a 0.015 kg bullet traveling at 500 m/s strikes a 1.0 kg block of wood that is balanced on a table edge 0.92 m above the ground as shown to the right. the bullet buries itself in the block. calculate the horizontal distance, dx where the block hits the floor.

Answers

Answer 1

The horizontal distance where the block hits the floor is 3.2 m.

The given parameters:

mass of the bullet, m₁ = 0.015 kgspeed of the bullet, u₁ = 500 m/smass of block wood, m₂ = 1.0 kgheight of the table, h = 0.92 m

The final velocity of the bullet-block system after the collision is calculated by applying the principle of conservation of linear momentum;

[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.015(500) + 1(0) =v(0.015 + 1)\\\\7.5 = 1.015v\\\\v = \frac{7.5}{1.015} \\\\v = 7.39 \ m/s[/tex]

The time taken for the bullet-block system to fall to the floor after collision is calculated as follows;

[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.92}{9.8} }\\\\t = 0.43 \ s[/tex]

The horizontal distance where the block hits the floor is calculated as follows;

[tex]X = v_x t\\\\X = 7.39 \times 0.43\\\\X = 3.2 \ m[/tex]

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Related Questions

What is the object' velocity between O s and 2 s?

Answers

Answer:

Explanation:

Acceleration b/c 0m/s/2s =0m/s²

How much energy does a 150 N child have sitting on a 35M high cliff

Answers

Answer:

150+35=185 Plsss Brainliest plssss

A 27.0 kg box is pulled with a 113.6 N force at an angle of 35.1 degrees along a
surface that has a coefficient of friction of 0.4. What is the net force on the box?

Answers

Answer: 2,509.42

Explanation: using the equation net force=force x cos(angle) we can find the net force by multiplying the kg and the Newtons to get 3,067.2 then find the cos of 35.1 then multiple those two together to get 2,509.42

How many protons, electrons and nurturing does krypton have NEED HELP ASAP THANK YOU

Answers

Answer:

Krypton – Mass Number – Neutron Number – Kr 2020-11-21 by Nick Connor Krypton is a chemical element with atomic number 36 which means there are 36 protons and 36 electrons in the atomic structure. The chemical symbol for Krypton is Kr.

Atomic Number: 36

Element: Krypton

Element Category: Noble Gas

Symbol: Kr

Explanation:

Answer:

your answer is in an image here

imageshare.best/image.php?id=JS9NDO

Explanation:

copy and paste in browser

not a bot btw

Qué velocidad –en m/s– tiene un móvil, que recorre 15 km en 20 minutos
(es para hoy por faaaa)

Answers

Answer:

Explanation:

15 km(1000 m / km) / (20 min(60 s/min)) = 12.5 m/s

Which object would have more momentum?

A 2 kg ball rolling at 4 m/s

A 5 kg ball rolling at 2 m/s

(Hint: Use momentum = mass * velocity)

a
Not enough information to determine which ball has more momentum.
b
They have the same momentum.
c
The 2 kg ball will have more momentum.
d
The 5 kg ball will have more momentum.

Answers

Answer:

b is the ans......

Explanation:

"b" (and any subsequent words) was ignored because we limit queries to 32 words.


A wheel with radius 41.5 cm rotates 5.13 times every second.
Find the period of this motion.
What is the tangential speed of a wad of chewing gum stick to the rim of the wheel?

Answers

The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.

Let suppose that the wheel rotates at constant angular speed ([tex]\omega[/tex]), in radians per second, the tangential speed of a wad of chewing gum to the rim of the wheel ([tex]v[/tex]), in centimeters per second, is:

[tex]v = 2\pi\cdot r\cdot f[/tex] (1)

Where:

[tex]r[/tex] - Radius of the wheel, in centimeters[tex]f[/tex] - Frequency, in hertz

If we know that [tex]f = 5.13\,hz[/tex] and [tex]r = 41.5\,cm[/tex], then the tangential speed of the chewing gum is:

[tex]v = 2\pi\cdot (41.5\,cm)\cdot (5.13\,hz)[/tex]

[tex]v \approx 1337.659\,\frac{cm}{s}[/tex]

The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.

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During an experiment, your teacher gives you two objects: tissue paper and a balloon. You observe that the tissue paper repels the balloon. What does this most likely tell you about the charges of the two objects?

