A 20-N falling apple encounters a 4-N of air resistance. The magnitude of the net force on the apple is?

A. 0n
B.4n
C.16n
D. 20n
E. None of the above

Answers

Answer 1

Answer:

C

Explanation:

Pls brainliest


Related Questions

A racing car on the straight accelerates from 100 km/h to 316 km/h in three seconds.
What is its acceleration?

40m/s2

30m/s2

20m/s2

72m/s2

Answers

Answer:

[tex]20m/s^2[/tex]

Explanation:

Solution is attached. I apologize if it is a little messy.

It velocity of light scalar or vector equality ​

Answers

Answer:

velocity is a vector quantity

Explanation:

velocity is a vector quantity because it has a mass and a direction

When a 25000-kgkg fighter airplane lands on the deck of the aircraft carrier, the carrier sinks 0.30 cmcm deeper into the water.

Answers

even i cant find the answer just guess

What do alcohol, drugs, and tobacco all have in common?
All have some medicinal value.

All are harmful to the body.

All are depressants.

All are stimulants.

Answers

Answer:

all are harmful to the body

What are the 7 different states of matter in Chemistry?How many states of matter are there?

Answers

Answer:

The 7 states of matter are solid, loquid, gas, fermionoc condensate, quark gluton plasm, bose einetein condensate amd ionised plasm but its usually only 3 they teach you

Answer:

7

Explanation:

solid, liquid,gas,fermionoc condensate,quark glutton plasm,bose einetein condensate amd ionised plasm.

Students were asked to create roller coasters for marbles. The only requirement is that the roller coaster include at least one hill that the marble must roll over in order for the roller coaster to be considered a success. Students are building their designs with marbles and foam tubing so there will be some air resistance and friction. What should the students keep in mind if they want to create a successful roller coaster?

Question 23 options:

1)


Without an extra push at the bottom of the first hill, there is no way the car will make it back up a hill of any height because the marble doesn't have enough mass or velocity

2)


The hill should be at least a little lower than the starting height because some of the kinetic energy at the bottom of the first hill will be converted to other types of energy due to friction so it will not have as much potential energy at the top of the next hill

3)

The hill should be taller than the starting height because the marble will pick up speed on the downward hill and the increased velocity will allow it to travel higher on the next hill

4)


The hill should be the exact same height as the starting height because 100% of the kinetic energy at the bottom of the first hill will be converted back to potential energy at the top of the next hill

Answers

Since energy is lost in the roller coaster due to friction, the hill should little lower than the starting height since some of the kinetic energy at the bottom of the first hill is lost  due to friction so it will not have as much potential energy at the top of the next hill.

A roller coaster is a good way to demonstrate the principle of conservation  of energy. Recall that energy is neither created nor destroyed but can be converted from one form to another.

In a roller coaster, all the heights are not the same because energy is lost along the line. Therefore, the students must bear in mind that  the hill should be at least a little lower than the starting height because some of the kinetic energy at the bottom of the first hill will be converted to other types of energy due to friction so it will not have as much potential energy at the top of the next hill.

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Which of the following can cause an object to accelerate?
Select one:
a. Force
b. Inertia
c. Mass
d. Kinetic Energy

Answers

I think force can accelerate

Explanation:

i think force of an object

how does the structure of compounds determines the properties of the compounds?

Answers

Answer:

The chemical structure of the molecule is responsible for each of these characteristics. The chemical structure is comprised of the bonding angle, the kind of bonds, the size of the molecule, and the interactions that occur among the molecules. Even little changes in the chemical structure of a molecule may have a significant impact on the characteristics of the substance.

Explanation:

Hope it helps:)

PLEASE HELP I DONT GET THISS

Answers

Answer:

I feel like its the second one but I'm not completely sure..

Explanation:


1. How far does a train travel in the fourth second if it starts from rest with a uniform
acceleration of 2.0 m/s2?

Answers

Answer:

Explanation:

d = ½(2.0)4² - ½(2.0)3² = 7 m

A 1.5 kg cart is attached to a spring with spring constant of 5 N/m. The cart & spring is pulled to stretch the spring by 3 meters.

