Answer: Our notation is as follows : the mass of the original body is M=20.0kg ; its initial velocity is
ν
0
=(200m/s)
i
^
; the mass of one fragment is m
1
=10.0kg ; its velocity is
ν
1
=(100m/s)
j
^
; the mass of the second fragment is m
2
=4.0kg ; its velocity is
ν
2
=(−500m/s)
i
^
; and , the mass of the third fragment is m
3
=6.00kg . Conservation of linear momentum requires
M
ν
0
=m
1
ν
1
m
2
ν
2
+m
3
ν
3
.
The energy released in the explosion is equal to ΔK , the change in kinetic energy .
(a) Using the above momentum -conservation equation leads to
ν
3
=
m
3
M
ν
0
−m
1
ν
1
−m
2
ν
2
=
6.00kg
(20.0kg)(200m/s)
i
^
−(10.0kg)(100m/s)
j
^
−(4.0kg)(−500m/s)
i
^
=(1.00×10
3
m/s)
i
^
−(0.167×10
3
m/s)
j
^
.
The magnitude of
ν
3
is
ν
3
=
(1000m/s)
2
+(−167m/s)
2
=1.01×10
3
m/s
It points at θ=tan
−1
(−167/1000)=−9.48
∘
(that is at 9.5
∘
measured clockwise from the +x axis) .
(b) The energy released is ΔK :
ΔK=K
f
−K
i
=(
2
1
m
1
ν
1
2
+
2
1
m
2
ν
2
2
+
2
1
m
3
ν
3
2
)−
2
1
Mν
0
2
=3.23×10
6
J
Explanation:
7. A taxi is travelling at 15 m/s. Its driver accelerates with acceleration 3 m/s2 for 4 s. What is its new velocity
Hi there!
To solve, we can use the following equation:
vf = vi + at
vi = initial velocity (m/s)
a = acceleration (m/s²)
t = time (s)
vf = final velocity (m/s)
Plug in the given values:
vf = 15 + 3(4)
vf = 15 + 12 = 27 m/s
Answer:
[tex]\boxed {\boxed {\sf 27 \ m/s}}[/tex]
Explanation:
We are asked to find the new or final velocity of a taxi.
We will use the following kinematic equation:
[tex]v_f=v_i+at[/tex]
The car was initially traveling at 15 meters per second. It accelerated at 3 meters per second squared for 4 seconds.
[tex]v_i=[/tex]15 m/s[tex]a=[/tex]3 m/s ²t= 4 sSubstitute the values into the formula.
[tex]v_f= 15 \ m/s + (3 \ m/s^2* 4 \ s)[/tex]
Multiply the numbers in parentheses.
3 m/s/s * 4 s = 3 m/s *4 = 12 m/s[tex]v_f= 15 \ m/s +12 \ m/s[/tex]
Add.
[tex]v_f=27 \ m/s[/tex]
The new velocity of the taxi is 27 meters per second.
what is the model size to actual size
Answer:
You have to divide your real measurement to the model. For example, if your real measurement is 5m and your model is 20cm, divide 5/20 =1/4 and that means the ratio would be 1:4.
Explanation:
the small lightweight particles outside the nucleus of an atom are called___.
The neutron has no charge, and a mass of slightly over 1 amu. Some scientists propose the neutron is made up of a proton and electron-like particle. The electron is a very small particle located outside the nucleus.
Electron: -1
Neutron: 0
Proton: +1
ASAP
A truck is speeding up (with a constant acceleration) from rest to 45 m/s and it takes it 15 seconds to do so. How far will the car travel?
Answer:
675 KM
Explanation:
hAVE A NICE DAY
A rock climber’s shoe loosens a rock, and her climbing buddy at the bottom of the cliff notices that the rock takes 3.20 s to fall to the ground. How high up the cliff is the rock climber?
Answer:
50.176 [m].
Explanation:
1) the required height can be calculated using the formula:
h=V₀*t+1/2* g*t₂, where V₀ - initial velocity of the rock, t - elapsed time, g - 9.8 m/s²;
2) if V₀=0, t=3.2, g=9.8, then
h=0.5*9.8*3.2²=1024*49*10⁻³=50.176 [m].≈50[m].
1. If the mass of an object is measured in kg and the velocity is measured in m/s, what is the unit for momentum?
The unit for momentum is equal to Kgm/s.
Given the following data:
Unit of mass = Kilogram (kg).Unit of velocity = meter per seconds (m/s).To determine the unit for momentum:
What is momentum?In Science, momentum can be defined as a multiplication of the mass of an object and its velocity.
Mathematically, momentum is giving by this formula;
[tex]Momentum = mass \times velocity[/tex]
Substituting the given parameters into the formula, we have;
[tex]Momentum = kg \times m/s\\\\[/tex]
Momentum = Kgm/s.
Read more on momentum here: brainly.com/question/15517471
if an astronaut has a mass of 80kg on earth, what is their mass on the moon?
Answer:
130 N basically
Explanation:
Which choice can be classified as a pure substance?
A. homogeneous mixture
B. compound
C. heterogeneous mixture
D. solution
Tại sao khi bị sì hơi quả bóng bay sẹp lại?
Answer:
what is this language??
If the momentum of the NASA space shuttle as it leaves the atmosphere is 3.75 x 10^8 kg ·m/s and its mass is 75000 kg, what is its speed?
Hi there!
We know that:
Momentum (p) = mass (kg) × velocity (m/s)
Or:
P = mv
We can rearrange the equation to solve for speed:
P/m = v
Plug in the given values:
(3.75 × 10⁸)/75000 = 5000 m/s
How is a controlled variable different from a responding variable? O A. A controlled variable changes due to changes in the responding variable during the experiment. B. A controlled variable stays the same throughout an experiment, but a responding variable changes, C. A controlled variable changes throughout an experiment, but a responding variable stays the same. O D. A controlled variable stays the same due to changes in the responding variable during the experient.
Answer:The controlled variable is the one that you keep constant. The responding variable or variables is what happens as a result of the experiment
Explanation:Mark me brainly please
Please Help
A car travels on a straight road with velocity components of 20 m/s west and 70 m/s south. What is the total distance the car travels in 50 s?
The metal hammer has a mass of 1500 kg and it hits the baseplate
with a speed of 8.0 m/s.
0 Calculate the kinetic energy of the hammer as it hits the baseplate.
Answer:
2300.68
Explanation:
The metal hammer has a mass of 1500 kg and it hits the baseplate
with a speed of 8.0 m/s.
0 Calculate the kinetic energy of the hammer as it hits the baseplate. there for it will create the kinetic energy of 2300.68 as it hits the baseplate.
Menciona tres diferencias entre un planeta y un satélite natural.
Answer:
1. Un planeta gira alrededor del Sol mientras que un satélite gira alrededor de un planeta.
2. Tamaño
3. Aspectos Físicos
4. Creación
please help me please help
Answer:
Answer → Distance is 5 × 10⁴ km
Explanation:
Gravitational formular
[tex]{ \tt{F = \frac{GMm}{ {r}^{2} } }} \\ [/tex]
F is the gravitational forceG is the universal gravitational constantr is the separation distanceM & m are the massesFor the first case;
[tex]{ \tt{F _{1} = \frac{GMm}{2.5 \times {10}^{4} } }} \\ [/tex]
For the second case;
[tex]{ \tt{F _{2} = \frac{GMm}{r _{2}} }} \\ [/tex]
but F2 = ½F1
Therefore, F1 = 2F2
Hence:
[tex]{ \tt{ \frac{GMm}{2.5 \times {10}^{4} } =2 \times \frac{GMm}{r _{2} } }} \\ \\ { \tt{ \frac{1}{2.5 \times {10}^{4} } = \frac{2}{r _{2} } }} \\ \\ { \tt{r _{2} = 2 \times 2.5 \times {10}^{4} }} \\ \\ { \underline{ \tt{ \: \: r _{2} = 5 \times {10}^{4} \: km \: \: }}}[/tex]
Answer: Distance is 5 × 10⁴ km
Explanation:
which of the following changes will result in a weaker electromagnet
Answer:
Changing the metal core for a different metal will make the electromagnet stronger or weaker.
Explanation:
Hope this helped, nya~ :3
true and false? When an object remains stationary, any forces acting on it must be balanced.
Answer:
Balanced forces acting on a stationary object cause the object to remain at rest. True: Forces can give energy to an object it acts on causing the object to change it state of motion. If forces acting on an object are balanced, they do not cause a change in motion.
Answer:
False
Explanation:
It is NOT possible for just three forces to be acting upon an object and they still balance each other. A free-falling object experiences a balance of forces.
A car of mass 1500 kg is moving with a velocity of 30 m/s. If the velocity-time graph for this car
is a horizontal line parallel to the time axis, then the velocity of the car at the end of 25 s will be
Answer:
v=30m/s
Explanation:
m = 1500kg
v = 30m/s
t = 25s
The velocity time graph is parallel to the time axis,
that means The Velocity is constant. ('constant' means remains same).
Therefore, after 25s, v=30m/s
If the pressure of a gas is kept constant and the temperature (in Kelvin) is cut in half, the volume will _________.
Answer: be cut in half
Explanation:
In the year 2081 in a shipping port on the moon, workers for Ore-Space, Inc., hoist a 500.0 kg hunk of anorthosite moon rock by a chain. (Neglect the weight of the chain.) The block is initially accelerating at 4.0 m/s.
How much force is being exerted by the chain?
Answer:
2,800 n
Explanation:
hope this helps, have a nice day/night! :D
The force of 2812.5 N is being exerted by the chain.
What is force?An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.
Given that:
Mass of the hunk of anorthosite moon rock : m = 500.0 kg.
Acceleration of the hunk: a = 4.0 m/s².
Acceleration due to gravity in moon = 1.625 m/s².
So, required force = 500.0(4.0 +1.625) n = 2812.5 N.
The force of 2812.5 N is being exerted by the chain.
Learn more about force here:
https://brainly.com/question/13191643
#SPJ2
Q2) You pick up some nails with your fingers from a pile of nails and find that they appear to stick together. Are they made out of iron or steel? Explain your answer.
Answer:
Iron is correct answer. ... Since Magnet is also made up of Iron, Nickel and Cobalt. Therefore, it attracts iron towards it.
what types of electromagnetic radiation does the sun emit?
Answer:
https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf
Explanation:
If you have a rocket that has a mass of 20kg and is accelerating at 25 m/s what force
would that rocket experience?
a . 20N
b . 40000N
c. 500N
d. 25N
A 10 kg box is motionless on the floor. If the coefficient of static friction is 0.4 and the coefficient of kinetic friction is 0.3 (between the box and the floor), find the force required to start the block in motion
Please I need help ❤️
The force required to start the block in motion is equal to 39.2 Newton.
Given the following data:
Mass of box = 10 kgCoefficient of static friction = 0.4 Coefficient of kinetic friction = 0.3To determine the force required to start the block in motion:
Note: The force that is required to start the block in motion must be greater than or equal to the force of static friction.
Mathematically, the force of static friction is given by the formula;
[tex]Fs = uFn = umg[/tex]
Where;
Fs represents the force of static friction.μ represents the coefficient of friction.[tex]F_n[/tex] represents the normal force.g is the acceleration due to gravity.m is the mass of an object.Substituting the given parameters into the formula, we have;
[tex]F_s = 0.4 \times 10 \times 9.8\\\\F_s = 4 \times 9.8\\\\F_s = 39.2\;Newton[/tex]
Read more on force of static friction here: https://brainly.com/question/25686958
In the very distant future, given our best model of the accelerating universe, what will the universe look like?
The models of the universe allow finding the result for how serious the universe in the distant future is:
In the distant future the galaxies are far apart and the interaction between them would be negligible.
The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.
Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.
Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.
In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:
In the distant future the galaxies are far apart and the interaction between them would be negligible.
Learn more about the motion of the galaxies here: brainly.com/question/18212080
The best evidence for dark matter in the milky way comes from the observation that the rotation curve
A boy standing on a bridge 150m above the canyon floor throws a stone downward with a speed of 20.0m/s.
A) with what velocity will it hit the ground?
B) How long will it take to descend?
