1.045cm and a height of 30.48cm what is the volume of the cylinder

Answers

Answer 1

Answer:

104.57

Explanation:

V = πr^2h

-3.14, 1.045^2, and 30.48=104.567666431


Related Questions

When particles get close to the surface, they interact with atoms in
the
(Finish the sentence)

Answers

Is there anything else in the page I think it’s missing a part

a. What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren?
b. What frequency does she receive after the ambulance has passed?

Answers

Answer:

A)828.8Hz

B)869.2Hz

Explanation:

Here is a complete question;

What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren? Speed of sound is 345m/s

b. What frequency does she receive after the ambulance has passed?

Vs= speed of the ambulance

, We convert to m/s for unit consistency

= 115 km/h= 115km× 1000m/1m × 1hr/3600s= 31.94m/s

Dopler effect is when observed frequency of wave changes with respect to the source or when observed moves relative to transmitting medium can be expressed as

f'=[ (v + vo)/(v- vs)]*f

=[ (v )/(v- vs)]*f

The sign vo and vs depends on vthe direction of the velocity

f= frequency of ambulance siren= 753Hz

v= speed of sound in air= 345m/s

Vo= speed of observer= 0

A) we are to determine the f' of ambulance as heard by person as ambulance approaching.

To find the frequency f' observed by the person we use the expresion below

Then substitute the values

f'=[ (v )/(v- vs)]*f

=[ (345)/(345-31.94)]×753

= 828.8Hz

B)What frequency does she receive after the ambulance has passed?

To find the frequency f' observed by the person we use the expresion below

Then substitute the values

f'=[ (v )/(v + vs)]*f

=[ (345)/(345 + 31.94)]×753

= 869.2Hz

=

A racecar accelerates from rest at 6.5 m/s2 for 4.1 s. How fast will it be going at the end of that time?

Answers

Answer:

The final velocity of the car is 26.65 m/s.

Explanation:

Given;

acceleration of the racecar, a = 6.5 m/s²

initial velocity of the car, u = 0

time of motion, t = 4.1 s

The final velocity of the car is given by;

v = u + at

where;

v is the final velocity of the car

suvstitute the givens

v = 0 + (6.5)(4.1)

v = 26.65 m/s.

Therefore, the final velocity of the car is 26.65 m/s.

If the particles were moving with a speed much less than c, the magnitude of the momentum of the second particle would be twice that of the first. However, what is the ratio of the magnitudes of momentum for these relativistic particles?

Answers

Answer:

p₂ / p₁ = 2 (v₁ / v₂)

Explanation:

The moment is a very useful concept, since it is one of the quantities that is conserved during shocks and explosions, for which it had to be redefined to be consistent with special relativity,

         p = m v / √[1+ (v/c)² ]

for the case of speeds much lower than the speed of light this expression is close to

         p = m v

 

In this exercise they indicate that the moment of the second particle is twice the moment of the first, when their velocities are small

        p₂ = 2 p₁

       p₂/p₁ = 2

in consecuense

       m v₂ = 2 m v₁

       v₂ = 2 v₁

consider particles of equal mass.

By the time their speeds increase they enter the relativistic regime

        p₂ = mv₂ /√(1 + v₂² /c²)

        p₁ = m v₁ /√(1 + v₁² / c²)

let's look for the relationship between these two moments

       p₂ / p₁ = mv₂ / mv₁   [√ (1+ v₁² / c²) /√ (1 + v₂² / c²)

       

from the initial statement

      p₂ / p₁ = 2 √(c² + v₁²) / (c² + v₂²)

we take c from the root

      p₂ / p₁ = 2 √ [(1+ v₁²) / (1 + v₂²)]

this is the exact result, to have an approximate shape suppose that the velocities are much greater than 1

      p₂ / p₁ = 2 √ [v₁² / v₂²] = 2 √ [(v₁ / v₂)²]

      p₂ / p₁ = 2 (v₁ / v₂)

we see the value of the moment depends on the speed of the particles

Answer as soon as possible

Answers

Answer:

the velocity of the acorn

Explanation:

just do in in real life and see

Answer:

it is probably the velocity of the acorn

When the current through a circular loop is 6.0 A, the magnetic field at its center is 2.0 * 10-4 T. What is the radius of the loop?

Answers

Answer:

ill get back to this question once i get the answer

The radius of the loop is 13 cm

To find the radius of the loop, the values are given as,

Current I = 6A

Magnetic field, B = 2* 10⁻⁴ T

How to find the radius of the loop?

