2(3−8y)= i need help someone

Answer:

Option (3)

Step-by-step explanation:

From the figure attached,

Area of the shaded region = Area of circle - (Area of the ΔOAB + Area of ΔOED)

Area of the circle = πr²

                             = π(5)²

                             = 25π cm²

Area of ΔOAB = 2(Area of ΔOCB)

AB = 6 cm

OC = 5 - 1 = 4 cm

By applying Pythagoras theorem in ΔOCB,

OB² = OC² + BC²

5² = 4² + BC²

BC² = 25 - 16

BC = √9 = 3 cm

Area of ΔOCB = [tex]\frac{1}{2}(OC)(BC)[/tex]

                        = [tex]\frac{1}{2}(4)(3)[/tex]

                        = 6 cm²

Area of ΔAOB = 2(6) = 12 cm²

Area of ΔAOB = Area of ΔDOE = 12 cm²

Area of shaded region = 25π - (12 + 12)

                                      = (25π - 24) cm²

Therefore, Option (3) will be the answer.

Answer:

1/8

Step-by-step explanation:

The second option is the answer

Answer:

The resulting function is [tex]f(x+1) = x^3 + 4x^2 + 3x + 1[/tex]

Step-by-step explanation:

Suppose we have a function f(x). If we want to shift the function 1 unit to the left, we find f(x+1).

In this question, we have:

[tex]f(x) = x^3 + x^2 - 2x + 1[/tex]

Shifting 1 unit to the left:

[tex]f(x+1) = (x+1)^3 + (x+1)^2 - 2(x+1) + 1[/tex]

[tex]f(x+1) = (x^3 + 3x^2 + 3x + 1) + (x^2 + 2x + 1) - 2x - 2 + 1[/tex]

[tex]f(x+1) = x^3 + (3+1)x^2 + (3+2-2)x + 1 + 1 - 2 + 1[/tex]

[tex]f(x+1) = x^3 + 4x^2 + 3x + 1[/tex]

The resulting function is [tex]f(x+1) = x^3 + 4x^2 + 3x + 1[/tex]

Answer:

what?????????????????

Answer:

Answer. The numbers are 4 and 5. Their sum = 25 + 16 = 41.

Answer:a

Step-by-step explanation:trust me bro

The domain is the set of all x-coordinates and

the range is the set of all y-coordinates.

So the domain for this relation is {0, 1, 2, 3, 4}

and the range is {0, -1, -4, -9, -16}.

Now, I graph these points below.

For the relation tobe a function, it must pass the vertical line test.

If we can draw a vertical line that passes through only one point

anywhere on the graph, the relation is a function.

Notice that if you were to draw a vertical line,

no line would intersect two points on the same line.

Answer:

35+14=7(5+2) , so you have the alternative way of computing the sum.

49=7(7)

Answer:

35+14=7(5+2)

Step-by-step explanation:

Answer:

187

Step-by-step explanation:

Answer:

y=-5x-1

Step-by-step explanation:

If parallel lines, then the slope is the same.

y=-5x+b

To solve for b, plug in (-1,4)

(4)=-5(-1)+b

4=5+b

-1=b **Subtract 5 from both sides**

y=-5x-1

Answer: 63

Step-by-step explanation:

Add the two numbers you have then subtract from 180 because a triangle is 180 degrees

Answer:

5.3 is the amswer! Hope u pass

Answer:

Step-by-step explanation:

Given:

LP = 27

LM = NP

MN = 3

16). LP = LM + MN + NP

      27 = LM + 3 + LM

      27 = 3 + 2(LM)

      LM = 12

17). Since, LM = NP

      NP = 12

18). Since, MP = MN + NP

     MP = 3 + 12

     MP = 15

19). NL = LM + MN

     NL = 12 + 3

     NL = 15

Answer:

august 1st

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

16/1 -3/1 = 16-3

= 13answer is unknow no.

Answer:

Step-by-step explanation:

Answer:

x = 3

equation: 6x - 6 = 12

Step-by-step explanation:

6x - 6 = 12

aka:

6x + -6 = 12

+6. +6

6x = 18

/6. /6

x = 3

check: 6(3) - 6 = 12

18 - 6 = 12

12 = 12

Answer:

364.08 Feet

Step-by-step explanation:

Answer:

Step-by-step explanation:

the yard will have the area is A= L*W

A=24.6*14.8=364.08 ft^2

Answer:

Step-by-step explanation:

[tex]\frac{6}{\sqrt{2} - \sqrt{3} } * \frac{\sqrt{2} + \sqrt{3} }{\sqrt{2} + \sqrt{3} }[/tex]

[tex]\frac{6\sqrt{2} + 6\sqrt{3} }{2-3}[/tex]

[tex]-6(\sqrt{2} + \sqrt{3} )[/tex]

The fraction after rationalizing the denominator is given by the equation

A = -6 ( √2 + √3 )

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.

