Answer:
k. e. = 1/2 mv^2
1/2 * 1000 * (5)^2
1/2 * 1000 * 25
12500 joules
k. e. = 1/2 mv^2
1/2 * 1000 * (10)^2
1/2 * 1000 * 100
50000
change in k. e. = final - initial
50000 - 12500
= 37500 joules
hope it helps you
TRUE OR FALSE: some rays of light carry radiation.
Answer:
true
Explanation:
Answer:
True
Explanation:
Mutations in sections of DNA can be caused by all of the following EXCEPT
Question 2 options:
Viruses
Chemicals
Ultraviolet Radiation
Sexual Reproduction
Answer:
sexual reproduction
Explanation:
Please help as fast you can
Answer:
d a
Explanation:
State the lows of reflection
Answer:
The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection.
Explanation:
Answer: The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection.
how much power is used to move a 25 kg mass 8 meters in 15 seconds?
Answer:
Concept: Physics
Power is related to Work which we will find below[tex]work = f \times d[/tex]Note that force is a vector quantity that has magnitude and direction We have a mass of 25 kg and we want to know the force it exerts by newton's first law: 25 × 9.81 m/s^2 = 245 N Now we have our force and d 245 × 8 meters= 1960 J Power is represented in joules The equation for Power is [tex]p = \frac{w}{t} [/tex]Hence [tex] \frac{1960}{10} [/tex]So we get that P= 196 WAn object completes 10 cycles in 50s.
a. What is the period of its rotation?
b. What is the frequency of its rotation?
Answer:
.
Explanation:
Explanation:
Given parameters:
Number of cycles = 10cycles
Time taken = 50s
Unknown:
Period of its rotation = ?
Frequency of its rotation = ?
Solution:
The period of rotation is the time taken time taken for a body to complete a number of rotation;
Period = [tex]\frac{t}{n}[/tex]
t is the time
n is the number of cycles
Period = [tex]\frac{50}{10}[/tex] = 5s
The period is 5s
Now, frequency is the inverse of period;
F = [tex]\frac{1}{period}[/tex] = [tex]\frac{1}{5}[/tex] = 0.2Hz
pls someone help me
Answer:
Can't see the pic
Explanation:
An 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him?
Answer:
1626.4 N
Explanation:
Given that a 82 kg man, at rest, drops from a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. What force does the water exert on him?
The parameters to be considered are:
Distance S = 3m
Time t = 0.55s
Since the man started from rest, initial velocity u = 0
Using second equation of motion
S = Ut + 1/2at^2
3 = 1/2 × a × 0.55^2
3 = 1/2 × a × 0.3025
a = 3/ 0.15125
a = 19.83 m/s^2
Force = mass × acceleration
Force = 82 × 19.83
Force = 1626.4 N
Therefore, the force that water exerted on him is 1626.4 N
2. Two projectiles thrown from the same point at angles 0,=60° and 02=30° with the horizontal,
attain the same height. What is the ratio of their initial velocities (Voi:Voz)?
Answer:
The answer is below
Explanation:
The maximum height (h) of a projectile with an initial velocity of u, acceleration due to gravity g and at an angle θ with the horizontal is given as:
[tex]h=\frac{u^2sin^2\theta}{2g}[/tex]
Given that the two projectile has the same height.
[tex]For\ the\ first\ projectile\ with\ an\ angle\ \60^0 \ with\ the\ horizontal\ and initial\ velocity\ u_1:\\\\h=\frac{u_1^2sin^260}{2g} =\frac{0.75u_1^2}{2g} \\\\For\ the\ second\ projectile\ with\ an\ angle\ \30 \ with\ the\ horizontal\ and initial\ velocity\ u_2:\\\\h=\frac{u_2^2sin^230}{2g} =\frac{0.25u_2^2}{2g}\\\\\frac{0.25u_2^2}{2g}=\frac{0.75u_1^2}{2g}\\\\0.25u_2^2=0.75u_1^2\\\\\frac{u_1^2}{u_2^2} =\frac{0.25}{0.75} \\\\\frac{u_1^2}{u_2^2}=\frac{1}{3} \\[/tex][tex]\\\frac{u_1}{u_2}=\sqrt\frac{1}{3}[/tex]
A man standing on top of a 30 m tall building throws a brick downwards with a velocity of 12 m/s. Determine the speed of the brick just before it hits the ground.
Answer:
27.1m/s
Explanation:
Given parameters:
Height of the building = 30m
Initial velocity = 12m/s
Unknown:
Final velocity = ?
