) Cars are parked in line as they come off the assembly lines. There are three models: red cars which take up 2 spaces, blue cars which also take up 2 spaces, and green cars which take up only 1 space. Let an be the number of ways of filling the first n parking spaces with red, blue and green cars.
Answer:
Hello your question has some missing information below is the complete question
answer :
[tex]a_{n} = a_{n-2} + a_{n-2} + a_{n-1}[/tex]
Step-by-step explanation:
Red car and Blue car take up 2 spaces each
Green cars take up 1 space
lets determine the number of ways of filling up the parking spaces
i) First lets assume the last space is filled by Green car then there will be [tex]n^{th}[/tex] space occupied hence there will be ( n - 1 ) spaces left to be filled in [tex]a_{n-1}[/tex] ways
ii) lets assume the last space is filled by either a Red car or a Blue car then there will be [tex]n^{th} + ( n -1 )^{st}[/tex] parking space occupied hence there will be
( n - 2 ) spaces left to be filled in [tex]a_{n-2}[/tex] ways
Hence A closed formula for [tex]a_{n}[/tex]
[tex]a_{n} = a_{n-2} + a_{n-2} + a_{n-1}[/tex]
where : a1 = 1 way , a2 = 3 ways
The 5 members of the math team at Nielsen Middle School are raising money to go to the
state competition. They need between $55 and $80 per person for each day of the trip. Which
of the following is a reasonable estimate of the total amount of money they will need for the
2-day trip?
Answer:
The answer is $700
Step-by-step explanation:
Brainliest plzz
What is the area of the school crossing sign represented below?
15 inches 15 inches
15 inches
15 inches
help me plsss
In a class of students, the following data table summarizes how many students have a cat or a dog. What is the probability that a student chosen randomly from the class has a cat or a dog?
Has a cat Does not have a cat
Has a dog 9 2
Does not have a dog 4 5
Answer:
0 students have a cat and 92 students have a dog
The probability that a student is chosen randomly from the class has a cat or a dog is 15/20.
What is the probability?Probability refers to a possibility that deals with the occurrence of random events. The probability of all the events occurring need to be 1.
The formula of probability is defined as the ratio of a number of favorable outcomes to the total number of outcomes.
P(E) = Number of favorable outcomes / total number of outcomes
The class has a cat and a dog = 9
Has a dog and does not have a cat = 2
Does not have a dog and has a cat = 4
Does not have dog and cat = 5
The total strength of the class is 20
The probability that a student is chosen randomly from the class has a cat or a dog = Number of favorable outcomes / total number of outcomes
P(E) = 15 /20
Hence, The probability that a student is chosen randomly from the class has a cat or a dog is 15/20.
Learn more about probability :
https://brainly.com/question/795909
In order to play on the 7th grade basketball team you must buy a team uniform. Last year a uniform cost $40, but this year a uniform cost $48. What is the percent of change?
Show your work here:
INCLUDE ANSWER AND TY
Answer:
20%
Step-by-step explanation:
The uniform cost $8 more than last year.
Last year was $40
Find what percent of 40 is 8.
