A ball of mass 12 kg is released from a height of 2.5 m
find the gravitational potential energy of the ball at point A
and when it reach the ground.
then deduce the kinetic energy of the ball once it reach the ground
(use g=10 N/kg) * 5

Answers

Answer 1

Answer:

300 J

Explanation:

From conservation of energy;

Gravitational potential energy at top = Kinetic Energy at bottom

mgh = ½mv²

We are given;

Mass; m = 12 kg.

Height; h = 2.5 m

g = 10 m/s²

Thus;

mgh = 12 × 2.5 × 10 = 300 J

Since mgh = Kinetic Energy at bottom.

Thus; kinetic energy of the ball once it reach the ground = 300 J


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*
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Answers

Answer:

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Explanation:

Given;

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Therefore, the time taken for the motion is 3.37 s

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Answers

Answer:

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Answers

Answer:

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Explanation:

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Answers

Answer:

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Answers

Answer:

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Explanation:

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Answers

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Answers

Answer:

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Explanation:

Answer:

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Explanation:

Remarks

This is one of those questions that defies belief. The final vertical velocity is the same as if you just dropped the rock, which is amazing.Another amazing fact is that the horizontal speed has no acceleration. And  amazing fact number three is the the vertical initial speed is 0.And finally, the time taken to go horizontally = time to go vertically.

Solution

Time

So the time taken is d = r * t  

Remember, this formula can only be used when there is no acceleration.

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d = ?

Formula

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Solution

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The brakes create friction, which transformed the kinetic energy to heat energy that was dissipated to the surroundings

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