75,582

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Related Questions

Estimate 94.44 + 65.392 by first rounding each number to the nearest whole number.

Answers

0-4 rounds down to the original whole number
5-9 rounds up to the next whole number

94.44 rounds to 94
65.392 rounds to 65

94+65=159

ANSWER: 159

A plug is removed from a trough to drain the water. The volume, in gallons, in the trough after it has been unplugged can be modeled by the expression 10x2 − 11x + 3, where x is the time in minutes. Choose the appropriate form of the expression that would reveal the time, in minutes, when the trough is empty. (1 point)
10(0)2 − 11(0) + 3
(5x − 3)(2x − 1)
10(x − 3)2 − 1
10(x − 1)2 − 3

Answers

When A plug is removed from a trough to drain the water, The appropriate form of the expression is 10(x - 1)² - 3. Option D

How to determine the appropriate form of expression

The appropriate form of the expression that would reveal the time, in minutes, when the trough is empty is: 10(x - 1)² - 3.

This expression represents the volume of the trough after the plug is removed, with x representing the time in minutes. When the volume of the trough is equal to zero, it means the trough is empty.

Therefore, setting the expression equal to zero and solving for x will give us the time when the trough is empty.

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As a salesperson at Scrapbooks and
Treasures, Alysse receives a monthly
base pay plus commission on all that she
sells. If she sells $500 worth of
merchandise in one month, she is paid
$515. If she sells $900 of merchandise in
one month, she is paid $607.
Find Alysse's total salary function, s(x), when
she sells x dollars of merchandise.
s(x)=

Answers

To find Alysse's total salary function, we need to determine the formula for her pay based on the information given. We know that she receives a monthly base pay plus commission on all that she sells. We can use the two data points given to create a system of equations and solve for the base pay and commission rate:

When Alysse sells $500 of merchandise, her pay is $515:
Base pay + Commission rate × $500 = $515
Base pay + Commission rate × 500/500 = 515/500
Base pay + Commission rate = 1.03

When Alysse sells $900 of merchandise, her pay is $607:
Base pay + Commission rate × $900 = $607
Base pay + Commission rate × 900/500 = 607/500
Base pay + 1.8 × Commission rate = 1.214

We can solve this system of equations by subtracting the first equation from the second equation, which eliminates the base pay variable:

1.8 × Commission rate - Commission rate = 1.214 - 1.03
0.8 × Commission rate = 0.184
Commission rate = 0.23

Using the first equation, we can solve for the base pay:

Base pay + 0.23 × $500 = $515
Base pay = $515 - $115
Base pay = $400

Therefore, Alysse's total salary function, s(x), when she sells x dollars of merchandise is:

s(x) = $400 + 0.23x

This means that her base pay is $400 per month and she earns a commission of 23% on all the merchandise she sells. For example, if she sells $1000 worth of merchandise in a month, her total pay would be:

s($1000) = $400 + 0.23($1000) = $630

So her total pay increases as she sells more merchandise, reflecting the commission she earns on each sale.

Answer:

s(x) = 0.23x + 400

Step-by-step explanation:

Let x = cost of merchandise sold

We start by finding the slope which is the percent of commission Alysse receives.

Let's start with doing 607 - 515. This is because we are subtracting the commissions, which also can be y2 - y1. Then, we do 900-500=400 (x2-x1). This is how to find the slope of the function. [tex]\frac{y2-y1}{x2-x1}=\frac{92}{400} =0.23[/tex], 0.23 being the slope.

s(x) = b+0.23x, now substitute values making the money received as s(x).

515 = b+0.23(500)

515=b+115

-115   -115

400 = b

607 = 400+0.23(900)

607 = 400 + 207

607 = 607

So, s(x) = 0.23x + 400

considering the unit price per ib of jelly beans, how much would a 25-pound shipment cost? i need answers ASAP

Answers

With the unit price of $5 per pound, the 25-pound shipment would cost $125.

We have,

To determine the cost of a 25-pound shipment of jelly beans, you would need the unit price per pound of jelly beans.

Without that information, it's not possible to calculate the total cost accurately.

Once you have the unit price per pound, you can simply multiply it by the weight of the shipment.

For example, if the unit price per pound is $5, then the cost of a 25-pound shipment would be:

Cost = Unit Price per Pound × Weight of Shipment

= $5/pound × 25 pounds

= $125

Thus,

With the unit price of $5 per pound, the 25-pound shipment would cost $125.

