a 0.006kg bullet is fired at 350 m/s into a container that stops it at .30 m. what is the average force stopping the bullet?

Answer:

The answer for this question is

D

Answer:

The correct option is;

c. 12.8 cm

Explanation:

The given parameters are;

The length of each spring = 12 m  = 0.12 m

Given that the masses and the springs are vertically oriented, we have;

The mass on the first spring = 3 × 6.4 = 19.2 kg

The weight on the first spring = 19.2 kg × 9.81 m/s² = 188.352 N

The extension of the first spring = 188.352 N/7,800 N/m ≈ 0.02415 m

The mass on the second spring = 2 × 6.4 = 12.8 kg

The weight on the second spring = 12.8 kg × 9.81 m/s² = 125.568 N

The extension of the second spring = 125.568 N/7,800 N/m ≈ 0.016098 m

The mass on the third spring = 1 × 6.4 = 6.4 kg

The weight on the third spring = 6.4 kg × 9.81 m/s² = 62.784 N

The extension of the third (bottom) spring = 62.784 N/7,800 N/m ≈ 0.00805 m

The total length of the bottom spring = Original length of the bottom spring + Extension of the bottom spring

The total length of the bottom spring ≈ 0.12 m + 0.00805 m = 0.12805 m

The total length of the bottom spring ≈ 0.12805 m ≈ 12.81 cm

The bottom spring will be approximately 12.81 cm long.

Answer:

100

Explanation:

my apologies if I am wrong

Answer:

b and f

Explanation:

Following are examples of projectile motion: a. A tennis ball lobbed over a net c. A plastic disk sailing across a lawn d. A hawk diving to catch a mouse e. A parachutist drifting to Earth. The correct options are A, C, D and E.

Projectile motion refers to the motion of an object that is launched into the air and moves along a curved trajectory under the influence of gravity alone, with no other forces acting horizontally. In projectile motion, the object follows a path called a parabola.

In the given options, a tennis ball being lobbed over a net, a plastic disk sailing across a lawn, a hawk diving to catch a mouse, and a parachutist drifting to Earth all demonstrate projectile motion. In each case, the objects are initially launched or propelled into the air and subsequently follow a curved path influenced primarily by gravity. The trajectory of these objects can be described by a parabolic shape, which is a characteristic of projectile motion.

The correct options are A, C, D and E.

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Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 5N

distance = 20m

We have

workdone = 5 × 20

We have the final answer as

Hope this helps you

Explanation:

[tex]b. \: light[/tex]

Explanation:

the weight of the people inside the bus

Answer:

Same as loop #2

Explanation:

The magnitude of emf in loop #1 is the same as that of loop #2

Answer:

the path the object follows is called its trajectory so A. trajectory

Answer:

Reasd through the explanartion first :)

Explanation:

Initial velocity, u = 30 m/s

Final velocity, v = 100 m/s

Acceleration, a = 40 m/s²

Distance traveled, s = ?

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

So, putting all the values, we get

⇒ v² - u² = 2as

⇒ (100)² - (30)² = 2 × 40 × s

⇒ 10000 - 900 = 80s

⇒ 9100 = 80s

⇒ 9100/80 = s

⇒ s = 113.75 m.

Answer:

weight of truck in kg, height of person in meter m, amount of water in kiloliter kl, length of eyelash in mm

Answer:

(a). The change in electric potential energy is 8.3 μJ.

(b).  The second particle moves away from the source charge.

Explanation:

Given that,

Charge of first particle = -8.8 nC

Charge of second particle = -4.3 nC

Distance = 0.11 m

They are released and the second particle moves 0.030 m,

(a). We need to calculate the change in electric potential energy

Using formula of potential energy

[tex]U=\dfrac{Kq_{1}q_{2}}{d}[/tex]

Change in potential energy

[tex]\Delta U=\dfrac{kq_{1}q_{2}}{d_{2}}-\dfrac{Kq_{1}q_{2}}{d_{1}}[/tex]

Put the value into the formula

[tex]U=\dfrac{9\times10^{9}\times(8.8\times10^{-9}\times4.3\times10^{-9})}{0.030}-\dfrac{9\times10^{9}\times(8.8\times10^{-9}\times4.3\times10^{-9})}{0.11}[/tex]

[tex]\Delta U=0.000008256\ J[/tex]

[tex]\Delta U=8.3\ \mu J[/tex]

(B). We need to find the second particle move toward or away from the source charge

We know that,

Both charges are same, so the second particle will be repul from the source charge.

So, The second particle moves away from the source charge.

Hence, (a). The change in electric potential energy is 8.3 μJ.

(b).  The second particle moves away from the source charge.

Answer: Explanation:

If the net force on an object is doubled, its acceleration will double If the mass of an object is doubled, the acceleration will be halved .

In Newton’s second law, if the net force acting on object doubles then either acceleration is double or mass is double.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

According to Newtons second law force is product of mass and acceleration.

F = ma

In Newton’s second law, if the net force acting on object doubles then either acceleration is double or mass is double.

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Answer:

take another pic i cant see it

Explanation:

Answer:

0 N

Explanation:

Net force = mass × acceleration

∑F = ma

The velocity is constant, so the acceleration is 0.  Therefore, the net force is 0.

The net force acting on the bike is 0 N.

Net force is the sum of all forces acting on an object. The net force can be calculated using Newton's second law, which states that F = ma, where: F is the net force. m is the mass of the object. a is acceleration.

The velocity is constant, so the acceleration is 0.  Therefore, the net force is 0 N.

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Answer:

The net external force on the apple is 9.18 N and the direction of net force is 82.6°.

