The tοtal energy οf the system is 0.0181 J. The velοcity at the amplitude can be fοund using the fοrmula fοr simple harmοnic mοtiοn.
What is Energy?Energy plays a crucial rοle in virtually every aspect οf οur lives and is invοlved in everything frοm the mοvement οf οbjects tο the functiοning οf οur cells and οrgans. Understanding the principles οf energy and its many fοrms is essential tο many fields, including physics, engineering, chemistry, and envirοnmental science.
Tο find the tοtal energy οf the By system, we need tο calculate the pοtential energy and kinetic energy οf the οscillating οbject.
[tex]U = (1/2) k x^2[/tex]
In this case, the displacement is the amplitude οf οscillatiοn, which is 2.9 cm οr 0.029 m. The spring cοnstant can be fοund using the fοrmula:
k = F/x
The fοrce can be calculated frοm the weight οf the οbject:
F = m g
where m is the mass οf the οbject and g is the acceleratiοn due tο gravity [tex](9.81 m/s^2)[/tex]. Therefοre,
[tex]F = 0.8 kg \times 9.81 m/s^2 = 7.848 N[/tex]
The spring cοnstant is then:
k = F/x = 7.848 N / 0.088 m = 89.09 N/m
The pοtential energy οf the spring at the maximum displacement (amplitude) is:
[tex]U = (1/2) k x^2 = (1/2) \times 89.09 N/m \times (0.029 m)^2 = 0.0122 J[/tex]
The kinetic energy οf the οscillating οbject can be fοund using the fοrmula:
[tex]K = (1/2) m v^2[/tex]
where v is the velοcity οf the οbject at any pοint during the οscillatiοn. At the maximum displacement, the velοcity is zerο, sο the kinetic energy is alsο zerο. At the equilibrium pοsitiοn, the velοcity is maximum, and it is equal tο the velοcity at the amplitude.:
v = ω A
where ω is the angular frequency οf the οscillatiοn, and A is the amplitude. The angular frequency can be fοund using the fοrmula:
ω = √(k/m)
Therefοre,
ω = √(89.09 N/m / 0.8 kg) = 4.195 rad/s
and
v = ω A = 4.195 rad/s × 0.029 m = 0.1217 m/s
The kinetic energy at the amplitude is then:
[tex]K = (1/2) m v^2 = (1/2)\times 0.8 kg \times (0.1217 m/s)^2 = 0.0059 J[/tex]
The tοtal energy οf the system is the sum οf the pοtential and kinetic energies:
E = U + K = 0.0122 J + 0.0059 J = 0.0181 J
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A scientist makes a model of Earth's water by drawing 100 drops of water, all the same size. How many of the 100 drops represent ocean water?
A.3
B.50
C.75
D.97
Answer:
D
Explanation:
If the water represents the oceans water then you'd would need to calculate how much of earth is water (96.5)
A rock group is playing in a bar. Sound
emerging from the door spreads uniformly in
all directions. The intensity level of the music
is 32.2 dB at a distance of 4.99 m from the
door.
At what distance is the music just barely
audible to a person with a normal threshold
of hearing? Disregard absorption.
Answer in units of m.
Answer:
5292.64 m
Explanation:
I need this tomorrow 50 points
Answer: NUMBER - 275.5 N
Explanation:
On a hot summer day, a young girl swings on a rope above the local swimming hole. When she lets go of the rope her initial velocity is 2.25m/s at an angle of 35º above the horizontal. If she is in flight for 1.20s, how high above the water was she when she let go of the rope?
When she let go of the rope, her height above the water would be 3.20 meters.