     The magnetic field in a circular loop will have same magnitude and direction. The current carrying loops will be formed due to the magnetic field and there will be n times of loops adds up for every turns.

Formula for magnetic field in the circular loop is,

                   B = µ₀ I 2R Tesla

Here, we have to find the radius of the loop,

                    R = B / µ₀ I × 2

µ₀ = 4π × 10-7 H/m.

Substituting all the values in the equation,

                   R = ( 2 × 10⁻⁴ ) / ( 4π × 10-7 × 6 × 2)

                      = ( 2 × 10⁻⁴ ) / ( 0.0000150796)

    Radius, R  = 13 cm

Thus, the radius of the loop is 13 cm.

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How should the magnetic field lines be drawn for the magnets shown below?​

Answers

Answer:

Magnetic field lines can be drawn by moving a small compass from point to point around a magnet. At each point, draw a short line in the direction of the compass needle.When opposite poles of two magnets are brought together, the magnetic field lines join together and become denser between the poles.

Explanation:

A 4.5 kg puffer fish expands to 40% of its mass by taking in water. When the puffer fish is threatened, it releases the water toward the threat to move quickly forward. What is the ratio of the speed of the puffer fish forward to the speed of the expelled water backwards?

Answers

Answer:

2:5

Explanation:

We have the initial mass of the fish = 4.5kg

The mass of water intake = 40%of 4.5kg

= 0.40x4.5kg

= 1.8kg

The formula for conserving momentum

M1V1 = M2V2

M1 = mass of the puffer fish = 4.5kg

M2 = mass of the applied water = 1.8kg

V1 = velocity of the puffer fish

V2 = velocity of water

We are then to find v1/v2

V1/V2 = M2/M1

V1/V2 = 1.8/4.5

= 1/2.5

This is also 2/5

Therefore we have the ratio to be 2:5

Heidi (39 kg) is walking her tiny chihuahua, Chaxi (5.60 kg), on the sidewalk. To encourage Chaxi along, Heidi pulls forward with a force of 9.55 N. Identify the correct reaction force in response to Heidi’s action force.

a. The friction is less than 660 N since the beam can be moved at a constant velocity.
b. There is no friction acting on the beam since it is accelerating.
c. The friction is equal to 660 N since the beam is not accelerating.
d. The friction is greater than 660 N since the beam is not in equilibrium.

Answers

Answer:

The correct reaction force in response to Heidi's action force is:

c. The friction is equal to 660 N since the beam is not accelerating.

Explanation:

Heidi's action force does not affect the beam.  Since friction resists the sliding or rolling of one solid object over another, there is no friction acting on the beam, in this respect.  The reaction force is what makes the dog to move because it acts on it.  According to Newton's Third Law of Motion, forces always come in action-reaction pairs.  This Third Law states that for every action force, there is an equal and opposite reaction force.  This means that the dog exerts some force on Heidi, as he pulls it "forward with a force of 9.55 N."

Power is the rate at which work is done true or false

Answers

Answer:

false

Explanation:

PLS HELP WILL GIVE BRAINLIST
what is the rate at which an object moves towards a target in

A speed B Arc C force D trajectory

Answers

Answer: The rate at which an object moves towards a target is Speed

Explanation:

Rate is something that tells us amount of solmething that changes in one unit of time.

Speed is defined as the measure of the rate of movement of a body expressed either as the distance travelled divided by the time taken.

Arc is defined as the apparent path described above and below the horizon taken up by a celestial body.

Force is defined as a push or pull upon an object resulting from the object's interaction with another object.

Trajectory is defined as the path followed by an object moving under the action of given force.

An object of mass 3.00 kg, moving with an initial velocity of 5.05 m/s, collides with and sticks to an object of mass 2.76 kg with an initial velocity of -3.66 m/s. Find the final velocity of the composite object.

Answers

Answer:

0.752 m/s

Explanation:

m1 = 3.00kg

u1 = 5.05m/s

m2 = 2.76kg

u2 = -3.66m/s

According to the law of conservation of momentum,

m1u1 + m2u2 = (m1+m2)v

3(5.05) + 2.76(-3.66) = (5.05+2.76)v

15.15 - 9.2736 = 7.81v

5.8764 = 7.81v

v = 5.8764/7.81

v = 0.752m/s

answer plese lang po​

Answers

Answer:

hi

Explanation:

how to convert gumbauan baboy to kung burger p

How much work is done by the gravitational force on the block?

