Can u tell answers of all the given questions? Plz
50 points + brainliest answer questions 7 and 8 with work and all
Answer:
7) m∠BHE = 146°
8) m∠BAC = 25°
Step-by-step explanation:
Question 7:Given that, [tex]\displaystyle\mathsf{\overline{CD}\:||\:\overline{EF}}[/tex], and that [tex]\displaystyle\mathsf{\overline{AB}}[/tex] is a transveral.
We are also provided with the following measures of the angles: m∠DGH = 2x, and m∠FHB = 5x - 51.
∠DGH and ∠FHB are also corresponding angles, as they have corresponding positions on the same side of the transversal, [tex]\displaystyle\mathsf{\overline{AB}}[/tex]. These two angles also have the same measure.
Solve for x:In order to find the measure of ∠BHE, we could set up an equality statement on ∠DGH and ∠FHB to solve for the value of x.
m∠DGH = m∠FHB
2x = 5x - 51
Add 51 and subtract 2x from both sides of the equation:
2x -2x + 51 = 5x - 2x - 51 + 51
51 = 3x
Divide both sides by 3:
[tex]\displaystyle\mathsf{\frac{51}{3}\:=\:\frac{3x}{3}}[/tex]
x = 17
⇒ m∠DGH = 2x = 2(17) = 34°,
⇒ m∠FHB = 5x - 51 = 5(17) - 51 = 34°.
Since ∠FHB and ∠BHE are supplements (whose sum add up to 180°), we could determine the measure of ∠BHE as follows:
m∠BHE + m∠FHB = 180°
m∠BHE + 34° = 180°
m∠BHE + 34°- 34° = 180°- 34°
m∠BHE = 146°.
Therefore, the measure of ∠BHE is 146°.
Question 8:Given that ΔABC with [tex]\displaystyle\mathsf{\overline{AC}}[/tex] extended to D, and that m∠ABC = 63° and m∠BCD = 92°:
The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the two nonadjacent interior angles. In other words: ∠BCD = ∠BAC + ∠ABC.
Before we could apply the Exterior Angle Theorem, we must first find m∠BAC. Since ∠BCD and ∠BCA are supplements:
m∠BCD + m∠BCA = 180°
92° + m∠BCA = 180°
92° - 92°+ m∠BCA = 180° - 92°
m∠BCA = 88°
Solve for m∠BAC:Now that we have the measure for ∠BCA, we can find m∠BAC by applying the Triangle Sum Theorem where it states that the sum of the interior angles of a triangle is equal to 180°.
m∠BCD + m∠ABC + m∠BAC = 180°
92° + 63° + m∠BAC = 180°
125° + m∠BAC = 180°
155° - 155° + m∠BAC = 180° - 155°
m∠BAC = 25°
Therefore, the measure of ∠BAC is 25°.
Compare the expressions 7+3^2-2⋅5 and (3/4+1/8)÷1/8 using , =, or . Show your work. Answer:
[tex]A=7+3^2 -2 \cdot 5 = 7 + 9 - 10 = 9-3=6\\\\\\B = \left(\dfrac 34 + \dfrac 18\right) \div \dfrac 18 = \dfrac 78 \times 8 =7\\\\\\B>A[/tex]
The expression relation is 7+3²-2⋅5 > (3/4+1/8)÷1/8.
What is Inequality?Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
Given:
First, 7+3²-2⋅5
Solving the above expression
= 7 + 9 -2.5
= 16 - 2.5
= 13.5
Second,
(3/4+1/8)÷1/8
= (6/8 + 1/8) ÷ 1/8
= 7/8 ÷ 1/8
= 7/8 x 8/1
= 7
Hence, 7+3²-2⋅5 > (3/4+1/8)÷1/8.
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which of the following are perfect cubes 1)3375 2)8000 3)6859
Answer:
all are perfect cubes
Step-by-step explanation:
you can just cube root the numbers and bom if it aint decimal its a perfect cube
(10 points!!!) AND I’LL GIVE YOU BRAINLIEST IF CORRECT
I ALREADY KNOW THE ANSWER I JUST WANT THE EXPLANATION!!
The answer is ( Jose, $901.31 more)
Janell deposits $2,000 and for 5 years leaves it in an account earning 3% annual interest, compounded quarterly. For 5 years, José saves and deposits $150 per quarter in an account earning 3% interest compounded quarterly. Who will have more money in the account after 5 years? How much more?
Use the table to answer:
Answer:
2%
Step-by-step explanation:
Cuantos triángulos se pueden construir con un número entero de palillos
Answer:
Step-by-step explanation:
After creating an equilateral triangle using 3 toothpicks, I require 3 more toothpicks to create more 3 equilateral triangles ie.4 triangles it toto.