8/0.4 = 20
the percent change is 20%
draw to show 5- 2 on the number line
Answer:
the image is there
Step-by-step explanation:
Calculus helpppppppppppppppp
Answer:
[tex]\displaystyle y' = \frac{5x^2 + 3}{3(1 + x^2)^\bigg{\frac{2}{3}}}[/tex]
General Formulas and Concepts:
Pre-Algebra
Equality PropertiesAlgebra I
FunctionsFunction NotationExponential Rule [Root Rewrite]: [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]Algebra II
Logarithms and Natural LogsLogarithmic Property [Multiplying]: [tex]\displaystyle log(ab) = log(a) + log(b)[/tex]Logarithmic Property [Exponential]: [tex]\displaystyle log(a^b) = b \cdot log(a)[/tex]Calculus
Derivatives
Derivative Notation
Derivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Logarithmic Derivative: [tex]\displaystyle \frac{d}{dx} [lnu] = \frac{u'}{u}[/tex]
Implicit Differentiation
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y = x\sqrt[3]{1 + x^2}[/tex]
Step 2: Rewrite
[Equality Property] ln both sides: [tex]\displaystyle lny = ln(x\sqrt[3]{1 + x^2})[/tex]Logarithmic Property [Multiplying]: [tex]\displaystyle lny = ln(x) + ln(\sqrt[3]{1 + x^2})[/tex]Exponential Rule [Root Rewrite]: [tex]\displaystyle lny = ln(x) + ln \bigg[ (1 + x^2)^\bigg{\frac{1}{3}} \bigg][/tex]Logarithmic Property [Exponential]: [tex]\displaystyle lny = ln(x) + \frac{1}{3}ln(1 + x^2)[/tex]Step 3: Differentiate
ln Derivative [Implicit Differentiation]: [tex]\displaystyle \frac{d}{dx}[lny] = \frac{d}{dx} \bigg[ ln(x) + \frac{1}{3}ln(1 + x^2) \bigg][/tex]Rewrite [Derivative Property - Addition]: [tex]\displaystyle \frac{d}{dx}[lny] = \frac{d}{dx}[ln(x)] + \frac{d}{dx} \bigg[ \frac{1}{3}ln(1 + x^2) \bigg][/tex]Rewrite [Derivative Property - Multiplied Constant]: [tex]\displaystyle \frac{d}{dx}[lny] = \frac{d}{dx}[ln(x)] + \frac{1}{3}\frac{d}{dx}[ln(1 + x^2)][/tex]ln Derivative [Chain Rule]: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{1}{3} \bigg( \frac{1}{1 + x^2} \bigg) \cdot \frac{d}{dx}[(1 + x^2)][/tex]Rewrite [Derivative Property - Addition]: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{1}{3} \bigg( \frac{1}{1 + x^2} \bigg) \cdot \bigg( \frac{d}{dx}[1] + \frac{d}{dx}[x^2] \bigg)[/tex]Basic Power Rule]: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{1}{3} \bigg( \frac{1}{1 + x^2} \bigg) \cdot (2x^{2 - 1})[/tex]Simplify: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{1}{3} \bigg( \frac{1}{1 + x^2} \bigg) \cdot 2x[/tex]Multiply: [tex]\displaystyle \frac{y'}{y} = \frac{1}{x} + \frac{2x}{3(1 + x^2)}[/tex][Multiplication Property of Equality] Isolate y': [tex]\displaystyle y' = y \bigg[ \frac{1}{x} + \frac{2x}{3(1 + x^2)} \bigg][/tex]Substitute in y: [tex]\displaystyle y' = x\sqrt[3]{1 + x^2} \bigg[ \frac{1}{x} + \frac{2x}{3(1 + x^2)} \bigg][/tex][Brackets] Add: [tex]\displaystyle y' = x\sqrt[3]{1 + x^2} \bigg[ \frac{5x^2 + 3}{3x(1 + x^2)} \bigg][/tex]Multiply: [tex]\displaystyle y' = \frac{(5x^2 + 3)\sqrt[3]{1 + x^2}}{3(1 + x^2)}[/tex]Simplify [Exponential Rule - Root Rewrite]: [tex]\displaystyle y' = \frac{5x^2 + 3}{3(1 + x^2)^\bigg{\frac{2}{3}}}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Implicit Differentiation
Book: College Calculus 10e
Answer choices
4 feet
5feet
6feet
8feet
Please help if you send a link I will report
Answer:
d
Step-by-step explanation:
only reasonable answer
Last month we had only five sunny days. There were 30 days in all last month.
What was the ratio of sunny days to the total number of days? What was the ratio
of sunny days to days that were not sunny?
Answer:
6
Step-by-step explanation:
30 ÷ 5 = 6
Answer:
6
Step-by-step explanation:
it is 6
I can't figure this out
9514 1404 393
Answer:
143 in²
Step-by-step explanation:
The figure is dimensioned in such a way that it can be divided easily into three rectangular areas. The top rectangle is 10 in wide and 7 in high. The vertical rectangle below that is 4 in wide and 12 in high, and the square appendage on the right is 5 in square.