Answers

Answer:

Work = Mass * Gravity * Height and is measured in Joules. Imagine you find a 2 -Kg book on the floor and lift it 0.75 meters and put it on a table. Remember, that “force” is simply a push or a pull. If you lift 100 kg of mass 1-meter, you will have done 980 Joules of work.

Explanation:

he gravitational force between two objects of masses m1m1m_1 and m2m2m_2 that are separated by distance rrr is

Answers

Answer:

[tex]F = \frac{6.67408m_1 m_2}{10^{11}r^2}[/tex]

Explanation:

Given

[tex]Object_1 = m_1[/tex]

[tex]Object_2 = m_2[/tex]

[tex]Distance = r[/tex]

Required

Determine the force of attraction

This is calculated as:

[tex]F = \frac{GMm}{d^2}[/tex]

Where

M = mass of object 1

m = mass of object 2

d = distance

Where G = gravitational constant

[tex]G = 6.67408 * 10^{-11}\ m^3 kg^{-1} s^{-2}[/tex]

Substitute these values in

[tex]F = \frac{GMm}{d^2}[/tex]

[tex]F = \frac{6.67408 * 10^{-11} * m_1 * m_2}{r^2}[/tex]

[tex]F = \frac{6.67408 * m_1 * m_2* 10^{-11}}{r^2}[/tex]

[tex]F = \frac{6.67408m_1 m_2* 10^{-11}}{r^2}[/tex]

[tex]F = \frac{6.67408m_1 m_2}{10^{11}*r^2}[/tex]

[tex]F = \frac{6.67408m_1 m_2}{10^{11}r^2}[/tex]

The 600-N ball shown is suspended on a string AB and rests against the frictionless vertical wall. The string makes an angle of 30° with the wall. The line AB goes through the center of the ball, and the contact point with the wall is at the same vertical height as the center of the ball. The ball presses against the wall with a force of magnitude:

Answers

Answer: T = 692.82 and 346.4 N

Explanation:

Given that;

w = 600 N

∅ = 30°

ΣFy = ma

a = 0 m/s²

ΣF = T(cos30°) - W = 0

T(cos30°) = W

we Divide both sides by cos30°

T = W / cos30o

T= 600N / cos30°

T = 692.82

and ∑fx

F = T sin∅

F = 692.82 × (sin30°)

F = 346.4 N

The equilibrium condition allows finding the result for the force of the ball against the wall is:

The force of the ball directed towards the wall is 346.4 N

Newton's second law gives a relationship between force, mass and acceleration of bodies. In the case where the acceleration is zero, it is called the equilibrium condition.

            ∑ F = 0

A free-body diagram is a diagram of the forces without the details of the bodies. In the attached we have a free-body diagram of the system.

Let's use trigonometry to break down stress.

          sin 30 = [tex]\frac{T_x}{T}[/tex]  

          cos 30 = [tex]\frac{T_y}{T}[/tex]  

          T_y = T cos 30

          Tₓ = T sin 30

Let's write the equilibrium condition for the system.

y-axis.

         T_y -W = 0

          T cos 30 = W

          [tex]T = \frac{W}{cos 30}[/tex]  

x-axis.

        R - Tₓ = 0

        R = T sin 30

 

We substitute

        [tex]R = \frac{W}{cos 30} \ sin 30 \\R = W \ tan 30[/tex]

Let's calculate.

        R = 600 tan 30

        R = 346.4 N

This force is directed from the wall towards the ball, by Newton's third law the force of the ball is of equal magnitude and opposite direction, that is, directed towards the wall.

In conclusion with the equilibrium condition we can find the result for the force of the ball against the wall is:

The force of the ball directed towards the wall is 346.4 N

Learn more about the equilibrium condition here: brainly.com/question/18117041

Suppose you put an ice cube into a cup of hot tea. In what direction does energy in the form of heat flow? What happens to the ice cube as this flow of energy occurs?

Answers

Answer:

The energy flows between the ice and the tea equally. The table below shows the temperatures of several different objects made of the same material.

What type of meter would be connected on both sides of a resistor in a circuit?

Answers

Type of meter would be connected on both sides of a resistor in a circuit is a a voltmeter , which measures potential difference .

What is a voltmeter ?

A voltmeter is an instrument used for measuring the potential difference , or voltage between two points in an electrical circuit .

A voltmeter is always attached in a series combination and an ammeter (which measures current in a circuit ) always attached in parallel combination with the circuit.