Kinematic motionWe can use the equations of motion to solve this problem. Let's assume that the girl's initial height above the water is h, and that the acceleration due to gravity is -9.81 m/s^2 (negative because it is directed downward). Then we have:
Initial horizontal velocity (vx) = 2.25 cos(35º) = 1.84 m/s
Initial vertical velocity (vy) = 2.25 sin(35º) = 1.30 m/s
During the 1.20 s of flight, the girl's vertical motion can be described by the following equation:
h + vy*t + (1/2)gt^2 = 0
where t is the time of flight and g is the acceleration due to gravity. Substituting the known values, we get:
h + (1.30 m/s)(1.20 s) + (1/2)(-9.81 m/s^2)*(1.20 s)^2 = 0
Simplifying and solving for h, we get:
h = -1/2*(-9.81 m/s^2)(1.20 s)^2 - (1.30 m/s)(1.20 s) = 3.20 m
Therefore, the girl was 3.20 meters above the water when she let go of the rope.
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A machine has velocity ratio 6 and is 80% efficient. what effort would be needed to lift a load of 300N with the aid of this machine?
The effort needed to lift the load of 300 N, given that the velocity ratio is 6 and the machine has an efficiency of 80% is 62.5 N
How do i determine the effort needed to lift the load?First, we shall determine the mechanical advantage of the machine. Details below:
Velocity ratio (VR) = 6Efficiency = 80%Mechanical advantage (MA) = ?Efficiency = MA / VR
80% = MA / 6
Cross multiply
MA = 80% × 6
MA = 4.8
Finally, we shall determine the effort of the machine. Details below:
Mechanical advantage (MA) = 4.8Load (L) = 300 NEffort (E) = ?Mechanical advantage (MA) = Load (L) / Effort (E)
4.8 = 300 / Effort
Cross multiply
4.8 × Effort = 300
Divide both sides by 4.8
Efoort = 300 / 4.8
Effort = 62.5 N
Thus, we can conclude that the effort of the machine is 62.5 N
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Find I1, V1, and V2 for the circuit shown in Fig. 4
From the given circuit, the value of I1 = -4 Amp, V1 = -4 V, and the V2 = 4V. Ohm's law has three different variations that are related to voltage, current, and resistance. The relationship between the voltage across the terminals and the resistor's resistance determines the current for a constant flow of current.
What is the tenet of Ohm's law?According to Ohm's law, the voltage across a conductor determines how much current flows through it. For many materials, including metals, this is true so long as the temperature (as well as other physical parameters) stay constant.
What does "nodal analysis" mean?Any electrical network may be solved using nodal analysis, which is what it is called. the formula used to determine how much voltage is shared across circuit nodes. Since the node voltages are with respect to the ground, this method is also referred to as the node-voltage method.
Applying KCL,
I1 = -1 -3
I1 = -4 A
Applying concept of super-node,
V2 = 4V
[tex]\frac{4-V1}{2} -1-3=0[/tex]
[tex]2-\frac{V1}{2} =4[/tex]
[tex]\frac{-V1}{2} =4-2[/tex]
[tex]V1=-4V[/tex]
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The Hertzsprung-Russell diagram shown is divided into four sections.
C Section 3
n
Luminosity (Lsun)
Cortion A
10%
10⁰
10²
10-2
104
Hertzsprung-Russell Diagram
400 200 100
55
Temperature (x10² K)
Which section of the diagram includes the coolest, brightest stars?
A Section 1
B
Section 2
75
45
●
30
The section of the diagram that includes the coolest, brightest stars is A, Section 1.
How is the Hertzsprung-Russell diagram described?On the Hertzsprung-Russell diagram, the vertical axis represents luminosity, which is the total amount of energy emitted by a star per unit time. The luminosity is measured in units of solar luminosity, which is the amount of energy emitted by the Sun per unit time.
The section that includes the coolest, brightest stars is Section 1. This is because in this section, the stars have a low temperature (around 3,000-4,000 K) and a high luminosity (around 1,000-10,000 times that of the Sun). These stars are called red giants, and they are nearing the end of their lives. As they run out of fuel, their outer layers expand and cool, making them appear red and bright.
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which one defines force?
Answer:
a
Explanation:
a push or a pull that occurs when an object interacts with another object or field.
pls mrk me brainliest
If the train set uses stronger magnets, will the distance between these train cars increase or decrease? Explain your answer.
The distance between the train cars will decrease, as stronger magnets will create a greater attractive force between them. This will cause the cars to be pulled closer together.