Then the total area is the sum of products of length and width:
A = (10 in)(7 in) + (4 in)(12 in) + (5 in)(5 in) = (70 +48 +25) in²
A = 143 in²
The area of the irregular figure is 143 in².
#The extremities of the diagonal of a square are (1,1 )and (-2, -1).Obtain the two other vertices and the equation of a next diagonal.
#
find the area of the triangle with vertices(1,2),(2,3),and(4,5).what inference can you draw about the points from your upshot?
Answer:
(i) (-3/2, 3/2) and (1/2, - 3/2)
6x + 4y = - 3
(ii) Points are col linear
Step-by-step explanation:
Let the coordinates of the point(lower) be (a, b) and that of upper be (x, y).
Using mid point formula,
Mid point of diagonal(using the given points) is:
= ( (-2+1)/2 , (-1+1)/2) = (-½ , 0)
Using (a, b) and (x, y) :
= ( (a+x)/2 , (b+y)/2 ) = (-1/2, 0)
Which means, a+x= -1 & b + y = 0
Therefore, x = - 1 - a & b = - y
Using distance formula, diagonal = √(-2-1)² + (-1-1)² = √13
Knowing the relation in diagonal and side, side = diagonal/√2 = √13/√2 = √(13/2)
Again using distance formula, diagonal = √13
=> √(x - a)² + (y - b)² = √13
=> (-1-a -a)² + (-b - b)² = 13
=> a² + b² + a = 3 ... (1) [solved directly]
Length of side = √(13/2)
=> √(a-(-2))² + (b-(-1))² = √(13/2)
=> a² + b² + 4a + 2b = 3/2 ...(2)
On solving (1) and (2):
a = 1/2 or -3/2, but a lies in 4th quadrant so a > 0, thus, a = 1/2
b = -3/2 or 3/2, but b lies in 4th quadrant so b < 0, b = -3/2
Therefore,
x = - 1 - a = -1 - 1/2 = -3/2
y = - b = - (-3/2) = 3/2
Vertices are (x, y) = (-3/2, 3/2) and (a, b) = (1/2, -3/2)
Equation is just a relation in y and x, for a relation:
Subtract (1) from (2):
3a + 2b = -3/2 => 6a + 4b = - 3
By merely replacing a, b by x, y
6x + 4y = -3 is the required equation
(ii):
Ar. of ∆ = ½ | 1(3 - 5) + 2(5 - 2) + 4(2 - 3) |
Ar. of ∆ = ½ | -2 + 6 - 4 | = 0
As the area of the ∆ is 0, the given points don't form ∆, they are col linear.
please help answer questions 1 and 2!
Answer:
1:A
3:C
hope this help
Calculate the slope of a line that goes through points (3, 4) and (0, 0).
Question 5 options:
3/4
3
4
4/3
Answer:
4/3
Step-by-step explanation:
0-4/0-3
-4/0-3
-4/-3
4/3
Answer:
Step-by-step explanation:
3\4
plz, help. I need it...
Answer: (6, 3)
Step-by-step explanation:
Leanna opens a savings account with an initial balance of $100. She then deposits $50 each month. Use an equation, a table, and a graph to explain the relationship between the amount of money in the account, a, and the number of months since Leanna opened the account, m.
Part A Write an equation to represent the problem. Explain how the value of a changes as m increases.
Part B Make a table to show the relationship between m and a. Find 5 ordered pairs.
Part C Use your table from Part B to draw a graph to represent the situation.
Please answer all questions
See the attached picture:
what is the value of x in each figure
PLEASE DON'T GIVE ME A LINK
Answer:
x=43
Step-by-step explanation:
3x+17+x-9=180
4x+8=180
4x=180-8
4x=172
x=43
answer and show proof for branliest
Answer:
-2(4 - 1)
Step-by-step explanation:
Choice A: ❌
9-(-17)
9 + 17 = 26
Choice B: ❌
(4 - 16)/(-2)
(-12)/(-2)
6
Choice C: ✅
-2(4 - 1)
-2(3)
-6
Choice D: ❌
3 x (-2) x (-1)
-6 x (-1)
6
Answer:
- 2(4 - 1)
Step-by-step explanation:
9 - (- 17)
9 + 17 = 26
[tex]\frac{4 - 16}{-2}[/tex] = 12
- 2(4 - 1)
- 2(3) = - 6
3 × - 2 × - 1 = 6
PLEASE HELP 0ffering MAX POINTS
Answer:
Priya is correct
Step-by-step explanation:
Priya is right because of the plus sign. When its adding you should always subtract from both sides but when you have the subtraction side you have to add to both sides.