What is the SPE?​

Answers

22.5 J

Explanation:

Given:

x = 3 m

[tex]k = 5\:\text{N/m}[/tex]

The spring potential energy [tex]PE_s[/tex] is

[tex]PE_s = \frac{1}{2}kx^2 = \frac{1}{2}(5\:\text{N/m})(3\:\text{m})^2[/tex]

[tex]\:\:\:\:\:\:\:=22.5\:\text{J}[/tex]

The average normal body temperature measured in the mouth is 310 K. What would Celsius thermometers read for this temperature?

54.1°C

23.8°C

36.9°C

42.7°C

Answers

Option 36,9°C

________

= 310 - 273

= 37°C

Actually,310 Kelvin is same with 37°C, and as you see, there is no 37°C

So, The Nearest Number To 37°C is 36,9°C

Answer:

36.9

Explanation:

Plato

What does Newton's third law describe?
A) the tendency of stationary objects to remain at rest.
B) How the force applied to an object is related to a change in its motion.
C) The four fundamental forces of nature.
D) The forces between two objects

Thanks!!

Answers

Answer:

What does Newton's third law describe?

D) The forces between two objects

MCQ
A body of mass 5kg is pushed for distance x with accleration a. Then workdone against static friction is

1.ma*X cosB
2.ma*X sinB
3.zero
4.ma/X​

Answers

Answer:

ma*XsinB

option 2 is correct

What is the birth rate of a population of 3000 chipmunks if 200 chipmunks are born each year?
o 0.022 births per chipmunk per year.
0.067 births per chipmunk per year.
O 0.82 births per chipmunk per year.
o 15 births per chipmunk per year.

Answers

Answer:

0.067 births per chipmunk per year

Explanation:

I took the test

2. Two equipotential lines are separated by a distance of 2.17 cm. If the potential values of the lines are 5.9 volts and 8.6 volts, what would the strength of the electric field between the lines be

Answers

What’s the answer? For this question?

What is the meaning of eddy currents in electromagnetic series?​

Answers

Answer:

currents which circulate in conductors like swirling eddies in a stream in electromagnetic series....

A cubical box with sides of length 0.368 m contains 1.980 moles of neon gas at a temperature of 298 K. What is the average rate (in atoms/s) at which neon atoms collide with one side of the container? The mass of a single neon atom is 3.35x10-26 kg.

Answers

The average rate at which the neon atoms collide with one side of the container is [tex]3.31 \times 10^{26} \ atoms/s[/tex].

The given parameters;

length of the cubical box, L = 0.368number of moles of the gas, n = 1.98temperature, T = 298 Kmass of the gas, m = 3.35 x 10⁻²⁶ kg

The average kinetic energy of the gas molecules is calculated as follows;

[tex]K = \frac{3}{2} \frac{R}{N_a} T\\\\K = \frac{3 \times 8.314\times 298}{2\times 6.022 \times 10^{23}} \\\\K = 6.17\times 10^{-21} \ J/atoms[/tex]

The average speed of the gas molecules is calculated as follows;

[tex]K = \frac{1}{2}mv_{rms}^2\\\\v_{rms} = \sqrt{\frac{2K}{m} } \\\\v_{rms} = \sqrt{\frac{2\times 6.17 \times 10^{-21}}{3.35\times 10^{-26}} } \\\\v_{rms} = 607 \ m/s[/tex]

The time of collision of the gas molecules with the walls of the container is calculated as follows;

[tex]t = \frac{2d}{v} \\\\t = \frac{2\times 0.368}{607} \\\\t = 0.0012 \ s[/tex]

The average rate at which the gases collide with a single wall out of the 3 identical walls is calculated as follows;

[tex]rate =\frac{1}{3} \times \frac{n \times N_a}{t} \\\\rate = \frac{1.98 \times 6.02 \times 10^{23} \ atoms}{3 \times 0.0012 \ s} \\\\rate = 3.31 \times 10^{26} \ atoms/s[/tex]

Thus, the average rate at which the gases collide with one side of the container is [tex]3.31 \times 10^{26} \ atoms/s[/tex].

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The angle of incidence (5 points)



must equal the angle of reflection


is always less than the angle of reflection


is always greater than the angle of reflection


may be greater than, less than, or equal to the angle of reflection

Answers

Answer:

D.) the same.

They are traveling in the same vacuum so there is no resistance and no outside influences. They will travel at the same speed as each other will little to no variance in their speed.