Given data ,

Let the fraction be represented as A

Now , the value of A is

A = 6 / ( √2 - √ 3 )   be equation (1)

Now , on simplifying the equation , we get

To rationalize the denominator of the fraction ,

Multiply the denominator by its conjugate ,

So , the conjugate of ( √2 - √ 3 ) = ( √2 + √ 3 )

Multiplying the numerator and denominator of the fraction by ( √2 + √ 3 )

A x ( √2 + √ 3 ) / ( √2 + √ 3 )

Substituting the values in the equation , we get

[ 6 / ( √2 - √ 3 ) ] x ( √2 + √ 3 ) / ( √2 + √ 3 )

On simplifying the equation , we get

6 ( √2 + √ 3 ) / ( 2² - 3² )

So , the value of A is A = 6 ( √2 + √ 3 ) / ( -1 )

A = -6 ( √2 + √ 3 )

Therefore , the value of A is A = -6 ( √2 + √ 3 )

Hence , the equation A = -6 ( √2 + √ 3 )

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9514 1404 393

Answer:

  (a)  y = 1/2x + 2

Step-by-step explanation:

The only equation that matches the first table entry is ...

  y = 1/2x +2

  3 = (1/2)(2) +2 . . . . first table entry

Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}} : [/tex]

[tex] \underline{ \underline{ \text{To \: find}}} : [/tex]

[tex] \underline{ \underline{ \text{Using \: pythagoras \: theorem}}} : [/tex]

[tex] \boxed{ \sf{ {Hypotenuse}^{2} = {Perpendicular}^{2} + {Base}^{2} }}[/tex]

⤑ [tex] \sf{ Perpendicular = \sqrt{ {(Hypotenuse)}^{2} - {(Base)}^{2} } }[/tex]

⤑ [tex] \sf{ \sqrt{ {(10)}^{2} - {(8)}^{2} } }[/tex]

⤑ [tex] \sf{ \sqrt{100 - 64}} [/tex]

⤑ [tex] \sf{ \sqrt{36}} [/tex]

⤑ [tex] \boxed{ \sf{6\: units}}[/tex]

[tex] \pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline { \tt{6 \: units}}}}}}}[/tex]

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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Answer:

19

Step-by-step explanation:

Sub the x with 6

30 - 11 = 19

Answer:

11x+21

Step-by-step explanation:

blue square= x squared

green square=3x

pink square=7x

orange square=21

=

11x+21

Answer:

16.67

Step-by-step explanation:

12 is what percent of 72? = 16.67

Answer:

exactly. 16.67

is the answer its process is simple suppose x

Answer:

Ur final grade will go down if you are looking for answers buddy! :)

Step-by-step explanation:

a) The average for a student with the given scores is 76.3 (rounded to one decimal place).

b) The average for a student with the given scores, but with a score of only 17 on attendance, is 74.4 (rounded to one decimal place).

Here, we have,

To calculate the average for the given scores, taking into account the different weights of each component, we can use the following steps:

(a) Average with the given scores:

To calculate the average with the given scores, we multiply each score by its respective weight, then sum up the results.

Here's the calculation:

Average = (Attendance * 0.03) + (First Paper * 0.06) + (Second Paper * 0.06) + (Test 1 * 0.19) + (Test 2 * 0.19) + (Test 3 * 0.19) + (Final Exam * 0.28)

Substituting the given scores:

Average = (81 * 0.03) + (62 * 0.06) + (86 * 0.06) + (78 * 0.19) + (68 * 0.19) + (68 * 0.19) + (87 * 0.28)

Average = 2.43 + 3.72 + 5.16 + 14.82 + 12.92 + 12.92 + 24.36

Average = 76.33

Therefore, the average for a student with the given scores is 76.3 (rounded to one decimal place).

(b) Average with a score of 17 on attendance:

Using the same calculation method as above, substituting the attendance score:

Average = (17 * 0.03) + (62 * 0.06) + (86 * 0.06) + (78 * 0.19) + (68 * 0.19) + (68 * 0.19) + (87 * 0.28)

Average = 0.51 + 3.72 + 5.16 + 14.82 + 12.92 + 12.92 + 24.36

Average = 74.41

Therefore, the average for a student with the given scores, but with a score of only 17 on attendance, is 74.4 (rounded to one decimal place).

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Answer:

85

Step-by-step explanation:

Answer: 220:4 or 220 to 4

Step-by-step explanation:

Answer:220:4

Step-by-step explanation: