(21.) A writer earns $3400 a month. Last month she spent $204 on food.
What percent of her income was spent on food?

Answers

Answer 1
6 percent was spent
Answer 2

Answer: 6%

Step-by-step explanation:

3400's x%=204

(3400)x/100=204

34x=204

34x/34=204/34

I used my calculator to divide

x=6

So  6%


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Find the roots of h(t) = (139kt)^2 − 69t + 80
the smaller root is:
the larger root is:

The answers will consist of algebraic expressions containing the parameter k.

What positive value of k will result in exactly one real root?
K = ?

Answers

Answer:

The positive value of [tex]k[/tex] will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let [tex]h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80[/tex], roots are those values of [tex]t[/tex] so that [tex]h(t) = 0[/tex]. That is:

[tex]19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0[/tex] (1)

Roots are determined analytically by the Quadratic Formula:

[tex]t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}[/tex]

[tex]t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }[/tex]

The smaller root is [tex]t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }[/tex], and the larger root is [tex]t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }[/tex].

[tex]h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80[/tex] has one real root when [tex]\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0[/tex]. Then, we solve the discriminant for [tex]k[/tex]:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Answers

Answer:

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Step-by-step explanation:

// Solve equation [2] for the variable  y  

 

 [2]    y = 2x - 8

// Plug this in for variable  y  in equation [1]

  [1]    (2x-8) + x = 4

  [1]    3x = 12

// Solve equation [1] for the variable  x  

  [1]    3x = 12  

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// Use the  x  value to solve for  y  

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^^ the person above had the same answer as me! have a good day!

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Answers

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