First place 3 toothpicks end to end on a Horizontal plane to create an equilateral triangle.
THEN erect 3 toothpicks on each corner of the triangles making other ends joined up together in space above the Horizontal plane so as to create another same THREE equilateral triangles. (I am unable to provide a pictorial presentation due to inadequacy of signs & symbols on the keyboard. )
I suppose, you must have visualised the superstructure.
Thanks.
Pregnant women have the option of being scanned for Cystic Fibrosis risks in their unborn babies. If a mother or a father have a certain recessive gene, the baby is at risk for Cystic Fibrosis. Given the three events, which of the following statements is true? Select all that apply.
Event A: The mother or father carries the recessive gene.
Event B: The father carries the recessive gene.
Event C: The baby is at risk for Cystic Fibrosis.
Answer:
Pregnant women have the option of being scanned for Cystic Fibrosis risks in their unborn babies. If a mother or a father have a certain recessive gene, the baby is at risk for Cystic Fibrosis.
Given the three events, which of the following statements is true?
Select all that apply.
Event A: The mother or father carries the recessive gene.
Event B: The father carries the recessive gene.
Event C: The baby is at risk for Cystic Fibrosis.
Select all that apply:
Event A and Event B are mutually exclusive.
Event B and Event C are mutually exclusive.
Event A and Event C are not mutually exclusive.
Event A and Event C are mutually exclusive.
Event A and Event C are not mutually exclusive.
Remember that in general, A and B are mutually exclusive events if they cannot occur at the same time. This means that A and B do not share any outcomes and P(A AND B)=0.
In this question, note that if the mother or father carries the recessive gene for cystic fibrosis, the baby is at risk. So here, A and C are not mutually exclusive, and B and C are not mutually exclusive.
A and B are not mutually exclusive because they share an outcome: the father carrying the recessive gene.
Step-by-step explanation:
Flying against the wind, a jet travels 3780 miles in 6 hours. Flying with the wind, the same jet travels 5950miles in 7 hours. What is the rate of the jet in still air and what is the rate of the wind? 1111 Rate of the jet in still air:
The rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.
The given parameters;
distance traveled against the wind, d₁ = 3780 milestime of motion, t₁ = 6 hoursdistance traveled with wind, d₂ = 5950 milestime of motion, t₂ = 7 hoursLet the rate of the jet in still air = R₁
Let the rate of the wind = R₂
The rate of the jet against the wind:
[tex]R_1 - R_2 = \frac{3780}{6} \\\\R_1 - R_2 = 630[/tex]
The rate of the jet with the wind:
[tex]R_1 + R_2 = \frac{5950}{7} \\\\R_1 + R_2 = 850\\\\[/tex]
The rate of the jet in still air is calculated as follows;
[tex]R_1 = \frac{630 + 850}{2} \\\\R_1 = 740 \ mph[/tex]
The rate of the wind is calculated as follows;
[tex]R_1 - R_2 = 630\\\\R_2 = R_1 - 630\\\\R_2 = 740 - 630 \\\\R_2 = 110 \ mph[/tex]
Thus, the rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.
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15 points plz answer soon
Answer:
P(ΔTRP) = 36 m
Hope this helps!
Evaluate the algebraic expression if w= -0.5, x = 2, y= -3, and z = 2.5.
2w^2 - 3x + y - 8z
Answer:
-28.50
Step-by-step explanation:
Given the algebraic expression, 2w² - 3x + y - 8z, where w = -0.5, x = 2, y= -3, and z = 2.5:
Substitute the given values for the variables to evaluate the algebraic expression.
2w² - 3x + y - 8z
= 2(-0.5)² - 3(2) + (-3) - 8(2.5)
= 2(0.25) - 6 - 3 - 20
= 0.50 - 6 - 3 - 20
= -28.50
Therefore, 2w² - 3x + y - 8z = -28.50.
Answer:
-28.5
Step-by-step explanation:
Substitute the values for their given variables and evaluate.
[tex]2w^2-3x+y-8z\\\\2(-0.5)^2-3(2)+(-3)-8(2.5)\\\\2(0.25)-6-3-20\\\\0.5-6-3-20\\\\-28.5[/tex]
Draw a square and its diaginals
Answer:
you cant draw......................
Step-by-step explanation:
HELP ME PLEASE!!!!!!!!!!!
