Solution :
It is given that a large institution is preparing food menus which contains foods A as well as B.
Each lunch provides :
10 units of carbohydrates
6 units of fats
7 units of proteins
The food from A cost = $0.12 per ounce
And food from B cost = $0.08 per ounce
Objective function :
[tex]$C= 0.12x+0.08y$[/tex]
Constraints : [tex]$x\geq 0, y \geq 0, x+y \geq 6, 2x+y \geq 10, x+y \leq 7$[/tex]
Domain : [tex]$3 \leq x\leq 7$[/tex]
Range : [tex]$0\leq y\leq4$[/tex]
Guys help I’m failing math this assignment is 100 points it will boost my grade I’m timed..
Answer:
edf
Step-by-step explanation:
PLEASE HELP 25 POINTS
The topographic map shows the location of a park ranger at Point X when a message is received that an injured hiker needs help at Point Z.
Which answer correctly identifies the elevations of both points on the map?
Point X= 1500m, Point Z= 2000m
Point X= 1550m, Point Z= 1600m
Point X= 1600m, Point Z= 2050m
Point X= 2050m, Point Z= 1600m
Answer:Point X= 1600m, Point Z= 2050m
Step-by-step explanation:
) Cars are parked in line as they come off the assembly lines. There are three models: red cars which take up 2 spaces, blue cars which also take up 2 spaces, and green cars which take up only 1 space. Let an be the number of ways of filling the first n parking spaces with red, blue and green cars.
Answer:
Hello your question has some missing information below is the complete question
answer :
[tex]a_{n} = a_{n-2} + a_{n-2} + a_{n-1}[/tex]
Step-by-step explanation:
Red car and Blue car take up 2 spaces each
Green cars take up 1 space
lets determine the number of ways of filling up the parking spaces
i) First lets assume the last space is filled by Green car then there will be [tex]n^{th}[/tex] space occupied hence there will be ( n - 1 ) spaces left to be filled in [tex]a_{n-1}[/tex] ways
ii) lets assume the last space is filled by either a Red car or a Blue car then there will be [tex]n^{th} + ( n -1 )^{st}[/tex] parking space occupied hence there will be
( n - 2 ) spaces left to be filled in [tex]a_{n-2}[/tex] ways
Hence A closed formula for [tex]a_{n}[/tex]
[tex]a_{n} = a_{n-2} + a_{n-2} + a_{n-1}[/tex]
where : a1 = 1 way , a2 = 3 ways
Paisley is going to invest $28,000 and leave it in an account for 14 years. Assuming the interest is compounded monthly, what interest rate, to the nearest tenth of a percent, would be required in order for Paisley to end up with $74,000?
Answer:
r=7
Step-by-step explanation:
74000=28000(1+r/12)^12(14)
divide 74000 by 28000, and cancel out 28000.
1.00580=1+r/12
(100) .06962=r
r = 6.96198
the 6 after the 9 rounds 9 to 0, which rounds the 6 to 7
r=7