Since , in question it is given that a meter would be connected on both sides of a resistor in a circuit that means it must be a series combination

hence , correct answer is B) a voltmeter , which measures potential difference .

learn more about voltmeter

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True or False when an object speeds up it gains momentum

Answers

Yes ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Answer: True

Explanation:

A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. How far away is the cliff? The speed of sound in air a ordinary temperature is 343 m/s.

Answers

Answer:

480.2 m

Explanation:

The following data were obtained from the question:

Speed of sound (v) = 343 m/s.

Time (t) = 2.8 s

Distance (x) of the cliff =?

The distance of the cliff from the woman can be obtained as follow:

v = 2x /t

343 = 2x /2.8

Cross multiply

2x = 343 × 2.8

2x = 960.4

Divide both side by the coefficient of x i.e 2

x = 960.4/2

x = 480.2 m

Therefore, the cliff is 480.2 m away from the woman.

The distance should be 480.2 m

The calculation is as follows:

Since A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. And, there is the velocity of 343 m/s

[tex]v = 2x \div t\\\\343 = 2x \div 2.8\\\\2x = 343 \times 2.8[/tex]

2x = 960.4

x = 480.2 m

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What is the similarity between relative dating and radioactive dating? I will mark brainlest. I dont know how btw

Answers

Answer:

relative dating and radioactive dating are two methods in archeaology to determine the age of fossils and rocks

Explanation:

the act of or study of fossils is important for the determination of the kind of organism it represents how the organism lived and how it was preserved on the Earth’s surface over the past 4600000000 years

5.
An 80 newton force and a 45 newton force act on an object
as shown below.
80 N
30°
4S N
Which of the following vectors would bets represent an
equilibrant when added to this system?
(1) 24 N to the left (3) 24 N to the right
(2) 114 N to the right (4) 45 N to the left
Tirant Showroiculations

Answers

Answer:

the answer is a time your welcome

Answer:

(1)

Explanation:

A copper collar is to fit tightly about a steel shaft whose diameter is 6.0000 cm at 19°C. The inside diameter of the copper collar at that temperature is 5.9800 cm. To what temperature must the copper collar be raised so that it will just slip on the steel shaft, assuming the temperature of both the steel shaft and copper collar are raised simultaneously?

Answers

Answer:

T' = 865.15 °C

Explanation:

In order for the copper collar to just slip on the steel shaft the, assuming are heated simultaneously, we must find the final parameters of both and equate them. Because the final diameters of both must be same for the slipping to occur.

FOR COPPER COLLAR:

dc' = dc(1 + ∝c*ΔT)

where,

dc' = final diameter of copper ring

dc = initial diameter of copper ring = 5.98 cm

∝c = coefficient of linear expansion for copper = 16 x 10⁻⁶ °C⁻¹

ΔT = Change in Temperature

Therefore,

dc' = (5.98 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT]   ------------- equation (1)

FOR STEEL SHAFT:

ds' = ds(1 + ∝s*ΔT)

where,

ds' = final diameter of steel shaft

ds = initial diameter of steel shaft = 6 cm

∝s = coefficient of linear expansion for steel = 12 x 10⁻⁶ °C⁻¹

ΔT = Change in Temperature

Therefore,

dc' = (6 cm)[1 + (12 x 10⁻⁶ °C⁻¹)ΔT]   ------------- equation (2)

Comparing equation (1) and equation (2):

(5.98 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT] = (6 cm)[1 + (12 x 10⁻⁶ °C⁻¹)ΔT]

(5.98 cm/6 cm)[1 + (16 x 10⁻⁶ °C⁻¹)ΔT] = [1 + (12 x 10⁻⁶ °C⁻¹)ΔT]

0.9967 + (1.59 x 10⁻⁵ °C⁻¹)ΔT = 1 + (12 x 10⁻⁶ °C⁻¹)ΔT

1 - 0.9967 = [(15.9 -12) x 10⁻⁶ °C⁻¹]ΔT

0.0033/3.9 x 10⁻⁶ °C⁻¹ = ΔT

ΔT = 846.15 °C

but,

ΔT = T' - T = T' - 19°C = 846.15°C

T' = 846.15 °C + 19 °C

T' = 865.15 °C

2) What does the specific heat capacity of a material tell you about how easy it is to heat up
that material

Answers

Answer:

High specific heat -> takes more energy to raise/lower object's temperature

Low specific heat -> takes less energy to raise/lower object's temperature

Explanation:

The specific heat capacity is the amount of heat required to raise the temperature of something per unit of mass.