Answer:
SAS theorem >This is the correct
Answer:
SSS theoremStep-by-step explanation:
[tex] \huge\colorbox{pink}{hope \: its \: help}[/tex]
pls help, what is the slope of the graph?
well, let's take 2 points from it and get it :) , say let's use (4 , 5) and (-1 , 5)
[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{(4)}}}\implies \cfrac{0}{-5}\implies 0[/tex]
bearing in mind that for any horizonal line it's always 0.
What is the equation of a line that passes through the points (3, 6) and (8, 4)?
Answer:
[tex]y=-\frac{2}{5} x+\frac{36}{5}[/tex]
Step-by-step explanation:
→ Find the gradient
[tex]\frac{4-6}{8-3}= \frac{-2}{5} =-\frac{2}{5}[/tex]
→ Write into y = mx + c format
[tex]y=-\frac{2}{5} x+c[/tex]
→ Substitute in ( 3 , 6 )
[tex]6 = -\frac{6}{5} +c[/tex] ∴ [tex]c = 6+\frac{6}{5} =\frac{36}{5}[/tex]
→ Rewrite into y = mx + c format
[tex]y=-\frac{2}{5} x+\frac{36}{5}[/tex]
least common denominator of both 4/x^2*t and x/t^2
Step-by-step explanation:
LCD of 4/x²t and x/t²
= LCM(x²t , t²)
= x²t²
Form an equation to help you solve this problem Four identical lumps of gold on one side of some scales balance with one identical lump and a 22kg mass. Find the mass of one lump of gold. kg
Answer:
equation= 4x=x+22kg
Step-by-step explanation:
i hope it helped :))
What is the scale factor for the dilation of triangle ABC
to produce triangle A'B'C'?
A. 0.25
B. 0.5
C. 2
D. 3
What is the scale factor for the dilation of triangle ABC
to produce triangle A"B"C?
A. 0.25
B. 0.5
C. 2
D. 3
Answer:
1) B 0.5
2) C 2
Step-by-step explanation:
point A (-2, 2) (0.5) = (-1, 1) A'
point B (-2, -1) (0.5) = (-1, -0.5) B'
point C (3, -1) (0.5) = (1.5, -0.5) B'
point A (-2, 2) (2) = (-4, 4) A'
point B (-2, -1) (2) = (-4, -2) B'
point C (3, -1) (2) = (6, -2) B'
PLS HELP REWARDING A LOT!!
Answer:
157°
Step-by-step explanation:
Sum of interior angles of polygon
(n-2)*180 ---- n = total number of sides
7 angles, 7 sides
5*180 = 900
final angle will be
900-162-115-125-138-105-98
=157
Answer:
157
Step-by-step explanation:
it is obvious that it's a heptagon
so (n-2) x180
n=7
(7-2) x 180 =900
900-162-115-125-138-105-98
900-743=157
final unknown=157°
Select all of the following that are quadratic equations. 7x2 + 14x = 0 x3 - 3x2 + 1 = 0 5x - 7 = 0 x2 + 3x -5 = 0 x - 5 = 9x + 7 x2 - x = 3x + 7
Answer:
7x2 + 14x = 0
x2 + 3x -5 = 0
x2 - x = 3x + 7
Step-by-step explanation:
A quadratic equation has the highest power of x to the second power. It must have x to the second power
7x2 + 14x = 0 quadratic
x3 - 3x2 + 1 = 0 not quadratic but cubic
5x - 7 = 0 not quadratic but linear
x2 + 3x -5 = 0 quadratic
x - 5 = 9x + 7 not quadratic but linear
x2 - x = 3x + 7 quadratic
1.)Which of the following is a linear inequality in two variables?
a. 3x≤16
b. 3m-4m>5
c. 9q+4<12
d. 11+2t ≥ 3?
[tex] \large╚»★«╝ { \mathcal{Answer }}╚»★«╝[/tex]
The Correct option among them is B
[tex] \sf3m - 4n > 5[/tex]_____________________________________
The other options have one variable each, but according to the given question there should be two variables in the inequality.
The only choice satisfying the conditions is Option B
having two variables in it ( that is "m" and "n" )
[tex] ꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
Determine whether each situation represents a discrete or continuous function.
a. The function y = 30.48x converts length from x feet to y centimeters. [ A. discrete , B. continuous ]
b. The function y = 3x + 2 represents the amount of water y in gallons in a tank after x minutes.
[ A. discrete ,B. continuous ]
Answer:
Both of those are continuous
Step-by-step explanation:
A discrete function is only defined for a specified countable set of x, neither of the two provided fit that description. On the other hand, both are defined for arbitrary positive real numbers.
The value of both functions is defined for a continuous interval of x thus both will be continuous.