Answer:
I think he is right I got that it is priya
Step-by-step explanation:
A person invested $5,500 in an account growing at a rate allowing the money to double every 14 years. How long, to the nearest tenth of a year would it take for the value of the account to reach $6,800?
Answer:
t=4.3
Step-by-step explanation:
y=a(2)^{\frac{t}{d}}
y=a(2)
d
t
y=6800\hspace{40px}a=5500\hspace{40px}d=14
y=6800a=5500d=14
d is the doubling time
\text{Plug in:}
Plug in:
6800=
6800=
\,\,5500(2)^{\frac{t}{14}}
5500(2)
14
t
\text{Solve for }t\text{:}
Solve for t:
\frac{6800}{5500}=
5500
6800
=
\,\,\frac{5500(2)^{\frac{t}{14}}}{5500}
5500
5500(2)
14
t
Divide by 5500
1.23636364=
1.23636364=
\,\,2^{\frac{t}{14}}
2
14
t
\log(1.23636364)=
log(1.23636364)=
\,\,\log\left(2^{\color{green}{\frac{t}{14}}}\right)
log(2
14
t
)
Take the log of both sides
\log(1.23636364)=
log(1.23636364)=
\,\,\color{green}{\frac{t}{14}}\log(2)
14
t
log(2)
Bring exponent to the front
\frac{\log(1.23636364)}{\log(2)}=
log(2)
log(1.23636364)
=
\,\,\frac{t}{14}
14
t
Divide by log(2)
0.30610313=
0.30610313=
\,\,\frac{t}{14}
14
t
Divide in calculator
14(0.30610313)=
14(0.30610313)=
Multiply by 14
4.285443788=
4.285443788=
\,\,t
t
1 . What is the distance between the two points.
(0,5 1,3), (-0,4, -1,3) ?
2. What is the distance between the two points
(6, -3), (2, -4)
Please help will give brainliest
Answer:
angle a+angle b+angle c=180°
90°+38°+angle c=180°
128°+angle c=180°
angle c=180°-128°
angle c =52°
52°+n°=180°
n=180°-52
n=128°
In ABC, the measure of the largest angle is 16 less than 4 times the smallest angle. The measure of the middle angle is 7 more than half the measure of the largest angle. What is the measure of the middle angle?
Answer:
Step-by-step explanation:
Let A ≤ B ≤ C
largest angle is 16 less than 4 times the smallest angle
C = 4A-16
middle angle is 7 more than half the measure of the largest angle
B = C/2 + 7
A+B+C = 180°
A = 28 ⅐°
B = 55 2/7°
C = 96 4/7°
Please help will give brainliest
Answer:
A+B=180°(linear pair)
a+ 52°=180°
a=180°-52°
a=128° is your answer
what is 4 1/8 - 2 2/3 to the nearest whole number
Answer:
1 11/24
Step-by-step explanation:
:))
Need help if you have the time and i need explanation for this (NO LINKS PLS)
Answer:
ask ur question i will try to help
Step-by-step explanation:
P = 3. Q = -2. Solve 4PQ
Answer:
-24
Step-by-step explanation:
4(3)(-2) = -24
please help i have been stuck on this for 3 hours
Answer:
The one you selected is the correct one
Answer:
(5/7) x 56 = 40 is correct
Step-by-step explanation:
How have you been stuck on this for 3 hours
-2y + x +
3
How many terms are in the expression
Answer:3
Step-by-step explanation:
This angle cuts out 1/4 of the circle. Find the measure of the angle.
Answer:
90 degrees
Step-by-step explanation:
What is y/x = 8 proportional to?
Answer:
y is directly proportional to 8
while x is inversily proportional to 8