A high specific heat value for an object means it takes more energy to raise or lower that object's temperature. A low specific heat value for an object means it does not take very much energy to heat or cool that object.

A bug crawls 2.25 m along the base of a wall. Upon reaching a corner, the bugs direction of travel changes from south to west. THe bug that crawls 3.15 m before stopping. What is the magnitude of the bugs displacment?A) 5.40 m.B) 2.72m.C) 3.45 m.D) 3.87 in.E) 4.29 m.

Answers

Answer:

The magnitude of the bugs displacement is 3.87 m

Explanation:

An illustrative diagram for the scenario is given in the attachment below.

In the diagram, the bug's displacement is given by x. The diagram shows a right angle triangle with x as the hypotenuse. We can determine x from the Pythagorean theorem which states that " the square of the hypotenuse equals sum of squares of the other two sides". That is

x² = 2.25² + 3.15²

x² = 5.0625 + 9.9225

x² = 14.985

x = √14.985

x = 3.87 m

Hence, the magnitude of the bugs displacement is 3.87 m.

plzzzzzzzzzzzzzzzzzzzzzzzzzz help 20 points

Answers

Answer:

1.23

Explanation:

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➩ 1.23 feet

[tex]{\underline{\purple{\textsf{\textbf{Explanation : }}}}}[/tex]

Given :

Simon cuts a pipe that was 4.92 feet long Then he cuts it into four equal pieces.

To find :

What is the length of the each piece.

Solution :

As it is told that it's divided into four equal pieces

Therefore,

We must divide it by 4 to get the length of each piece.

So,

[tex] \sf \to \: \frac{4.92}{4} \\ \sf \to \: 1.23 \: feet \: ans.[/tex]

Can someone please answer how to convert mass into weight?

Answers

Answer:

To find the weight of something, simply multiply its mass by the value of the local gravitational field, and you get a result in newtons (N). For example, if your mass is 50 kg (about 110 pounds), then your weight is (50) (9.8). The point that must be overwhelmingly emphasized is that weight is a force.

Explanation:

A falling stone takes delta t = 0.32s to travel past a window 2.2m Tall. From what height above the top of the window did the stone fall?

Answers

Answer:

The height above the top of the window is 1.44 m

Explanation:

Given;

time of motion, t = 0.32 s

height traveled at the given time, h = 2.2m

determine the initial velocity of the stone;

h = ut + ¹/₂gt²

2.2 = u(0.32) + ¹/₂ x 9.8 x 0.32²

2.2 = 0.32u + 0.502

0.32u = 2.2 - 0.502

0.32u = 1.698

u = 1.698 / 0.32

u = 5.31 m/s

This initial velocity on top of the window becomes the final velocity from the height above the window.

v² = u² + 2gh

where;

u is the initial velocity of the stone from the height above the window;

5.31² = 0 + (2 x 9.8)h

19.6h = 28.196

h = 28.196/19.6

h = 1.44 m

Therefore, the height above the top of the window is 1.44 m

What is the magnitude of the change in potential energy of the block-spring system when it travels from its lowest vertical position to its highest vertical position?

Answers

Answer:

 ΔU = 2 mg h

Explanation:

In a spring mass system the potential energy is U = m g h

where h is measured from the equilibrium point of the spring

the potential energy at the highest point is

         U₁ = m g h

the potential energy at the lowest point is

         U₂ = m g (-h)

instead in this energy it is

          ΔU = 2 mg h

In this two points the kinetic energy is zero, but there is elastic potential energy that has the same value in the two points, so its change is zero

Potential energy is defined as the energy stored in a body which may convert into kinetic energy when moved.

The Formule of the potential energy is [tex]mgh[/tex] The correct answer is 0

Hence, [tex]U = 2 mg h[/tex]

 The H stated as the measured from the equilibrium point of the spring

Therefore, the potential energy at the maximum point is  [tex]U_1 = m g h[/tex]  and the potential energy at the minimum point is    [tex]U_2 = m g (-h)[/tex]

Hence, after solving it we got

         [tex]U_1 -U_2 = 2 mg h[/tex]

Therefore, the energy change in the process is 0.

