2,9,23,51,107
Determine the next terms of sequence

Answer:

x-intercept: (-4,0)

y-intercept:(0,-2)

Step-by-step explanation:

Answer:

Blue dots are correct

Step-by-step explanation:

I took quiz

Answer:

thank you

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

add all together equals 522

522/10 = 52.2

The mean absolute deviation of the data set of 15.2

Mean absolute deviation (MAD) of a data set is the average distance between each data value and the mean.

Mean absolute deviation is a way to describe variation in a data set. Mean absolute deviation helps us get a sense of how "spread out" the values in a data set are.

Given is a data set, we need to find the mean absolute deviation for the group,

So,

The mean = 38+45+76+93+50+54+29+44+62+31 / 10

= 522/10 = 52.2

Now finding the absolute deviation =

|52.2-38| = 14.2

|52.2-45| = 7.2

|52.2-76| = 23.8

|52.2-93| = 40.8

|52.2-50| = 2.2

|52.2-54| = 1.8

|52.2-29| = 23.2

|52.2-44| = 8.2

|52.2-62| = 9.8

|52.2-31| = 21.2

The mean absolute deviation = 14.2 + 7.2 + 23.8 + 40.8 + 2.2 + 1.8 + 23.2 + 8.2 + 9.8 + 21.2 / 10

= 152.4 / 10

= 15.24

≈ 15.2

Hence, the mean absolute deviation of the data set of 15.2

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Answer:

10000^3

Step-by-step explanation:

Answer:

7 groups or teams

Step-by-step explanation:

7 x 4 is 28, as close as we can get to 29.

Answer:

3.26 x 102

Step-by-step explanation:

10 squared is 100

3.26 x 100 = 326 because you move the decimal to the right 2 spots

Answer:

The probability that an employee is not married and has between 1 and 5 absences in the past year is 0.204.

Step-by-step explanation:

The probability of an event, say E is the ratio of the favorable number of outcomes to the total number of outcomes.

[tex]P(E)=\frac{n (E)}{N}[/tex]

The number of absences during the past year tabulated by marital status is as follows:

Marital Status      0 Absences     1 - 5 Absences     More than 5 Absences

  Married                     100                     98                              52

Not Married                  77                     102                              71

Compute the probability that an employee is not married and has between 1 and 5 absences in the past year as follows:

[tex]P(\text{NM}\cap 1-5\ \text{Absences})=\frac{n(\text{NM}\cap 1-5\ \text{Absences})}{N}[/tex]

                                       [tex]=\frac{102}{100+98+52+77+102+71}\\\\=\frac{102}{500}\\\\=0.204[/tex]

Thus, the probability that an employee is not married and has between 1 and 5 absences in the past year is 0.204.

[tex]x^2 + 4x + (\frac{4}{2})^2 = x^2 + 4x + 4[/tex]

Answer is 4

Answer:

Minimum height is 7.25ft and maximum height is 7.75ft

Step-by-step explanation:

You measured to the nearest half foot, so the greatest possible error is 0.25 foot.

Minimum height= measured value-possible error= 7.5-0.25= 7.25ft

Maximum height= measured value+possible error= 7.5+0.25= 7.75ft

Answer:

The speed of the aircraft is 126.667 miles per hour.

Step-by-step explanation:

Let suppose that aircraft travels at constant speed. From Mechanical Physics, we understand speed as travelled distance divided by time. In this case, the absolute speed of the aircraft is the sum of wind speed and speed of the aircraft relative to wind. That is:

Tailwind (Wind flows in the same direction of aircraft)

[tex]t = \frac{s_{T}}{v_{W,T}+v_{A/W,T}}[/tex] (Eq. 1)

Headwind (Wind flow in the direction opposite to aircraft)

[tex]t = \frac{s_{H}}{v_{W,H}+v_{A/W,H}}[/tex] (Eq. 2)

Where:

[tex]s_{T}[/tex], [tex]s_{H}[/tex] - Travelled distances on tailwind and headwind conditions, measured in meters.