Explanation:

hope this helps. . . <3

good luck!    uωu

What is the frequency of a photon that has the same momentum as a neutron moving with a speed of 1000 m/sm/s

Answers

Explanation:

Since the neutron is only moving at 1000 m/s, we are going to ignore the relativistic effects on its mass and energy. The mass of a neutron in [tex]m_n = 1.67×10^{-27}\:\text{kg}[/tex] so its kinetic energy KE is

[tex]KE = \frac{1}{2}m_nv^2[/tex]

[tex]\:\:\:\:\:\:\:\:= \frac{1}{2}(1.67×10^{-27}\:\text{kg})(10^3\:\text{m/s})^2[/tex]

[tex]\:\:\:\:\:\:\:\:= 8.35×10^{-22}\:\text{J}[/tex]

A photon's energy E is defined as

[tex]E = h\nu[/tex]

where [tex]\nu[/tex] is the photon's frequency and h is the Planck's constant. Solving for the frequency, we get

[tex]\nu = \dfrac{E}{h} = \dfrac{8.35×10^{-22}\:\text{J}}{6.63×10^{-34}\:\text{J-s}}[/tex]

[tex]\:\:\:\:\: = 1.26×10^{12}\:\text{Hz}[/tex]

which is right around the infrared radiation range.

Nikolai is using a hand-operated grain mill to grind wheatberries into flour. The mill is operated by spinning a fly-wheel with radiusR= 23 cm, which has a handle attachedto the outer edge. After grinding for a few minutes at a con-stant angular speedωi, he lets go of the handle and allows themechanism to come to rest as it undergoes constant angularacceleration. This happens over the course oft= 0.50 s, andthe flywheel undergoes a quarter of a rotation during this time.What is the linear tangential accelerationaof the handle as itcomes to rest? For the limits check, investigate what happenstoaas the time required to stop the flywheel becomes small(t→0).

Answers

Answer:

Explanation:

α = Δω/t = (0 - ωi)/0.50 = -2ωi rad/s²

ωf² = ωi² + 2αθ

θ = (ωf² - ωi²) / 2α

2π/4 = (0² - ωi²) / (2(-2ωi))

2π/4 = ωi / 4

ωi = 2π rad/s

α = -2(2π) = -4π rad/s²

a = rα = 0.23(-4π) = 0.92π m/s² ≈ -2.89 m/s²

as the time to stop approaches zero, acceleration goes toward infinity.

An artificial satellite circles the Earth in a circular orbit at a location where the acceleration due to gravity is 6.44 m/s2. Determine the orbital period of the satellite.

Answers

Explanation:

The artificial satellite experiences a centripetal force [tex]F_c[/tex] as it moves around the earth and it is defined as

[tex]F_c = m\dfrac{v^2}{r} = m\left(\dfrac{2\pi r}{T}\right)^2\left(\dfrac{1}{r}\right) = \dfrac{4\pi^2mr}{T^2}[/tex]

where m is the mass of the satellite, r is its orbital radius and T is its orbital period. But we need to find the radius first.

Recall that the satellite is orbiting at a height where its acceleration due to gravity is 6.44 m/s^2. Since we know that the weight mg of the satellite is equal to the gravitational force [tex]F_G[/tex] between the earth and the satellite, we can write

[tex]mg = F_G = G\dfrac{mM}{r^2}[/tex]

[tex]\Rightarrow g = G\dfrac{M}{r^2}[/tex]

where M is the mass of the earth (=[tex]5.972×10^{24}\:\text{kg}[/tex]) and G is the universal gravitational constant (=[tex]6.674×10^{-11}\:\text{N-m}^2\text{/kg}[/tex]). Plugging in the values, we find that the radius of the satellite's orbit is

[tex]r = \sqrt{\dfrac{GM}{g}} = \sqrt{\dfrac{(6.674×10^{-11}\:\text{N-m}^2\text{/kg})(5.972×10^{24}\:\text{kg})}{6.44\:\text{m/s}^2}}[/tex]

[tex]\:\:\:\:\:= 7.87×10^6\:\text{m}[/tex]

Now that we have the value for the radius, we can now calculate the orbital period T. Recall that the centripetal force is equal to the weight of the satellite at its orbital radius. Therefore,