Both objects have negative charges.
The tissue has a positive charge, and the balloon has a negative charge.
The tissue has a negative charge, and the balloon has a positive charge.
The objects have no interactive with each other.

Answers

Answer:

i think your answer is this: the objects have no interactive with each other.

Explanation:

if you think about it tissue paper doesn't really have a static electrical charge if it does it is very weak so therefore cannot really attract or repel anything.

An irregularly shaped object weighs 11.20 N in air. When immersed in water, the object has an apparent weight of 3.83 N. Find its density.

Answers

Answer:

Weight of object = 11.2 N

Apparent weight = 3.83 N     when immersed

Weight of water displaced = 11.2 - 3.83 = 7.37 N      

d (density) W / V       weight / volume      the weight density

Wo = Vo do    weight of object

Ww = Vo dw    where Ww is weight of equivalent volume of water = 7.37

Wo / Ww = do / dw    dividing previous equations

do = 11.2 / 7.37 dw = 1.52 dw

The density of the object is 1.52 that of water

The density of water is 1000 kg / m^3 * 9.8 m/s^2 = 9800 N/m^3

So the weight density is 14900 N/m^3

An irregularly shaped object weighs 11.20 N in air. When immersed in water, the object has an apparent weight of 3.83 N. It's density can be calculated as 1523 kg/m³.

To find the density, the given values are,

Weight in air = 11.20 N

Weight in water = 3.83 N

density of water = 1000 kg/m³

What is meant by Density?

According to the Archimedes principle, when a body is immersed in a liquid partly or wholly, it experiences an upward force which is called buoyant force. The buoyant force is equal to the loss in weight of the body.

Loss in weight of the object = Weight of object in air - weight of object in water

Loss in weight = 11.20 - 3.83 = 7.37 N

Volume of body x density of water x g = 7.37

Let V be the volume of body

V x 1000 x 9.8 =7.37

V = 7.5× 10⁻⁴ m³

Weight in air = Volume of body x density of body x g

11.20 = 7.5× 10⁻⁴ x d x 9.8

d = 1523 kg/m³.

Thus, the density of body is 1523 kg/m³.

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Which of the following is most likely to be a secondary source

Answers

Answer:

analyze, assess or interpret an historical event, era, or phenomenon,.

Explanation:

Secondary sources are works that analyze, assess or interpret an historical event, era, or phenomenon, generally utilizing primary sources to do so. Secondary sources often offer a review or a critique. Secondary sources can include books, journal articles, speeches, reviews, research reports, and more.

Please help me.............................

Answers

Answer:

[tex]a[/tex]

Explanation:

is a corect anser

Four men are pushing on a broken car. One man pushes on the car with 345 N, another with 203 N, another
with 291 N and 101 N. The friction between the car and road pushes in the opposite direction with a force of 940 N.
1.) Make a claim: What is the net force on the car?
2.) Cite evidence: What evidence supports your claim?
3.) Make a claim: Will the car move?
4.) Provide reasoning: Why do you say that?

Answers

Answer:

1. 3 N

2. The total force being put on the car by the men is 943 while the friction is going in the opposite direction with a force of 940.

3. Yes

4. The net force is not equal to zero

Explanation:

1. 345 + 203 + 291 + 101 = 943 + -940 = 3

4. The winding ridge of a screw​

Answers

Answer:

Thread.

Explanation:

The most common form consists of a cylindrical shaft with helical grooves or ridges called threads around the outside.

A fan blade Spins at 3,000 revolutions per minute.
How
many degrees does it rotate in one second?

Answers

18,000 degrees in one second i believe

What are the three major types of severe weather? Describe at least two characteristics of each type

Answers

Answer:

High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.

Explanation:High winds-  wind speeds as low as 23 knots (43 km/h) may lead to power outages when tree branches fall and disrupt power lines. Once wind exceed 135 knots (250 km/h) within strong tropical cyclones and tornadoes, homes  completely collapse,  and significant damage is done to larger buildings. Total disruption occurs once wind exceeds 175 knots (324 km/h)

Tornado- Typically look like a narrow funnel reaching from the clouds to the ground. Their wind speed goes from 65 to 250 miles per hour.

"An extreme weather condition in which we face the high speed wind in combination with heavy snow."