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Add the vectors: 10 - 3 + 7​

Answers

The result of adding these numbers is 14.

To add the vectors 10, -3, and 7, we simply sum their corresponding components.

In mathematics, vectors typically represent quantities that have both magnitude and direction. They are usually denoted by an arrow or boldface letters. However, in your question, the numbers provided (10, -3, and 7) are not explicitly described as vectors. They are just numerical values.

To add these numbers together, you can simply perform the arithmetic operation of addition:

10 - 3 + 7 = 14

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A relationship is represented by the equation y = x - 12 which of the following tables best represent the equation

Answers

A table that best represent the equation include the following: H. table H.

How to determine the table that best represent the equation?

In order to determine the table that best represent the equation, we would have to substitute each of the values of x (x-values) into the linear function and then evaluate as follows;

When the value of x = 1 in table F, the linear function is given by;

y = x - 12

y = 1 - 12

y = -11 (False).

When the value of x = 0 in table G, the linear function is given by;

y = x - 12

y = 0 - 12

y = -12 (True).

When the value of x = 2 in table G, the linear function is given by;

y = x - 12

y = 2 - 12

y = -10 (False).

When the value of x = 0 in table H, the linear function is given by;

y = x - 12

y = 2 - 12

y = -10 (True).

When the value of x = 4 in table H, the linear function is given by;

y = x - 12

y = 4 - 12

y = -8 (True).

When the value of x = 6 in table H, the linear function is given by;

y = x - 12

y = 6 - 12

y = -6 (True).

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Question 8 of 10
If f(x) = x² is horizontally compressed to g(x), which could be the equation of
g(x)?
O A. g(x) - (x)
O B. g(x) - (x-6)²
OC. g(x)=x² +6
O D. g(x) - (6x)²
SUBMIT

Answers

The horizontally compressed function is [tex]\(\text{g(x)} = x^2 + 6\)[/tex]. The correct option is OC. [tex]\(\text{g(x)} = x^2 + 6\)[/tex].

To horizontally compress the function [tex]f(x) = x^2[/tex], we can modify the equation by introducing a horizontal compression factor. Let's call the compressed function [tex]g(x)[/tex].

The general equation for a horizontally compressed function can be expressed as [tex]g(x) = f(ax)[/tex], where a is the compression factor.

In this case, we want to compress [tex]f(x) = x^2[/tex]. Let's choose a compression factor of [tex]\frac{1}{2}[/tex].

Therefore, the equation for [tex]g(x)[/tex] would be:

[tex]\[ g(x) = f\left(\frac{x}{2}\right) = \left(\frac{x}{2}\right)^2 \][/tex]

Simplifying this equation, we have:

[tex]\[ g(x) = \frac{x^2}{4} \][/tex]

Hence, the equation of [tex]g(x)[/tex] is:

[tex]\[ \text{g(x)} = \frac{x^2}{4} \][/tex]

So, the correct option is OC. [tex]\(\text{g(x)} = x^2 + 6\)[/tex].

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Suppose a random sample of size 48 is selected from a population

Answers

The caluclated values are:

1.241.30 1.30 How to solve for the values

N = 500:

SEM = 9 * √[(500 - 48) / (500 - 1)] / √(48)

= 1.24 (rounded to 2 decimals)

N = 5000:

SEM = 9 * √t[(5000 - 48) / (5000 - 1)] / √(48)

= 1.30 (rounded to 2 decimals)

N = 50000:

SEM = 9 * √[(50000 - 48) / (50000 - 1)] / √(48)

= 1.30 (rounded to 2 decimals)

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Can I have help finding the area

Answers

Answer: For Area A, 60

For Area B, 16

For Area C, 16

For the entire shape, 92

Step-by-step explanation:

If you look at the top of the entire shape, it says the width is 10 cm, that means 10 cm's for the entire width and not just shape A.

If you look at shape B, it says the width is 4 cm, that means 4 out of those 10 cm's are for B and not A but we dont need the width of shape B, so we subtract that 4 bc it isnt necessary since its not in shape A

if you look at the left of shape A, it says 10 cm for the height, when finding area for a rectangle, always do width x height. We have both the width and the height so now we just multiply them, 10 x  6 = 60

Answer:

A = 60cm^2

Step-by-step explanation:

Given:

Length of figure: A = 10cm

Width of figure: B = 10 - 4 = 6cm

Figure A is rectangular in nature.