What is stronger magnet?The strength of a magnet depends on the type of magnet and the material it is made from. Generally, the strongest magnets are neodymium magnets, also known as rare earth magnets. These are made from a combination of neodymium, iron, and boron and can produce magnetic fields up to 1.4 teslas, or 14,000 gauss. Samarium cobalt magnets are also powerful, producing fields up to 1.4 teslas. Other types of magnets, such as ceramic and Alnico magnets, generally produce magnetic fields of around 0.5 teslas or 5,000 gauss.
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Two point charges are arranged in a straight line.
The point charge q1 has a charge of +7 μC . The point charge q2 is located 0.02 m to the left of q1 and has a charge of +2 μC.
What is the net electrostatic force on q2?
Answer:
100 force
Explanation:
did math if not correct worth a search
Which type of wave interaction allows us to hear sounds around corners and under doors?
A. Diffraction
B.Absorption
C.refraction
D.reflection
Answer: Diffraction
Explanation: It is diffraction, because due to diffraction, sound waves bend on the corner as their size is of the order of wavelength of sound waves.
The wave in the liquid travels towards the surface at an angle. Fig 9.2 shows the centres of the compressions of the sound wave in liquid. Some compressions shown have reached the liquid-air boundary. The parts of these compressions in the air are not shown on Fig 9.2 These waves are also reflected at the boundary. Draw on the diagram the reflected wavefronts.
The reflected sound wavefronts at the given boundary are waves that have bounced off a surface and changed direction.
The reflected sound wavefront is shown in the attachment.
What are reflected wavefronts?A reflected wavefront is a wavefront that has bounced off a surface and changed direction. When a wave, such as a light wave or sound wave, encounters a surface, some of the wave energy is reflected back in the opposite direction.
An example of reflected sound wavefronts in water can be seen in underwater sonar imaging.
In sonar imaging, a sound wave is emitted from a source and travels through the water. When the sound wave encounters an object, some of the wave energy is reflected back toward the source.
Reflected wavefronts play an important role in many areas of science and engineering, such as optics, acoustics, and electromagnetism. They are used to model the behavior of waves in complex systems and to design and optimize devices such as mirrors, lenses, and antennas.
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3. The Leatherback is the largest sea turtle. If one has a
kinetic energy of 12 J while swimming at 0.2 m/s, what is
his mass in kg?
The answer to the given question is 150Kg. The leatherback sea turtle weighs about 150 kg.
To calculate the mass of the Leatherback sea turtle, we can use the formula for kinetic energy:
KE = 1/2 × m × v²
where KE is the kinetic energy, m is the mass of the object, and v is the velocity.
Given that the Leatherback sea turtle has a kinetic energy of 12 J while swimming at 0.2 m/s, we can plug in these values into the formula and solve for the mass:
12 J = 1/2 × m × (0.2 m/s)²
12 J = 1/2 × m × 0.04 m²/s²
m = (12 J) / (1/2 × 0.04 m²/s²)
m = 150 kg
Therefore, the mass of the Leatherback sea turtle is approximately 150 kg.
The Leatherback sea turtle is known for being the largest of all living sea turtles, with an average weight of around 500 to 1500 pounds (225 to 680 kg). Its size and weight enable it to swim vast distances across the ocean, traveling from nesting beaches to feeding grounds.
By using the formula for kinetic energy and the given values of velocity and kinetic energy, we can calculate the mass of the Leatherback sea turtle. The mass of the Leatherback sea turtle is significant, weighing approximately 150 kg, which is required for it to be able to swim through the vast oceans.
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Use the table to answer the question.
Wave Wavelength (meters) Frequency (hertz)
W 5 200
X 3 300
The table shows information about two waves. Based on the given information, which conclusion can be made?
O Wave W has a faster speed.
O Wave W has a greater amplitude.
O Wave X has a greater amplitude.
O Wave X has a faster speed.
We can see from the table that we have in the question that Wave W has a faster speed.