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A 3520 kg truck moving north makes an INELASTIC collision with an 1480 kg car moving 13.0 m/s east. After colliding, they have a velocity of 9.80 m/s at 66.9 degrees. What was the initial velocity of the truck? (m/s)

Answers

Answer:

v = 12.8 m/s

Explanation:

Assuming no external forces acting during the collision, total momentum must be conserved.Since momentum is a vector, their components must be conserved too.Choosing a pair of axes coincident with the N-S and W-E directions, naming x to the W-E axis and y to the N-S one, we can write the following algebraic equations:      

       [tex]p_{ox} = p_{fx} (1)[/tex]

       [tex]p_{oy} = p_{fy} (2)[/tex]

Since we know all the information needed to solve (1), assuming a completely inelastic collision, we can focus in (2), writing both sides of the equation as follows:

       [tex]p_{oy} = m_{t} * v_{ot} = 3520 kg* v_{ot} (3)[/tex]

       [tex]p_{fy} = m_{f} * v_{fy} = 5000 kg* 9.8 m/s * sin 66.9 = 45080 kg*m/s (4)[/tex]

Since (4) and  (3) are equal each other, we can solve for vot, as follows:

       [tex]v_{ot} =\frac{45080kg*m/s}{3520kg} = 12.8 m/s (5)[/tex]

Other Questions
Meteorites are of three kinds: stones, irons, and stony irons. Eachcorresponds to a different part of planet formation. The stones resemblepieces of planetary crust and mantle, the irons the planet cores, and thestony irons the transitional area between core and mantle. In some stonyirons, translucent crystalline structures interpenetrate with opaque mantlerock Collectors sometimes cut stony irons into thin slices and illuminatethem from one side for a gorgeous stained glass effect. Only one per centof all meteorites are stony irons. Five per cent are irons, and the remainingninety-four per cent are stones. The main function of the paragraph is to:identify the three kinds of meteorites and provide information about each kind,describe the chemical structure of the different types of rock found within themeteorites classified as stonesexplain why some meteorites contain both crystalline structures and opaque mantlerocklist common ways collectors display pieces of meteorites. Which of the following expresses a cause of the increased specialization of labor?A. Economic power of monasteriesB. Beginning of a cash economyC. Greater role of banks in lendingD. Growth of towns and cities As a Gothic writer, Hawthorne choose subjects similar to those chosen by Poe and Melville. What is common in the writing of all three writers?He writes of obsession that brings about doom.He writes of the dark side of humanity.He writes of the loss of beautiful women.He writes about the pure innocence of nature. Which is an example of codominance Which number line correctly shows 3 1.5? I have a quastion who needs help reading. well heres a app !!! call reading eggs hope this helpss Triangle P'Q'R is the image of PQR under a transformation 80% of the 55 coffee mugs at Kari's Pancake House are dirty. How many dirty coffee mugs are there at the pancake house? 4x/3+3=x-2 value of x ? When passing, _____ only when you can see the tires of the vehicle you passed in your rearview mirror. A. return to your lane B. move into the next lane C. flash your headlights D. honk your horn Dillon pays x dollars to get a haircut. He gives the stylist a20% tip. The expression representing his total cost is x +0.2x.Which expression is equivalent and why?O A. (0.2) because the cost of the haircut can be factored out.B. 1.02x because adding 20% to the cost of the haircut is the sameas multiplying the cost by 1.02.C. 1.2x because adding 20% to the cost of the haircut is the same asmultiplying the cost by 1.2.D. 1.2x because adding $20 to the haircut is the same as multiplyingthe cost by 1.2. River deltas are? 1, caused by the movement of tectonic plates. 2, areas of infertile, rock soil. 3, formed by erosion. 4, created by seafloor spreading. A 45.0 mL solution of 0.0450 M hydroxylamine is extracted with 125 mL of solvent. The distribution constant for the reaction is 5.00 and the pKa of the protonated form of hydroxylamine is 5.960. Calculate the concentration of hydroxylamine remaining in the aqueous phase at pH=4.50 and pH=6.50 . Easy Chemistry/ Help The formula for the volume of a tetrahedron is given as v=sh. Rewrite theequation so that the height is a function of the area of base and the volume (solve forthe height), then find the height when the area of base is 8 and the volume is 48. i accidentally drank to much coffee and i can't sleep why is that?! In 1980 the social security tax was 5.83% up to a maximum of 25,900 if Nina earned $34,200 in 1989,how much did she pay in social security taxes? Identify the hypotenuse.A. MNB. LN What is the meaning of the metaphor, He is a walking dictionary? This chapter begins with a bold claim: Anthropologists study human beingswherever and whenever they find them. Yet there are limits to when and whereanthropologists can carry out their work. Can you think of any? How might your consideration of these limits affect how you would design an anthropological study?