[tex]F_c = mg \Rightarrow \dfrac{4\pi^2mr}{T^2} = mg[/tex]

or

[tex]4\pi^2r = gT^2[/tex]

Solving for T, we get

[tex]T^2 = \dfrac{4\pi^2r}{g} \Rightarrow T = \sqrt{\dfrac{4\pi^2r}{g}}[/tex]

We can further simplify the above expression into

[tex]T = 2\pi\sqrt{\dfrac{r}{g}}[/tex]

Plugging in the values for r and g, we get

[tex]T = 2\pi\sqrt{\dfrac{(7.87×10^6\:\text{m})}{(6.44\:\text{m/s}^2)}}[/tex]

[tex]\:\:\:\:\:= 6945\:\text{s} = 1.93\:\text{hrs}[/tex]

Convert 6 picoseconds into seconds.

Answers

Answer:

6e-12

Explanation:

divide the time value by 1e+12

F (N)
4
* 0
3
A
2
FIGURE 2
t(s)
5
0
1
2
3
4
3) A force of magnitude Fx acting in the x-direction on a 2.00 kg particle varies in time as shown
in FIGURE 2. Find
a) The impulse of the force
b) The final velocity of the particle if it is initially at rest
c) The final velocity of the particle if it is initially moving along the x-axis with velocity
of -2.00 ms -1

Answers

Answer:

Mark me as brainlist please.

a coconut falls from the top of a tree and takes 3.5 seconds to reach the ground. How tall is the tree?

Answers

Hello!

To solve, we can begin by using the kinematic equation:

[tex]d = v_it + \frac{1}{2}at^2[/tex]

Where:

vi = initial velocity (m/s)

t = time (s)

a = acceleration (in this case, due to gravity. g = 9.8 m/s²)

Since the object falls from rest, the initial velocity is 0 m/s.

[tex]d = \frac{1}{2}at^2[/tex]

Plug in the given values:

[tex]d = \frac{1}{2}(9.8)(3.5^2) = \boxed{60.025 m}[/tex]

PLSSS HELP IT'S VERY IMPORTANT FOR ME WILL MAKE AS BRAINLIEST
Fill in the blank
Valence electrons are______

"The answer is not electrons in the outer shells that are not filled!!"​​

Answers

Answer:

negatively charged particle

valence electron  is a electron of an atom, located in the outermost shell (valence shell ) of the atom, that can be transferred to or shared with another atom.

Two objects are a distance of 1.7 x 103 meters apart. One object has a mass of 3 x 107 kg and the other has a mass of 6 x 108. Determine the gravitational force between the objects.

Answers

Answer:  You need to use Newton's law for the equation --->

Explanation: G  ×  M  ×  m / separation. Thats how youll get your answer !!

Make one comparison between the moral condition of the world at the time of the Flood with our day. Only One Short explanation.

Answers

The moral condition of the world today appears to be worse than it was in the antediluvian era.

The biblical account of the flood records that the world delved into apostasy in the days of Noah so much so that God regretted the fact that he created man. Some of the evils of the antediluvian world include; sodomy, drunkenness, lewdness and several forms of immorality.

We can see that these vices that led to the destruction of the world due to moral bankruptcy in the antediluvian era is still very much prevalent in our world today. The moral condition of the world today appears to be worse than it was in the antediluvian era.

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F=mass x what does this equal?

Answers

Answer:

Force = mass × acceleration.

help me for a physics project please
Mister Brainly Please Help Me

Write 10 Information's About Sound

Answers

-cant travel through space since there's no molecules to travel through

-sound travels 4.3 times faster in water than air

-sounds are waves that pass through our ears via vibrations and travel by vibrations of molecules

-different types of sound like audible, inaudible, infrasonic, ultrasonic,

-sounds waves are either longitudinal, mechanical and pressure waves

-sound travels at 767 miles per hour

Speed of sound in air is 344m/sSound travels 4.3times faster in water than air.Sound can't travel through space(There is no atoms at there)The sound of an erupting volcano is loudest in earth.A human baby can cry about 115dB.Dogs can hear sounds of frequencies 50kHz,which humans can't.Any types of flies can't hear sound.Mammals like bat flies through following sound.The cows can give more milk if you let them hear some music.There is a pyramid at ITza ,if you clap at there the echo produced is like chirping of chickens.
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