What is the relationship of wavelength and frequency?Wavelength and frequency are two fundamental properties of waves, including electromagnetic waves and sound waves. The relationship between wavelength and frequency can be described by the following equation:
c = λν
where c is the speed of light (or speed of sound), λ is the wavelength, and ν is the frequency.
According to this equation, the wavelength and frequency are inversely proportional to each other.
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if 100g of iron at 100°c is dropped into 390g of water at 20°c what will the final temperature be?
1 point Which two sentences best state the central ideas of Wiesel's speech? Remember those who were killed at Auschwitz. Allow memories of Auschwitz to help prevent similar tragedies. Understand that what happened at Auschwitz could never be repeated. Choose to move on from Auschwitz and embrace a hopeful future. Pay honor to those who survived Auschwitz.
The two sentences that best state the central ideas of Wiesel's speech are:
Remember those who were killed at Auschwitz.Allow memories of Auschwitz to help prevent similar tragedies.Elie Wiesel's speech
Elie Wiesel's speech focuses primarily on the Holocaust and the atrocities that were committed during that time, particularly at Auschwitz. The central ideas of his speech are:
Remember those who were killed at Auschwitz: Wiesel emphasizes the importance of remembering and honoring the memory of those who died at Auschwitz. He believes that we must never forget the victims of the Holocaust, and we must ensure that their memory lives on.Allow memories of Auschwitz to help prevent similar tragedies: Wiesel believes that by remembering the horrors of Auschwitz, we can work to prevent similar tragedies from occurring in the future. He believes that it is our duty to learn from the past and use our knowledge to create a better world.More on Wiesel's speech can be found here: https://brainly.com/question/30338903
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Physics problem in the photo that I have no clue how to answer, please, and thank you!
The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. It is expressed by the equation: fr = Fr/N.
What is the coefficient of friction μ?coefficient of friction, ratio of the frictional force opposing the motion of two surfaces in contact to the normal force pushing the two surfaces together.
Typically, it is represented by the Greek letter mu (). In terms of math, is equal to F/N, where F stands for frictional force and N for normal force. The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, although it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible.
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Full Question ;
A concrete highway curve of radius 80.0 m is banked at a 18.0 degrees angle.
What is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding? (Take the static coefficient of friction of rubber on concrete to be 1.0.)
Explain why a football accelerates
faster than a soccer ball when the
same amount of force is applied?
Answer: Answer is below <3 (The underlined part is the answer)
Explanation: The reason why an object with a smaller mass has a larger acceleration than an object with a larger mass if the same force acts on each is because the acceleration of an object depends on its mass as well as the force exerted on it, and if the mass is smaller than the other object than it is faster.
The reason why a football accelerates faster than a soccer ball when the same amount of force is applied is because of the difference in their masses. The acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. This means that the smaller the mass of an object, the greater the acceleration it experiences when the same amount of force is applied to it.
A football is typically smaller and lighter than a soccer ball, so when the same amount of force is applied to both balls, the football experiences a greater acceleration due to its lower mass. This is consistent with Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
Additionally, the surface area and shape of the balls can also affect their acceleration. A football is typically more aerodynamic with a pointed shape that reduces air resistance, allowing it to move through the air more easily and accelerate faster. In contrast, a soccer ball has a more spherical shape that can create more air resistance, slowing down its acceleration.
Therefore, the mass, shape, and surface area of the ball are all factors that can affect its acceleration when a force is applied.
A 7g bullet is fired into a 345g block that is initially at rest at the edge of a frictionless table of height 1.9m. The bullet remains in the block and after impact the block lands 2m from the bottom of the table. Find the initial speed of the bullet. The acceleration due to gravity is 9.8m/s^2. Answer in units of m/s
Answer:
≈ 192.7 m/s
Explanation:
Let's start by finding the velocity of the block just before it hits the ground. We can use the conservation of energy:
The initial potential energy of the block is mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the table.The final kinetic energy of the block is (1/2)mv^2, where v is the velocity of the block just before it hits the ground.Conservation of energy tells us that these two energies are equal:
mgh = (1/2)mv^2
Solving for v, we get:
v = sqrt(2gh)
Plugging in the given values, we get:
v = sqrt(2 * 9.8 m/s^2 * 1.9 m) = 6.06 m/s
Now, let's use conservation of momentum to find the initial speed of the bullet. We know that the total momentum of the system (bullet + block) is conserved before and after the collision. Before the collision, the momentum is:
p = mb * vb
where mb is the mass of the block and vb is its initial velocity, which is 0 since it is at rest.