As for any blizzard has the normal wind speed of about 40 mph, and the visibility range reduces to less then 500 ft.

Answer: High winds, hail, excessive precipitation, and wildfires are forms and effects of severe weather, as are thunderstorms, downbursts, tornadoes, waterspouts, tropical cyclones, and extratropical cyclones. Regional and seasonal severe weather phenomena include blizzards (snowstorms), ice storms, and duststorms.

Explanation:

2. The system shown is accelerated by applying a tension Ti to the right-most cable. Assume the system is
frictionless. Solve for the tension in the cable between the blocks, T2, in terms of T. (not a).

Answers

The tension in the cable between the blocks, T₂, is [tex]\frac{2T_i}{7}[/tex]

The given parameters:

Mass of the first block, = 2 kgMass of the second block, = 5 kg

The net force on the block system is calculated by applying Newton's second law of motion as follows;

Total mass of the block-system = 2 kg + 5 kg = 7 kg

The acceleration of the block-system;

[tex]a = \frac{T_i}{7}[/tex]

The tension in the cable between the blocks, T₂, is calculated as;

[tex]T_2 = m_2 a\\\\T_2 = 2a\\\\T_2 = 2 \times \frac{T_i}{7} \\\\T_2 = \frac{2T_i}{7}[/tex]

Thus, the tension in the cable between the blocks, T₂, is [tex]\frac{2T_i}{7}[/tex].

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You are in Paris, 50. m up on an Eiffel Tower support leg observation deck. If you throw a euro downward at a velocity of -1.0 m/s, how long would it take the coin to hit the ground?​

Answers

Here’s my work to your question. I used kinematic equations to solve. :)

A solid, uniform sphere with a mass of 2.5 kg rolls without slipping down an incline plane starting from rest at a vertical height of 19 m. If the sphere has a radius of 0.60 m, what is the angular speed of the sphere at the bottom of the incline plane

Answers

Answer:

1/2 m v^2 + 1/2 I ω^2 = m g h       conservation of energy

I = 2/5 m R^2     inertia of solid sphere

1/2 m v^2 + 1/5 m ω^2 R^2 = m g h

1/2 v^2 + 1/5 v^2 = g h

v^2 = 10 g h / 7 = 1.43 * 9.80 * 19 m^2/s^2 = 266 m^2/s^2

v = 16.3 m/s

v = R ω

ω = 16.3 / .6 = 27.2 / sec

Your friend's Frisbee has become stuck 19 m above the ground in a tree. You want to dislodge the Frisbee by throwing a rock at it. The Frisbee is stuck pretty tight, so you figure the rock needs to be traveling at least 4.1 m/s when it hits the Frisbee.

If you release the rock 1.8 m above the ground, with what minimum speed must you throw it?

Answers

Answer:

18.36 m/s

Explanation:

We can solve this using conservation of energy. The energy in the system will be conserved since there are no outside forces acting upon it so the potential energy and kinetic energy will be equal. Giving us this formula to start:

1/2mv^2=mgh

m=mass

g=gravity

h=height

v=velocity

We can start by figuring out the total height the rock travels which we can do by subtracting the height of the frisbee by the height the rock started at.

19m-1.8m=17.2m

Now we can plug in our variables to solve for velocity.

First we negate mass since its on both sides and cancels out leaving us with.

1/2v^2=gh

Plug in.

1/2v^2=(9.8)(17.2)

1/2v^2=168.56

v^2=337.12

v=18.36m/s

Who won the noble prize for physics. He led a coalition of scientists who argued to control nucleus weapons

Answers

Answer:

Linus Pauling

Explanation:

Prize motivation: "for his fight against the nuclear arms race between East and West." Linus Pauling received his Nobel Prize one year later, in 1963.

half-life questionnnnn:

Answers

120 and 150 and 180 and 210

Chronic diseases are also know as

Answers

Answer:

Chronic Condition or Long-term Illness

Explanation:

They can also be known as Chronic Conditions or Long-Term Illnesses, hope this helps.

Answer:

Chronic condition, also called long-term condition.

Explanation:

Pls answer ASAP pls bc I’m tryna get my grade up please

Answers

Answer:

The right answer for this question is 85%.

(I had the same question.)

A 40-kg worker climbs a ladder upwards for 15m. What work was done during their climb upwards?