Explanation:

Given that,

Force of gravity = 9.11 N

Force of wind = 1.18 N

We need to calculate the net external force on the apple

Using formula of net force

[tex]F'=\sqrt{(9.11)^2+(1.18)^2+2\times1.18\times9.11\cos90}[/tex]

[tex]F'=9.18\ N[/tex]

We need to calculate the direction of net force

Using formula of direction

[tex]\theta=\tan^{-1}(\dfrac{9.11}{1.18})[/tex]

[tex]\theta=82.6^{\circ}[/tex]

Hence, The net external force on the apple is 9.18 N and the direction of net force is 82.6°.

The magnitude of the net external force on the apple is 9.19 N and the direction of the net external force is 82.6⁰.

The given parameters;

The magnitude of the net external force on the apple is calculated as follows;

[tex]F= \sqrt{F_y^2 + F_x^2} \\\\F= \sqrt{9.11^2 + 1.18^2} \\\\F = 9.19 \ N[/tex]

The direction of the net external force on the apple is calculated as follows;

[tex]\theta = tan^{-1}(\frac{F_y}{F_x} )\\\\\theta = tan^{-1}(\frac{9.11}{1.18} )\\\\\theta = 82.6 \ ^0[/tex]

Thus, the magnitude of the net external force on the apple is 9.19 N and the direction of the net external force is 82.6⁰.

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Answer:

A is the answer because if you multiply 8 and 2 the period of wave frequency is 16Hz long.

Explanation:

Answer:

B 0.125 its a simple conversion

Answer:

[tex]average power = 416.67 \: W

[/tex]

Explanation:

[tex]are \: you \: sure \: this \: is \: a \: man \: or \: robot?......haha. \\ the \: average \: power \: is \: given \: by : \\ p_{(a.v)} = \frac{w}{t} \: but \: work \: or \: energy \: expanded \: is \: given \: by : \\ w = \: fs = mgs \: \: therfore, \: p_{(a.v)} = \frac{mgs}{t} \\ note \: the \: followng : \\ p_{(a.v)} = average \: power, \\ w = work \: done \: or \: energy \: expanded, \\ f = force \: due \: to \: gravity \: = weight = mg, \\ s = distance = height = 2m \times 25 \: lifts, \: m = mass = 50kg, \\ \: g \: = \: acceleration \: due \: to \: gavity = 10 {m(s)}^{ - 2} and \: t = time = 60s.

\\ so \: what \: now, ok \: lets \: find \: p_{(a.v)} . \\ p_{(a.v)} = \frac{mgs}{t}= \frac{50 \times 10 \times 50}{60} = 416.66666667 \: watts.[/tex]

¡Hellow!

For this problem, lets recabe information:

v (Velocity) = 10 m/s

a (Aceleration) = 1 m/s²

t (Time) = 1/4 min = 25 s

d (Distance) = ?

v' (Final velocity) = ?

First, for calculate distance, lets applicate formula:

                                        [tex]\boxed{\boxed{\text{d = Vo * t + (a * t}^{2})\text{ * 0,5} } }[/tex]

Lets replace according we information and let's resolve it:

d = 10 m/s * 25 s + (1 m/s² * (25 s)²) * 0,5

d = 250 m + (625 m) * 0,5

d = 2,5 m + 312,5 m

d = 314 meters.

Now, for calculate final speed, lets applicate formula:

                                                 [tex]\boxed{\boxed{\text{v' = v + a * t} } }[/tex]

Lets replace according we information and let's resolve it:

v' = 10 m/s + 1 m/s² * 25 s

v' = 10 m/s + 25 m/s

v' = 35 m/s

¿Good Luck?

Att: That guy who use the "ñ".

Answer:

8 x 10^-12

Explanation:

Radius = 4 x 10^-3nm = 4 x 10^-12 m

by the formula,

                        diameter = 2 x radius

                        diameter = 2 x (4 x 10^-12)

                        diameter = 8 x 10^-12 m

Answer:

A. Schwann cells

Explanation:

Answer:

Explanation:

16=m(2)*2

16=m4

m=16÷4

m=4

Answer:

Technician A

Explanation:

Technician A is correct because, the hand force required is not supposed and even should not exceed 80 lb.

On the other hand, the foot force limit is even higher at 100 lb. Thus, the required foot force break should not exceed 100 lb. We are given 80 lb in the question, which is quite less than 100 lb. It could exceed 80, but must not exceed 100. Thus only Technician A is correct among them both.

Answer:

The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.

Explanation:

Sample Response: The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.

What did you include in your description? Check all that apply.

The object starts away from the origin.

The object moves toward the origin at a constant velocity.

The object stops for one second.

The object moves away from the origin at a greater constant velocity.

The circled vectors represent speed.

The is the ratio of distance traveled to time of motion. Speed is a scalar quantity because it has only only magnitude.

From the map, as the magnitude (size) of the green arrows changes, the size of the circled arrows changes accordingly.

Also, the direction of the circled arrow was constant for both top and bottom arrows.

Velocity changes with direction BUT speed does not change with direction, and has a complete meaning with only magnitude.

Thus, the circled vectors represent speed.

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Answer:

Mass = 1450kg

Explanation:

P = M * V (where p is momentum, m is mass and v is velocity)

29000 = 20 * M

M = 29000 / 20

M= 1450 kg

Answer:

S=5.83...

Explanation:

s=d/t

Speed=distance/time

s=35/10

s=5.83...

Answer:

To make the  lifting more efficient. It lets there be less taxing and saves a ton of energy!!

Explanation:

Answer:

b)72

Explanation

work done= force* distance

work done=40*1.8

72J