After the collision, the bullet and block move together with a common velocity v. The total momentum is:
p = (mb + m) * v
where m is the mass of the bullet. Since momentum is conserved:
mb * vb = (mb + m) * v
Solving for vb, we get:
vb = (mb + m) * v / mb
Plugging in the given values, we get:
vb = (345 g + 7 g) / 7 g * 6.06 m/s = 192.7 m/s
Therefore, the initial speed of the bullet was approximately 192.7 m/s.
1. Find the displacement of a
farmer who walked 80.0 m
[0°] and then 60.0 m [335°].
it of
The farmer had a displacement of 133.4 m at an angle of -15.5° after moving 80.0 m [0°] and then 60.0 m [335°].
To find the displacement of the farmer who walked 80.0 m [0°] and then 60.0 m [335°], we need to use vector addition. First, we need to convert the distances and angles into their respective x and y components. The x component of the first displacement is 80.0 m (cos 0°) = 80.0 m, and the y component is 80.0 m (sin 0°) = 0 m. Similarly, the x component of the second displacement is 60.0 m (cos 335°) = 49.5 m, and the y component is 60.0 m (sin 335°) = -35.1 m (negative because it is in the fourth quadrant).
Next, we add the x and y components separately to find the resultant x and y components.
Resultant x component
= 80.0 m + 49.5 m
= 129.5 m
Resultant y component
= 0 m - 35.1 m
= -35.1 m
Now, we can use the Pythagorean theorem to find the magnitude of the resultant displacement:
|displacement| = √(129.5 m)² + (-35.1 m)²
= 133.4 m
Lastly, we can use inverse tangent to find the direction of the displacement:
θ = a tan (-35.1 m / 129.5 m) = -15.5°
Therefore, the displacement of the farmer who walked 80.0 m [0°] and then 60.0 m [335°] is 133.4 m at an angle of -15.5°.
Finding displacement through vector addition is a common problem in physics and is an important concept in understanding motion. By breaking down distances and angles into their respective x and y components, we can add them together to find the resultant displacement.
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5. What is the area of this figure? Please show your work.
20 in.
7 in
6. What is the area of this figure? Please show your
10 ft
8 ft
6 ft
work.
Answer:
The area of the figure 7 in the area of 6 ft
Use the work energy theorem to rank the final kinetic energy of a ball based on the initial kinetic energy Ki, the magnitude of a constant force F on the ball, the displacement of the ball, d and the angle, theta between the displacement of the ball and the net force on the ball. Rank from greatest kinetic energy (1) to least kinetic energy (4).
1. ki= 150 J, F= 10 N, d=15 m, theta= 90 degrees
2. Ki= 300 J, F= 200 N, d= 1.5 m, theta= 180 degrees
3. ki= 200 J, F= 25 N, d= 4 m, theta= 0 degreee
4. ki= 450 J, F= 15 N, d= 30 m, theta= 150 degrees
4.