What is a function?A certain kind of relationship called a function binds inputs to essentially one output.
The nature of the relationship defines the function for example y = sinx and y = x +6 like that.
Given the first function →
y = 30.48x where x is feet and y is a centimeter of conversion.
Now, it is known that for every foot interval there will be a centimeter that exists therefore they will be defined for all continuous intervals of x so it will be continuous.
The second function →
y = 3x + 2 where x is minutes and y is the number of gallons in a tank.
Now since for every minute of the interval, there will be a certain amount of gallons in the tank so it will be also continuous.
Hence "The value of both functions is defined for a continuous interval of x thus both will be continuous".
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Answer:
Its C (Third Multiple Choice Answer)
Step-by-step explanation:
The reason being that x + 1 / 2 (6x - 4) = 6 is the way it is instead of the first step being x + 6x / 2 - 4 / 2 = 6 is because it is using legal manipulation by multiplying the 1 / 2 out.
Math:
First
2 * (x + 1 / 2 (6x - 4) = 6 * 2 [In this case the x gets multiplied by 2 and multiplies 2 to the other side as well. The reason why it isn't a Distributive Property in the first place is because we are using multiplication only and the equation is not 1 / 2 (6x - 4).
Then
2x + 6x - 4 = 12 will then equal to 8x - 4 = 12 which is adding like terms
Thirdly
(+ 4) + 8x - 4 = 12 (+ 4) [The parenthesis is to identify that the 4 is positive]
will then turn into 8x = 16
Finally
By dividing 8 on both sides of the previous equation
8x / 8 = 16 / 8 equaling x = 2.
The height of a parallelogram is 6[tex]a^{2}[/tex][tex]b^{5}[/tex] and the base of a parallelogram is 4[tex]a^{3}[/tex][tex]b^{4}[/tex] Find the area of the parallelogram using the formula A = bh
[tex]\text{Area of parallelogram} = \text{Base}~ \times~\text{Height} = (4a^3b^4)(6a^2 b^5)=24a^5 b^9[/tex]
On two investments totaling $14,000, Peter lost 4% on one and earned 6% on the other. If his net annual receipts were $312, how much was each investment?
Answer:
5280 , 8720
Step-by-step explanation:
suppose the one is x, another is y
x+y=14000
y(6%)-x(4%)=312
x=5280
y=8720
net annual receipt means the income so you have to substract the lost from the gains
URGENT: HELP ME WITH THE MATH PROBLEMS!!
(Note This Needs To Be Done Tonight!)
Answer:
1. 3 and 1/5 improper: 11/15
2. 3 and 3/4 improper: 15/16
3. 1 and 2/3 improper: 5/6
4. 2 and 1/2 improper: 5/6
5. 3 and 2/10 improper: 32/40
6. 3 and 3/9 improper: 30/36
7. 1 and 2/6 improper: 8/12
The mass of Earth is approximately 6 x 10^27 that of the Sun is 330,000 times as much. The gravitational constant is 6.7 x 10^-8 cm/s2.g. The distance of Earth from the Sun is about 1.5 x 10^12 cm. Compute, approximately, the work necessary to increase the distance of Earth from the Sun by 1 cm.
Answer:
12.89
Step-by-step explanation:
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Help !!!!!!!!!!!!!!!!!!!!
Answer:
Step-by-step explanation:
One must rearrange the function to decreasing value of exponents
f(x) = -7x⁴ + 8x³ - 3x² - 9x + 11
to see that it is a 4th degree polynomial with leading coefficient of -7
you have to estimate
Answer:
75,388
Step-by-step explanation:
Long Multiplication form
[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]
[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]
[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]
[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex] [tex]=75,388[/tex]
See Image for the addition:
What is the solution set for this inequality?
- 6x + 30 < -18
0x<-2
0x<&
Ox>-2
Ox>8
Answer:
x>8
Step-by-step explanation:
[tex]- 6x+ 30 < - 18 \\ - 6x < - 18 - 30 \\ - 6x < - 48 \\ \frac{ - 6x}{ - 6} < \frac{ - 48}{ - 6} \\ x > 8[/tex]
(2³ x 2⁵) ÷ 2⁸
Solution
Answer:
it is 1
Step-by-step explanation:
Let's use PEMDAS (do the parenthesis first).
2 to the 3 = 2x2x2 = 8
2 to the 5 = 2x2x2x2x2 = 32
8 x 32 = 256 (all the solutions are factors of 2048).
2 to the 8 = 2x2x2x2x2x2x2x2 = 256 again
256 / 256 = 1