So, the Area of the figure: A = 1 x b = 10 x 6 = 60cm^2

Luna has 8 pints of juice. Michael has 2% times as many
pints of juice as Luna.a) How many pints of juice does Michael have?b) How many more pints of juice does Michael have than
Luna?Give your answers as whole numbers or as fractions in their simplest form.

Answers

a) Michael has 2% times 8 pints, which is 0.02 x 8 = 0.16 pints of juice.
b) Michael has 8 - 0.16 = 7.84 less pints of juice than Luna. Alternatively, Michael has 0.16 more pints of juice than Luna.

Answer: 0.16

Step-by-step explanation:

In AOPQ, 0 = 180 cm, p = 280 cm and ZQ=84°. Find the area of AOPQ, to the
nearest square centimeter.

Answers

The area of the triangle is 25061.6 cm²

What is area of triangle?

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices. A triangle is also a polygon.

The area of a triangle is expressed as;

A = 1/2bh where b is the base a d h is the height. This formula only works for right angled triangle.

Another formula for area of triangle is 1/2 absinC

a = 180cm

b = 280cm

C = 84°

A = 1/2 × 180 × 280 × sin84

A = 50123.9/2

A = 25061.6 cm²

Therefore the area of triangle OPQ is 25061.6 cm².

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50 Points! Multiple choice algebra question. Photo attached. Thank you!

Answers

Answer:

tan pi/6 is tan 30

Step-by-step explanation:

tan 30 is a special degree in trigonometric ratios which makes it easy to solve

tan 30=1√3 .this is the same as √3/3(B)

two numbers have a sum of 10. find the minimum value that the sum of their cubes could be

Answers

Let [tex]x[/tex] be one of the numbers. Then the other one is [tex]10-x[/tex].

Therefore, the sum of their cubes is:

[tex]x^3+(10-x)^3=x^3+1000-300x+30x^2-x^3=30x^2-300x+1000[/tex]

Now we need to find the minimum value of the resulting function.

[tex](30x^2-300x+1000)'=60x-300[/tex]

[tex]60x-300=0\\60x=300\\x=5[/tex]

The derivative is negative to the left of [tex]5[/tex] and positive to the right of it, therefore, at [tex]5[/tex] there exists the minimum.

[tex]5^3+(10-5)^3=125+125=250[/tex]

Therefore, the minimum value is 250.

The data set below represents the number of books checked out at the library each day. 21, 12, 15, 17, 6, 3, 19 Choose the correct answer from each drop-down menu to complete the statements. The range is books checked out. The median is books checked out.

Answers

The median and the range for the data-set are given as follows:

Median of 15 books checked out.Range of 18 books checked out.

How to obtain the median and the range of a data-set?

The median of a data-set is the middle value of a data-set, the value of which 50% of the measures are less than and 50% of the measures are greater than. Hence, the median also represents the 50th percentile of a data-set.

The ordered data-set is given as follows:

3, 6, 12, 15, 17, 19, 21.

The middle value is of 15, hence it represents the median of the data-set.

The range of a data-set is defined as the difference between the largest and the smallest value in the data-set, hence:

21 - 3 = 18.

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Colin walks two times around at one and 1 7/8 mile trail there are park benches everywhere 1/4 mile long trail but there are no benches at the store or another trail how many park benches are there in the trail

Answers

Answer:

15

Step-by-step explanation:

2 x 1 and 7/8 = 3 and 6/8 miles

= 3.75 miles

Since there are park benches every 1/4 mile on the trail, we can find the number of benches by dividing the total length of the trail by the distance between the benches:

Number of benches = (3.75 miles) / (1/4 mile per bench)

Number of benches = 15

200 People all speak at least one language, 73% speak german 62 % speak italian, how many speaks both languages ?

Answers

Answer:

70 people speak both languages

-----------------

Use formula:

Total = German speakers + Italian speakers - Both

We are given:

Total number of people = 200 German speakers = 73% of 200 = 0.73 * 200 = 146 Italian speakers = 62% of 200 = 0.62 * 200 = 124 Both = x

Substitute given and solve for x:

200 = 146 + 124 - x 200 = 270 - x x = 270 - 200 x = 70

So, 70 people speak both German and Italian.