Answers

Answer:

Explanation:

The work increased the potential energy

W = PE = mgh = 40(9.8)(15) = 5880 J(oules)

A mass of 0.01 kg of steam at a quality of 0.9 is contained in the cylinder as shown in Figure 1 below. The spring just touches the top of the piston. Heat is then added until the air expanded, and the spring is compressed by 15.7 cm. Calculate the final temperature of the steam in this cylinder. Sketch the process on a P-y and T-v diagrams with respect to saturation lines.​

Answers

A mass of 0.01 kg of steam at a quality of 0.9 is contained in the cylinder as shown in Figure 1 below. The spring just touches the top of the piston. Heat is then added until the air expanded, and the spring is compressed by 15.7 cm. Calculate the final temperature of the steam in this cylinder. Sketch the process on a P-v and T-v diagrams with respect to saturation lines K = 50 kN/m 160 kg 20 cm Figure 1 Piston cylinder with spring

What is the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25
s with 7,500 N of force?
128 kg
3991 kg
0.017 kg
14,091 kg

Answers

The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

HOW TO CALCULATE MASS:

The mass of an object can be calculated by dividing the force applied to the object by its acceleration.

According to this question, a bus can accelerate from rest to 15.5 m/s over 8.25s. The acceleration can be calculated as follows:

a = (v - u)/t

a = 15.5 - 0/8.25

a = 15.5/8.25

a = 1.88m/s²

The mass of the bus = 7500N ÷ 1.88m/s²

The mass of the bus = 3989.4kg

Therefore, the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

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Imagine that there is a small rocky body caught by Earth’s gravity. Draw a comic-strip cartoon

to illustrate its journey as it travels through space toward Earth, enters Earth’s atmosphere, and

lands on Earth. Describe your illustration with narration or speech/thought bubbles. Include the

use of these key terms: atmosphere, meteor, meteoroid, meteorite.

Answers

To create this comic strip you can use a narration describing each step and illustrate each one with one image or drawing.

Creating a comic strip involves using images and short texts to explain a specific idea or phenomenon. In the case of the process for a meteor to enter Earth you can use the following ideas.

A meteoroid approaches the Earth at high speed and draw a meteor traveling near to different planets and approaching Earth.What is that? and draw the Earth wondering who or what is approaching.The meteoroid enters the atmosphere of the Earth and becomes a meteor and draw the rocky body burningThe rocky body crashes with the surface becoming a meteorite and draw the zone where the meteorite crashed.

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What is the amplitude of this wave ?

Answers

Amplitude of a wave is the maximum displacement of the particles of a medium from their mean positions during the propagation of a wave.Here, the maximum displacement of the particles during wave propagation is equal to the height of the crests, i.e., EN or the depth of the troughs, i.e., MC.So, EN and MC are the amplitudes of the wave.The measure of EN is 1 mm.Hence, the amplitude of the wave is 1 mm.Note : I haven't considered -1 mm because amplitude cannot be negative.

Hope you could get an idea from here.

Doubt clarification - use comment section.

The block slides down an inclined friction-less track to a infinite hill that the block begins to climb and slow down. Is energy conserved or not?

Answers

Answer:

Energy is conserved.

Explanation:

Without friction, kinetic energy and gravity potential energy are always swapping back and forth.

The block slides down an inclined friction-less track to a infinite hill that the block begins to climb and slow down, in which the energy is conserved.

What is friction?

Friction refers to the force that prevents hard surface, fluid layers, as well as material elements from sliding against each other.

There are various kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in contact solid surfaces.

It is thought to be caused by the interactions of tiny bumps on surfaces rubbing against one another.

The bumps on each surface bend and exert force on one another, making it difficult for the surfaces to slide over one another.

A block's speed increases while its acceleration remains constant as it slides down a frictionless incline. After being placed on a ramp inclined at an angle with the horizontal, a crate remains stationary.

Thus, the block slides beneath an inclined friction-less track to an unlimited hill, where it commences to climb as well as slow down, preserving energy.

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Which is an electromagnetic wave A. The waves that heat a cup of water in a microwave oven B. A flag waving in the wind C. Turning on a flashlight D.The changes in the air that result from blowing a horn

Answers

Answer:

The answer would be A. The waves that heat a cup of water in a microwave oven

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