Answer:
150 J
-300 J
300 J
256.8 J
Explanation:
Use the following equation: W = ΔK = Kf - Ki
Calculations below:
Ki = 150 J, F = 10 N, d = 15 m, θ = 90°
The work done on the ball is:
W = Fd cos θ = 10 × 15 × cos 90° = 0 J
Therefore, the final kinetic energy is:
Kf = Ki + W = 150 + 0 = 150 J
Ki = 300 J, F = 200 N, d = 1.5 m, θ = 180°
The work done on the ball is:
W = Fd cos θ = 200 × 1.5 × cos 180° = -600 J
Therefore, the final kinetic energy is:
Kf = Ki + W = 300 - 600 = -300 J
Ki = 200 J, F = 25 N, d = 4 m, θ = 0°
The work done on the ball is:
W = Fd cos θ = 25 × 4 × cos 0° = 100 J
Therefore, the final kinetic energy is:
Kf = Ki + W = 200 + 100 = 300 J
Ki = 450 J, F = 15 N, d = 30 m, θ = 150°
The work done on the ball is:
W = Fd cos θ = 15 × 30 × cos 150° = -193.2 J
Therefore, the final kinetic energy is:
Kf = Ki + W = 450 - 193.2 = 256.8 J
An 12.000 milligram particle is sliding across a friction-less one-dimensional path at 55.000 m/s and collides with a 68.000 milligram particle moving at -48.000 m/s in a perfectly inelastic collision. What are the velocities of the particles after the collision?
answer with correct units
Answer:
-3525.000 m/s
Explanation:
In a perfectly inelastic collision, the two particles stick together and move with a common velocity after the collision. We can use the conservation of momentum to solve for this common velocity.
The initial momentum of the system is:
p_initial = m1 * v1 + m2 * v2
= (12.000 mg)(55.000 m/s) + (68.000 mg)(-48.000 m/s)
= -282.000 kg·m/s
Here, we convert the masses to kilograms to match the units of velocity.
Since the particles stick together after the collision, their masses add up:
m_final = m1 + m2
= 12.000 mg + 68.000 mg
= 80.000 mg
= 0.080 g
Now, we can use the conservation of momentum to find the final velocity:
p_final = m_final * v_final
where p_final = p_initial and m_final = 0.080 g.
Therefore:
v_final = p_final / m_final
= -282.000 kg·m/s / 0.080 g
= -3525.000 m/s
Help me please I’m begging
The total resistance is 3 ohm
The current is 1.5 A
What is the total resistance of the circuit?To calculate the total resistance of a circuit, you need to determine the equivalent resistance of all the resistors in the circuit. The equivalent resistance is the single resistance value that could replace all the individual resistors and produce the same overall resistance.
1) This is a parallel circuit thus;
1/RT = 1/6 + 1/6
RT = 3 ohm
2) This is a series circuit thus;
RT = 4 + 6 = 10 ohm
Current = 15V/10 ohm
= 1.5 A
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PLEASEEEEEEE HELPPPPPPPPP
Follow these directions:
1. Let your partner hold a ruler or meter stick in his/her hand vertically between the thumb and index finger, making sure he/she holds the meter stick so that the zero mark is between his/her fingers with the 1 cm mark above it. Your friend should hold the meter stick toward the top end, while your fingers are open at the bottom end of the ruler, ready to catch it between your index finger and your thumb . You should not be touching the meter stick or ruler.
2.Have your partner release the meter stick or ruler. As soon as you see the ruler released, snap your fingers shut and catch it.
3. Record in a data table the centimeter mark that was closest to your fingers.
4.Repeat this procedure several times, and average your results.
5.Change centimeters to meters.
6. Then calculate your reaction time by using the formula above and 9.8 m/s2 for g.
7. Compare your reaction time with that of your partner. Write out your comparison and possible reasons for differences.
004 (part 1 of 2) 10.0 points
In a 95 s interval, 216 hailstones strike a glass
2
window of area 1.156 m² at an angle 67 to the
window surface. Each hailstone has a mass of
5 g and speed of 13.5 m/s.
If the collisions are elastic, find the average
force on the window.
Answer in units of N.
005 (part 2 of 2) 10.0 points
Find the pressure on the window.
Answer in units of N/m².
Average force F = 97.52 N acting on window surface.