Need help with this problem

Answers

The length of side j, considering the trigonometric ratios, is given as follows:

j = 7.88.

What are the trigonometric ratios?

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

Sine of angle = length of opposite side to the angle divided by the length of the hypotenuse.Cosine of angle = length of adjacent side to the angle divided by the length of the hypotenuse.Tangent of angle = length of opposite side to the angle divided by the length of the adjacent side to the angle.

For the angle of 21º, we have that:

j is the opposite side.22 is the hypotenuse.

Hence the length j is obtained as follows:

sin(21º) = j/22

j = 22 x sine of 21 degrees

j = 7.88.

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Mass of the earth greater than mass of hydrogen atom

Answers

Yes, the mass of the Earth is much larger than the mass of an atom of hydrogen.

A hydrogen atom weighs around 1.67 x 10⁻²⁷ kilograms (kg) in mass. The mass of a hydrogen atom is approximately 1051 times smaller than that of the Earth, which has a mass of about 5.97 x 10²⁴ kg.

The majority of the mass of the Earth is made up of the following elements: iron, oxygen, silicon, magnesium, Sulphur, nickel, calcium, and aluminium. Despite its minor presence, hydrogen does not significantly contribute to the mass of the Earth.

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Find the value of x.

Answers

The calculated value of x in the circle is 7

How to find the value of x.

From the question, we have the following parameters that can be used in our computation:

The circle

From the circle, we have

Center = H

Also, we have

LIne GH bisects the chord FD

Using the above as a guide, we have the following:

DG = FG

So, we have

5x + 2 = 7x - 12

This gives

2x = 14

So, we have

x = 7

Hence, the value of x is 7

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i need help with this problem

Answers

The value of x is 40 degree.

We have,

Far Arc = 130 degree

Near Arc = 50 degree

According to "Angle-Arc Theorem." It states that the angle formed by the intersection of two tangents, two secants, or one tangent and one secant outside a circle is equal to half the difference of the intercepted arcs.

In other words, The angle formed outside of the circle is always equal to the the far arc minus the near arc divided by 2.

Using Angle = (Far Arc - Near Arc) /2

So, x= (130- 50)/2

x = 80/2

x= 40

                                 

Thus, the value of x is 40 degree.

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Use the data to answer questions 1-8.
8-iron, distance to hole (vards) 20 12 12 8 6 11 7 7 10 12 8 10 11 20
1) Organize the data from least to greatest.
6,7,7,8,8,10,10,11,11,12,12,12,20,20
2) Use the data to create a histogram.
Frequency
5 10 15 20 25 30
Distance to Hole (yds)
3) What is the mean (average) of the data? Round your answer to the nearest tenth.
4) Make a box plot of the data.
5 10 15 20 25 30
Distance to Hole (yds)
5) What is the median of the data?
6) What is the First Quartile(Q1)?
7) What is the Third Quartile(Q3)?
CODIO

Can somebody help with the whole thing?? All besides number 1

Answers

Sure, I can help you with the remaining questions.

3) To find the mean (average) of the data, add up all the values and divide by the total number of values. Using the data provided, the sum of all the values is 141, and there are 14 values. Therefore, the mean is 141/14 = 10.1 (rounded to the nearest tenth).

4) To create a box plot of the data, we need to determine the minimum, maximum, median, first quartile (Q1), and third quartile (Q3).

Minimum: 6
Maximum: 20
Median: The median is the middle value when the data is arranged in ascending order. In this case, we have an even number of values, so we take the average of the two middle values. The two middle values are 10 and 11, so the median is (10 + 11)/2 = 10.5.

Q1 (First Quartile): The first quartile is the median of the lower half of the data. Since we have 14 values, the lower half consists of the first 7 values when arranged in ascending order. The values are 6, 7, 7, 8, 8, 10, and 10. The median of these values is (7 + 8)/2 = 7.5.

Q3 (Third Quartile): The third quartile is the median of the upper half of the data. Again, we have 14 values, so the upper half consists of the last 7 values when arranged in ascending order. The values are 10, 11, 11, 12, 12, 12, and 20. The median of these values is (11 + 12)/2 = 11.5.