Solution:
We apply one of the kinematics equation to solve this problem:
v² = u² + 2gh
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
h is the height
v² = 12² + (2 x 9.8 x 30)
v = 27.1m/s
PLEASE HURRY What is "a section of a chromosome that typically contains the code for a particular protein, which determines a specific trait" called?
heterozygous
genetics
species
gene
Answer:
It is a gene!!
Explanation:
It is because RNA is referred to as a gene. Genes are contained in chromosones.
Are all forms of radiation safe for humans?
Answer:
there are not all safe for humans
decreases, gravitational, increases, kinetic, potential, thermal
A car driving along a road has energy in its _______ store. If the car drive faster this store_____. If the car drives up a hill, energy is transferred to its ____ store. If the care brakes, the kinetic store _____.
What is the momentum of a 120 pound bicyclist that is traveling at 25 mph?
An object of mass 2kg raised to a height 10m possess potential energy of 200J. What is the kinetic energy and potential energy at a height 4 metre?
Explanation:
[tex]{\bold{\sf{\underline{Understanding \: the \: concept}}}}[/tex]
✠ This question says that there is an object and its mass is 2 kg ; it's raised to a height 10 m and possess potential energy of 200 J. Now this question ask us to find the kinetic energy and the potential energy at a height 4 metre.
[tex]\bold{↬{ }}[/tex][tex]{\bold{\sf{\underline{Given \: that}}}}[/tex]
✰ Mass = 2 kilograms
✰ Raised height = 10 metres
✰ Posses potential energy = 200 Joules
[tex]\bold{↬{ }}[/tex][tex]{\bold{\sf{\underline{To \: find}}}}[/tex]
✰ Kinetic energy at a height 4 metre
✰ Potential energy at a height 4 metre
[tex]{\bold{\sf{\underline{Solution}}}}[/tex]
✰ Kinetic energy at a height 4 metre = 120 J
✰ Potential energy at a height 4 metre = 80 J
[tex]{\bold{\sf{\underline{Using \: concepts}}}}[/tex]
✰ Potential energy formula.
[tex]{\bold{\sf{\underline{Using \: formula}}}}[/tex]
✰ Potential energy = mgh
[tex]{\bold{\sf{\underline{We \: also \: write \: these \: as}}}}[/tex]
✰ Potential energy as P.E
✰ Mass as m
✰ Joules as J
✰ Height as h
✰ Raised height as g
[tex]{\bold{\sf{\underline{Full \: solution}}}}[/tex]
✠ Let us find the Potential energy.↦ Potential energy = mgh
↦ Potential energy = 2 × 10 × 4
↦ Potential energy = 20 × 4
↦ Potential energy = 80 J
✠ Now according to the question let us find the kinetic energy↦ Kinetic energy = Posses potential energy - Finded potential energy
↦ Kinetic energy = 200 J - 80 J
↦ Kinetic energy = 120 Joules
An object of mass 2kg raised to a height 10m possess potential energy of 200J.
to find:-What is the kinetic energy and potential energy at a height 4 metre?
solution:-from energy conservation,
potential energy at 10m height =potential energy +kinetic energy at 4 m
potential energy at 10 m height=200
let,Kinetic energy at 4m=KE
potential energy at 4m=PE
so,
200=KE+PEpotential energy at 4m height =
mgh2×10×480Hence,
kinetic energy at 4m is =200-80=120J
What happens when two sound waves meet in destructive interference?
sorry i did not mean to answer
A boxer pushes on a 25 kg heavy bag which is attached to the ceiling until it makes an angle of 36 degrees to the vertical. How much force must the boxer exert on the bag?
Answer:
198.20 N
Explanation:
Given that,
Mass of a heavy bag, m = 25 kg
The bag is attached to the ceiling until it makes an angle of 36 degrees to the vertical.
We need to find the force must the boxer exert on the bag. The force acting on the bag is given by :
[tex]F=mg\cos\theta\\\\=25\times 9.8\times \cos(36)\\\\=198.20\ N[/tex]
So, the required force is 198.20 N.
A boy pulls his toy on a smooth horizontal surface with a rope inclined at 60 degree to the horizontal if the effective force pulling the toy along the horizontal surface is 5 Newton calculate the tension in the rope
Answer:
Tension = 2.5 N
Explanation:
Given:
Angle = 60°
Force f = 5 N
Find:
Tension
Computation:
Tension = fcosθ
Tension = (5)cos60
Tension = (5)(1/2)
Tension = 2.5 N
How are mass and volume alike?
They always stay the same
They are both measured in grams
The cease to exist when placed in a liquid
Answer:
its b
Explanation:
b
2. A tower is 15.24 m high. At a certain distance away from the tower, an observer
determines that the angle of elevation to the top of it is 41°. How far is the observer
from the base of the tower?