[tex]v_{W,T}[/tex], [tex]v_{W,H}[/tex] - Tailwind and headwind speeds, measured in meters per second.

[tex]v_{A/W,T}[/tex], [tex]v_{A/W,H}[/tex] - Relative speeds of aircraft relative to tailwind and headwind, measured in meters per second.

We proceed to equalize both expressions to eliminate time:

[tex]\frac{s_{T}}{v_{W,T}+v_{A/W,T}} = \frac{s_{H}}{v_{W,H}+v_{A/W,H}}[/tex] (Eq. 3)

If we know that [tex]s_{T} = 360\,mi[/tex], [tex]s_{H} = 300\,mi[/tex], [tex]v_{W,T} = 10\,\frac{mi}{h}[/tex], [tex]v_{W,H} = -10\,\frac{mi}{h}[/tex] and [tex]v_{A/W,T} = v_{A/W,H}[/tex], then:

[tex]\frac{360}{v+10} = \frac{300}{v-10}[/tex]

The relative speed of the aircraft is now cleared:

[tex]360\cdot (v-10)=300\cdot (v+10)[/tex]

[tex]360\cdot v-3600 = 300\cdot v +3000[/tex]

[tex]60\cdot v = 7600[/tex]

[tex]v = 126.667\,\frac{mi}{h}[/tex]

The speed of the aircraft is 126.667 miles per hour.

Answer:

16

Step-by-step explanation:

the amount of peppers are double the amount of servings, 8x2 = 16

Answer:

16

Step-by-step explanation:

8-4/ 4-2= 2

8 x 2= 16

Answer:

The constant of proportionality is the ratio between two directly proportional quantities. ... Two quantities are directly proportional when they increase and decrease at the same rate.

Step-by-step explanation:

Answer:for a is (x,y) = (1, -5)

B is (x,y) ∈∅

And lastly is c is (x, y) = ( x , 1 - 7x), x∈

Step-by-step explanation:

for a is (x,y) = (1, -5)

B is (x,y) ∈∅

And lastly is c is (x, y) = ( x , 1 - 7x), x∈

9514 1404 393

Answer:

  (9, 54)

Step-by-step explanation:

The first road has a slope of 6 on its graph. So, the perpendicular road will have a slope of -1/6, the negative reciprocal of the slope of the original road. Translating that from y=-1/6x the the right by 333 units, the equation of the second road is ...

  y = -1/6(x -333)

The point where Alice turned is the point of intersection of these two equations:

Substituting for y, we have ...

  6x = -1/6(x -333)

  36x = -x +333 . . . . . multiply by 6, eliminate parentheses

  37x = 333 . . . . . . . .  add x

  x = 9 . . . . . . .  divide by 37

So, the point where Alice turned is ...

  (x, y) = (9, 6·9)

  (x, y) = (9, 54)

Answer:

y = 3x + 1 I think........

Answer:

C. -8x-104=6x-14

Step-by-step explanation:

–8(x + 13) = 2(x – 7) + 4x

-8x-104=2x-14+4x

-8x-104=6x-14

im sorry but i dont really understand your question :c

Answer:

0.6

Step-by-step explanation:

5:3

x:1

3x=5

x=0.6

The requried volume of the pyramid is 64.9 cubic meters.

Volume is defined as the mass of the object per unit density while for geometry it is calculated as profile area multiplied by the length at which that profile is extruded.

The first step is to find the area of the square base. Since the perimeter of the base is 15.4, each side of the square has a length of:

15.4 / 4 = 3.85

Therefore, the area of the base is:

A = (3.85)² = 14.8225 square meters

The volume of a pyramid is given by the formula:

V = (1/3) * A * h

where A is the area of the base and h is the height of the pyramid. Substituting the values given in the problem, we get:

V = (1/3) * 14.8225 * 13.1

V = 64.91925 cubic meters

Rounding to the nearest tenth of a cubic meter, we get:

V ≈ 64.9 cubic meters

Therefore, the volume of the pyramid is approximately 64.9 cubic meters.