Now, we can construct the box plot:

| (6) |
|_______|________|
(7.5) (10.1) (11.5)

The line in the middle represents the median (10.1), the left boundary represents Q1 (7.5), and the right boundary represents Q3 (11.5). The whiskers extend from the box to the minimum (6) and maximum (20) values.

5) The median of the data is 10.5.

6) The First Quartile (Q1) is 7.5.

7) The Third Quartile (Q3) is 11.5.

I hope this helps! Let me know if you have any further questions.

Question 7 of 10
Which expressions are equivalent to the one below? Check all that apply.
27
A. 3*
B. 9x
□ C. 9
□ D. (27) ²
9.3
DE 9
OF. (27-9)*

Answers

Answer:B,C

hope it helps

Find the area of each figure. Round to the nearest tenth, if necessary

Answers

Answer:

Solution is in the attached photo.

Step-by-step explanation:

This question tests on the concept of shapes, this shape can be separated into 2 basic shapes, triangle and rectangle.

100 Points! Algebra question. Photo attached. Will give Brainliest! Please show as much work as possible. Thank you!

Answers

Answer:

6.6, 22/73,

Step-by-step explanation:

Alright, here we go.
A: The mean is all of the values divided by the number of values, which is equal to 1,927.5 or:
0.5 * 5 + 1 * 16 + 2 * 28 + 3 * 22 + 4 * 17 + 5 * 98 + 8 * 13 + 10 * 73 + 12 * 5 + 15 * 2 + 20 * 4 + 25 * 9.

There are 292 or 5 + 16 + 28 + 22 + 17 + 98 + 13 + 73 + 5 + 2 + 4 + 9 packages. 1,927.5 / 292 = 6.6
B: The packages that weigh less than five pounds are 5 + 16 + 28 + 22 + 17 or 88 / 292 = 22 / 73
C and D: Manager original mean result not given.

Problema 1
En una calculadora se tecleó 35 X 100, pero se
cometió un error ya que se quería multiplicar
por 50. ¿Cómo se corrige sin borrar lo que ya
está?

Answers

The way to correct the entry on the calculator without deleting what is already there is by multiplying by 2.

Why would this correct the entry ?

Consider the scenario at hand, where an inadvertent error was committed during a calculator operation. The initial intention was to multiply by 100, yet the input mistakenly resulted in a multiplication by 50.

Seeing as this is multiplication, and the number that was to be multiplied is larger than the number given, you can find the quotient of the larger number from the smaller number to be :

= 100 / 50

= 2

Then multiply the entry by 2 as this would then lead to the correct result of 3, 500.

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2. The amount of a radioactive element at time t is given by the formula A(t)= A0ekt, (1) where A(0)= A0 is the initial amount of the element and k < 0 is the constant of proportionality which satisfies the equation (instantaneous rate of change of A(t) at time t) = kA(t). Iodine–131 is a commonly used radioactive isotope used to help detect how well the thyroid is functioning. Suppose the decay of Iodine–131 follows the model given in Equation (1), and that the half–life of Iodine–131 is approximately 10 days. If 5 grams of Iodine– 131 is present initially, find a function which gives the amount of Iodine–131, A, in grams, t days later, and then after 20 days.

Answers

The function that gives the amount of Iodine-131, A, in grams, t days later is A(t) = 5(1/2)^(t/10), and the amount after 20 days is 5/4 grams.

To find the function that gives the amount of Iodine-131, A, in grams, t days later, we can use the given formula A(t) = A0e^(kt).

Given that the half-life of Iodine-131 is approximately 10 days, we know that after each 10-day period, the amount of Iodine-131 will be reduced by half. This information allows us to determine the value of k.

Let's substitute the initial values into the equation:

A(0) = A0 = 5 grams.

We know that after 10 days, the amount is reduced by half. Therefore:

A(10) = 5/2 grams.

Using these two points, we can solve for k:

5/2 = 5e^(10k).

Dividing both sides by 5, we get:

1/2 = e^(10k).

Take the natural logarithm (ln) of both sides:

ln(1/2) = 10k.

Now, solve for k:

k = ln(1/2) / 10.

Now that we have the value of k, we can use it to find the function for the amount of Iodine-131, A, in grams, t days later.

The function is:

A(t) = A0e^(kt).

Substituting the known values:

A(t) = 5e^((ln(1/2)/10)t).

Simplifying:

A(t) = 5(1/2)^(t/10).