Pressure on the window: P = 84.39 N/m²
Explain about the elastic collision?An elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of the collision. In elastic collisions, momentum as well as kinetic energy are both conserved. An example of an elastic collision is when two balls collide at a pool table.Average force F:
F = mg sinФ
Put the values:
F = 0.05*9.81* sin 67°
F = 0.45 N
Number of hailstones = 216
Average force F = 0.45* 216 = 97.52 N
Pressure on the window:
Pressure = Average force / area
P = 97.52 / 1.156
P = 84.39 N/m²
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A rocket at rest on the ground with initial mass 20,000 kg, 80% of which is fuel, burns 200kg/s as it flies
directly upwards. The exhaust gas exits the rocket at a relative speed of 1.80 km/s. Find (a) the thrust of
the rocket, (b) how long it takes to exhaust its fuel, and (c) the rocket’s speed at the end of its engine burn.
Assume g is constant and neglect air resistance.
For Part A I got: 360,000 Newtons, Part B: 20 Seconds, Part C 205.658 m/s
Are my answers correct?
To check your answers, we can use the following equations:
(a) Thrust = (mass flow rate of exhaust gas) * (exhaust velocity of gas) + (initial mass of rocket) * (acceleration due to gravity)
(b) Time to exhaust fuel = (0.8 * initial mass of rocket) / (mass flow rate of exhaust gas)
(c) Final velocity of rocket = (exhaust velocity of gas) * ln(initial mass of rocket / final mass of rocket)
Using the given values:
Mass flow rate of exhaust gas = 200 kg/s
Exhaust velocity of gas = 1.80 km/s = 1800 m/s
Initial mass of rocket = 20,000 kg
Acceleration due to gravity = 9.81 m/s^2
Final mass of rocket = 0.2 * initial mass of rocket = 4,000 kg
(a) Thrust = (200 kg/s) * (1800 m/s) + (20,000 kg) * (9.81 m/s^2) = 360,000 N
Your answer for part (a) is correct.
(b) Time to exhaust fuel = (0.8 * 20,000 kg) / (200 kg/s) = 800 s = 20 minutes
Your answer for part (b) is incorrect. The correct answer is 800 seconds or 20 minutes, not 20 seconds.
(c) Final velocity of rocket = (1800 m/s) * ln(20,000 kg / 4,000 kg) = 205.66 m/s
Your answer for part (c) is correct.
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It is female (XO).A karyotype can be used to diagnose a chromosomal disorder by examining the number and arrangement of a person's chromosomes.
What is chromosomes ?Chromosomes are thread-like structures located in the nucleus of cells that carry genetic information in the form of genes. They are composed of DNA and proteins and are responsible for directing the development and functioning of cells. In humans, chromosomes come in pairs of 23, with one copy of each pair inherited from each parent.
For example, Down Syndrome is caused by an extra chromosome 21, Klinefelter Syndrome is caused by an extra X chromosome in males (XXY), and Turner Syndrome is caused by a single X chromosome in females (XO).
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Compare the patterns of iron filings to the spiral arms in Interacting galaxies.
The primary locations for the birth of new stars are in galaxies' spiral arms. The proportion of the galaxy that can participate in star formation increases as more gas and dust become available.
What distinguishes the numerous varieties of spiral galaxies?We refer to some spiral galaxies as "barred spirals" because the centre bulge seems extended, like a bar. The spiral arms of the galaxy seem to emerge from the ends of the bar in barred spirals. Elliptical galaxies are round or oval in shape, as their name implies, and have a rather uniform distribution of stars.
The four spiral arms are what?The Norma and Cygnus arm, Sagittarius, Scutum-Crux, and Perseus arms are the four principal spiral arms of the Milky Way.
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A car is moving along a road at 13.0 m/s with an engine that exerts a force of 1,775.0 N on the car to balance the drag and friction so that the car maintains a constant speed. What is the power output of the engine?
Answer:
The power output of the engine can be calculated using the formula:
Power = Force x Velocity
where force is the net force acting on the car, and velocity is the speed of the car. In this case, the net force is equal to the force exerted by the engine, which is 1,775.0 N, since the car is moving at a constant speed and there is no acceleration. The velocity of the car is 13.0 m/s. Thus, the power output of the engine can be calculated as:
Power = 1,775.0 N x 13.0 m/s = 23,075 W
Therefore, the power output of the engine is 23,075 watts.