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Answer:

If im not wrong the answer is 23,613.

Step-by-step explanation:

9,854+3,905=13,759+9,854=23,613.

Answer:

5.6

Step-by-step explanation:

Step 1:

7/10 = z/8       Equation

Step 2:

10z = 56      Multiply

Step 3:

z = 56 ÷ 10     Divide

Answer:

z = 5.6

Hope This Helps :)

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[tex]f(x) = - 3 {x}^{4} - 2 {x}^{3} + 3 {x}^{2} [/tex]

[tex]g(x) = 3 {x}^{4} - 4 {x}^{3} + {x}^{2} [/tex]

[tex]f(x) + g(x) = - 3 {x}^{4} - 2 {x}^{3} + 3 {x}^{2} + 3 {x}^{4} - 4 {x}^{3} + {x}^{2} \\ [/tex]

[tex]f(x) + g(x) = - 3 {x}^{4} + 3 {x}^{4} - 2 {x}^{3} - 4 {x}^{3} + 3 {x}^{2} + {x}^{2} \\ [/tex]

[tex]f(x) + g(x) = - 6 {x}^{3} + 4 {x}^{2} \\ [/tex]

Done....

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Answer:

_

1-+\|13

x= -------- or x1= - + 0.434259, x2=0

6

Step-by-step explanation:

1. collect terms

2. factor the expression

3. divide both sides

4. separate into possible cases

5. solve the equation

6.Equation has 3 solution

Answer:

im not sure but I think is c

Her final exam will be her 6th exam. To determine the her final exam  score we can use this equation:

Mean = All scores/6

70 = (58 + 73 + 85 + 83 + 79 + x )/6  ⇒ x stands for the final exam mark

70 = 378 + x /6   ⇒ Multiple both sides by 6 to cancel it out

420 = 378 + x   ⇒ Subtract 378 from both sides to isolate x

420 - 378 = x

42 = x

Therefore, she must get at least 42% on her final to maintain a 70% average.

Answer:

0.484

Step-by-step explanation:

Given that:

Alice defeats Carol 50% of the time.

This implies that, the probability of defeating Carol = 0.5

Also the probability of losing to Carol = 1 - 0.5 = 0.5

Similarly, Alice defeats Betty 40% of the time.

The probability of Alice defeating Betty = 0.4 and the  probability of losing to Betty = 1 - 0.4 = 0.6

However, in as much as Alice needs to win two consecutive games, the sequence which satisfies this condition are as follows:

Let W represent Win and L represent L.

Then the conditions are WWW, WWL and LWW

Since the outcome of each game is independent of the other games.

Then, the probability that Alice wins two games against Carol CBC is:

Pr(2W - CBC) = (0.5 × 0.4 × 0.5) + ( 0.5 × 0.4 × 0.5) + ( 0.5 × 0.4 × 0.5)

Pr(2W - CBC) = 0.1 + 0.1 + 0.1

Pr(2W - CBC) = 0.3

The probability that Alice wins two games against Betty (BCB) is:

Pr(2W - BCB) = (0.4 × 0.5 × 0.4) + (0.6 × 0.5 × 0.4) + ( 0.4 × 0.5 × 0.6)

Pr(2W - BCB) =  0.08 + 0.12 + 0.12

Pr(2W - BCB) = 0.32

However, the Probability of winning two consecutive games is the result of the addition of the probability of winning two consecutive games in the sequence CBC together with the probability of winning two consecutive games in the sequence of BCB.

i.e.

Pr(2W) = Pr(2W- CBC) + Pr(2W - BCB)

Pr(2W) = 0.3+0.32

Pr(2W) = 0.62

Finally, to calculate the probability that Alice will get $100 if she chooses the sequence CBC is:

[tex]\dfrac{Pr(2W -CBC)}{Pr(2W)}= \dfrac{0.3}{0.62}[/tex]

[tex]\mathbf{\dfrac{Pr(2W -CBC)}{Pr(2W)}= 0.484}[/tex]