Answer:
57.97m/s
12.1s
Explanation:
Use one of the key equations of accelerated motion and sub in the values
vf^2=vi^2+2aΔd
vf^2=(20)^2+(2*9.8)(150)
vf^2 = 3340
vf = 57.79m/s (square rooted both sides)
now use another equation
Δd = (vi+vf/2)Δt
and rearrange for Δt
Δt = (2Δd-vf)/vi
sub in values
Δt = (2*150-57.79)/20
Δt = 12.1s
mark me as brainliest if this helped!
which of these MANNER of death? (select all that apply)
1-blood loss
2-cessation of brain function
3-accidential death
4-stabbing
5-pulmonary arrest
6-homicidal death
7-natural death
8-shooting
Answer:
3, 4, 6, 7, 8 are manners of death.
The steepest street in the world is Baldwin Street in Dunedin, NZ. It is inclined at an angle of 380 , with the horizontal. A child slides down the street with a constant velocity on a sled with high friction runners. What is the coefficient of friction between the sled runners and the street?
Newton's second law allows to find the result for the friction coefficient of the street is:
The friction coeficinwete is: μ = 0.78
Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body.
∑ F = m a
Where bold indicates vectors, m is to mass and acceleration.
In the attached we see a free body diagram, it is a diagram of the forces without the details of the body, the x-axis is parallel to plane also shown with the positive in the direction of movement, going down the plane and the y-axis perpendicular to the plane.
Let's use trigonometry to break down the weight.
Sin θ = [tex]\frac{W_x}{W}[/tex]
cos θ = [tex]\frac{W_y}{W}[/tex] / W
Wₓ = W sin θ
[tex]W_y[/tex] = W cos θ
We write Newton's second law for each axis.
y-axis
N- [tex]W_y[/tex] = 0
N = mg cos θ
x-axis
Wₓ - fr = ma
Since they indicate that the body goes down at a constant speed, the acceleration is zero.
W sin θ = fr
The friction force is the macroscopic representation of the interactions between the two surfaces and the formula.
fr = μ N
we substitute.
fr = μ mg cos θ
mg sin θ = μ cos θ
μ = tan θ
Let's calculate.
μ = tan 38.0
μ = 0.78
In conclusion using Newton's second law we can find the results for the friction coefficient of the street is:
The frivtion coefficient is: μ = 0.78
Learn more about the coefficient of friction here: brainly.com/question/11808898
Rope A is tied to block 1, and rope B is attached to both block 1 and block 2 as shown in the diagram. Block 1 has a mass of 4.2 kg and block 2 has a mass of 2.6 kg. You lift both blocks straight up. Calculate the magnitude of tension in each of the ropes when the blocks
Move at constant velocity of 1.5 m/s [up]
Find the magnitude of tension in each rope when the blocks are accelerating at 1.2 m/s^2 [up].
The maximum tension the strings can withstand is 90. N. Knowing this, determine the maximum acceleration of the blocks that would not break the rope.
Hi there!
Part 1:
If the blocks are moving at a constant velocity:
∑F = 0
Begin by summing the forces acting on each block. Let the upward direction be positive.
∑F₁ = Ta - M₁g - Tb
∑F₂ = Tb - M₂g
Sum the forces:
∑F = Ta - M₁g - Tb + Tb - M₂g
∑F = Ta - M₁g - M₂g = 0
Solve for Tension A:
Ta = M₁g + M₂g (Let g = 9.8 m/s²)
Ta = 4.2(9.8) + 2.6(9.8) = 66.64 N
Now, solve for tension B using the summation of ∑F₁:
0 = Tb - M₂g
Tb = (2.6* 9.8) = 25.48 N
Part 2:
We can use the same method, but incorporate the acceleration:
∑F = Ta - M₁g - M₂g
(M₁ + M₂)a = Ta - M₁g - M₂g
(M₁ + M₂)a + M₁g + M₂g = Ta
(4.2 + 2.6)(1.2) + 4.2(9.8) + 2.6(9.8) = 74.8 N
∑F₂ = Tb - M₂g
M₂a + M₂g = Tb = 28.6 N
Part 3:
Since the top string experiences most of the tension, we can use its equation to calculate the maximum acceleration:
∑F = Ta - M₁g - M₂g
(M₁ + M₂)a = Ta - M₁g - M₂g
a = (90 - M₁g - M₂g)/(M₁ + M₂)
a = 3.435 m/s²