To find the amount of Iodine-131 after 20 days, we substitute t = 20 into the equation:

A(20) = 5(1/2)^(20/10).

A(20) = 5(1/2)^2.

A(20) = 5(1/4).

A(20) = 5/4 grams.

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We sample bags of candy under the assumption that the average weight is 16oz. with a population standard deviation of 1.25oz. Let x represent the average weight of our sample of bags of candy. What is the probability the average weight of our sample is greater than 15.8oz if our sample size is 40 bags of candy?

Answers

The Probability that the average weight of our sample is greater than 15.8 oz, given a sample size of 40 bags of candy, is approximately 0.8438 or 84.38%.

The probability that the average weight of our sample is greater than 15.8 oz, we need to use the concept of the sampling distribution of the sample mean and the Central Limit Theorem.

Given:

Population mean (μ) = 16 oz.

Population standard deviation (σ) = 1.25 oz.

Sample size (n) = 40 bags of candy.

The Central Limit Theorem states that for a large enough sample size (typically considered n > 30), the sampling distribution of the sample mean will be approximately normally distributed, regardless of the shape of the population distribution.

In this case, we can assume that the sampling distribution of the sample mean is approximately normally distributed.

To calculate the probability, we need to standardize the sample mean using the z-score formula:

z = (x - μ) / (σ / sqrt(n))

where x is the given value (15.8 oz), μ is the population mean, σ is the population standard deviation, and n is the sample size.

Substituting the values:

z = (15.8 - 16) / (1.25 / sqrt(40))

z = -0.2 / (1.25 / 6.3246)

z = -0.2 / 0.1988

z ≈ -1.006

Now, we need to find the probability that the standardized sample mean is greater than -1.006. Since we want the probability of the sample mean being greater than 15.8 oz, we need to find the area under the normal curve to the right of z = -1.006.

Using a standard normal distribution table or a calculator, we can find that the corresponding probability is approximately 0.8438.

Therefore, the probability that the average weight of our sample is greater than 15.8 oz, given a sample size of 40 bags of candy, is approximately 0.8438 or 84.38%.

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In triangle DEF, EF = 4cm, DF = 7cm, Find angle D
And E is the right angle

Answers

Hello !

1. The triangle

   D

   I\
   I  \  
   I    \
   I      \    7cm
   I        \
   I          \
   I            \

 E    4cm     F  

2. Find the ratio of the angle D

The ratio = hypotenuse ; opposite

⇒ calculate sin(D)

3. Calculate the angle D

sin(D) = opposite/hypotenuse = 4/7

arcsin(4/7) ≈ 34,84.. ≈ 35°

4. Conclusion

The angle D measures 35°.

Please help questions 5-10 this is easy…. NO SCAMS I WILL BE REPORTING ALL SCAMMERS U WILL NOT GET THE POINTS

Answers

The value of the missing probability for the given probabilities and condition of independent events is equal to 0.45.

Here,

Probability of the events A and B are,

P(A) = 7/10

P(A or B) = 167/200

Apply the formula for the probability of the union of two events,

P(A or B) = P(A) + P(B) - P(A and B)

Since events A and B are independent, we know that,

P(A and B) = P(A) x P(B)

This implies,

P(A or B) = P(A) + P(B) - P(A) x P(B)

Substitute the values we have,

⇒ 167/200 = 7/10 + P(B) - (7/10) x P(B)

⇒ 167/200 = [ 7 + 10P(B) - 7P(B) ] /10

⇒167/20 = 7 + 3P(B)

⇒3P(B) = 167/20 - 7

⇒ 3P(B) = (167 - 140)/20

⇒3P(B) = 27 /20

⇒P(B) = 9/20

⇒P(B) = 0.45

Therefore, the value of the probability P(B) is equal to 0.45.

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complete question:

Events [A] and [B] are independent. Find the missing probability.

P(B) = ?

P(A) =

7/10

P(A or B)

167/200

The hexagonal prism below has a base area of 36 units and a height of 5.9 units. Find its volume.

Answers

The volume of the given hexagonal prism is 212.4 cubic units.

Given that, the hexagonal prism below has a base area of 36 square units and a height of 5.9 units.

Formula to find the volume of the object is Volume = Area of a base × Height.

Here, volume = 36×5.9

= 212.4 cubic units

Therefore, the volume of the given hexagonal prism is 212.4 cubic units.

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