Explanation:
Opposite side from the 41° angle = 15.24m
We wish to find the adjacent side (horizontal length)
Therefore 15.24m / tan41° = 17.53m.
A man standing on top of a 30 m tall building throws a brick downwards with a velocity of 12 m/s. Determine the speed of the brick just before it hits the ground.
Answer:
27.1m/s
Explanation:
Given parameters:
Height of the building = 30m
Initial velocity = 12m/s
Unknown:
Final velocity = ?
Solution:
We apply one of the kinematics equation to solve this problem:
v² = u² + 2gh
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
h is the height
v² = 12² + (2 x 9.8 x 30)
v = 27.1m/s
Which of the following is NOT a benefit of dancing?
1. Improves balance and coordination.
2. Helps boost your mood.
3. Challenges your brain.
4. Isolates you from other people.
Answer:
4
Explanation:
Tor F. When we carry an object across the room without lifting it or setting it down, we
don't do any physical work on it.
Answer:
True
Explanation:
Study guide answer key
A 34.75 kg boulder is rolling down a hill. If, at one moment, the boulder has a momentum of 239.5 kg ⋅ m/s, what is its velocity at that time?
Answer:
Velocity = 6.89 m/s
Explanation:
The equation for momentum: [tex]Momentum=(Mass)(Velocity)[/tex]
Substitute the given information into the equation and solve for velocity.
[tex]239.5=34.75(Velocity)\\\frac{239.5}{34.75}=\frac{34.75(Velocity)}{34.75\\}\\6.89=Velocity[/tex]
is cereal a soup? explain why or why not
Answer:
no
Explanation:
because its cold
soup is hot
I need the answer to this question what has the student plotted on the vertical axis?
Answer:
The correct option is D
Explanation:
In trying to achieve what the student wanted to see, which is to see the relationship between the weight the cord can hold and how long the cord will stretch. Since the origin of the graph is from zero, the value plotted on the vertical axis would be just the length caused by each weights. Thus, the original length would have to be subtracted from the measured length to determine the actual length caused by the weight added to the cord.
A 3.0 g bullet traveling at a speed of 400 m/s enters a tree and exits the other side with a speed of 200 m/s. Where did the bullet's lost KE go, and what was the energy transferred?
Answer:
1800J
Explanation:
Step one:
given data
mass of bullet m= 3g= 0.03kg
initial velocity u = 400m/s
final velocity v= 200 m/s
Step two:
1.The bullet's lost kinetic energy went inside the tree.
2. The energy transferred is computed as
= initial KE- KE final
Initial KE= 1/2mu^2
Initial KE= 1/2*0.03*400^2
Initial KE= 1/2*0.03*160000
Initial KE= 1/2*4800
Initial KE= 2400J
KE final= 1/2mv^2
KE final= 1/2*0.03*200^2
KE final= 1/2*0.03*40000
KE final= 1/2*1200
KE final= 600J
KE transferred = 2400-600
KE transferred= 1800J
all 3 of these examples (Volt, Newton, Tesla) are units that come from other metric units true or false?
Answer:
False
Explanation:
because Only Volt and Newton are units come from metric units, however, the Tesla is not come from Metric units.
I need help please
What % of offspring will be green?
Answer:
50%
Explanation:
Gg = 50%
gg = 50%
are these punnet squares?
Pleaaaase help meeee
Read the following case and discuss how you would respond to the situation.
PROBLEM:
You have been assigned the position of Environmental Engineer for one of several local
robotics manufacturers whose water discharges flow into a lake in a flourishing tourist area.
Although all the robotics companies in the area are marginally profitable, they compete for
the same customers. Included in your responsibilities is the monitoring of water and air
discharges
at your plant and the periodic preparation of reports to be submitted to the Department of
Natural Resources. You have just prepared a report that indicates that the
level of pollution in the plant's water discharges slightly exceeds the legal limitations. Your
boss, the Plant Manager, says you should regard the excess as a mere
"technicality," and he asks you to "adjust" the data so that the plant appears to be in
compliance. He says that the slight excess is not going to endanger human or fish
life any more than if the plant were in compliance. On the other hand, he says, solving the
problem would require a very heavy investment in new equipment. He
explains, "We can't afford new equipment. It might even cost a few jobs. It will set us
behind our competitors. Besides the bad publicity we'd get, it might scare off
some of the tourist industry, making it worse for everybody."
1) How do you think you should respond to your boss's request? Explain :
2) Define the problem :
3) what are the possible results of decision?
4) is there any information about the situation that is not obvious or available in the paragraph?
5) what are the ethical issues to consider in this situation
6) How did you decide to handle the situation what did you decide to do?
Answer:
3
Explanation: