By using Specific heat capacity, 741.76 x [tex]10^4[/tex]heat energy is needed to raise the temperature.
The amount of heat required to increase the temperature of 1 gram of a substance by 1 degree Celsius (°C) is known as the specific heat capacity.
The importance of specific heat capacity may be summed up as the quantity of energy needed to heat or cool an item of a given mass by a certain amount.
Given:
Mass of vat, mvat = 20kg
Mass of water, mwater = 3kg
ΔT = 90 – 10 = 80℃
Specific heat capacity of iron, Ciron = 450J/kg
Specific heat capacity of water, Cwater = 4186J/kg
To find:
Heat energy required, Q = ?
Formula:
C = Q / (m ΔT)
Calculations:
Q = mCΔT
Q = Qempty + Qwater
Q = (20 x 450 x 80) + (3 x 4186 x 80)
Q = 172.464 x [tex]10^4[/tex]J
Result:
Heat energy required is 172.464 x [tex]10^4[/tex]J
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If a ball is thrown straight upward with an initial velocity of 30.0 m/s, how
much time does it table to reach its maximum height?
(A) 1.0 s
(B)1.4 s
(C)1.5 s
(D) 3.0 s
The time taken by the ball to reach the maximum height when ball is thrown straight upward is t = 1.5s.
Equation :To find the time we must know the distance so to calculate the distance using formula,
v² = u² + 2 as
where,
v is final velocity
u is initial velocity
a is acceleration due to gravity
s is distance
As, we can see,
u = v = 30m/s
a = - 9.8 m/s²
s = ?
So, putting the values we get,
30²m/s = 30²m/s + 2 (9.8 m/s²) s
s = 30²m/s / 30²m/s + 2 (-9.8 m/s²)
s = 19.6
Now after getting to know the distance we can use the formula,
s = d/t
Where,
s is speed
d is distance
t is time
So, putting the values,
t = 30 / 19.6
t = 1.5s
Hence, the time taken by the ball to reach the maximum height is 1.5s.
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A 232g ball hangs on the end of a spring. When the spring is pulled down it oscillates with a period of .13s. When pull down too far to a point .56m below the equilibrium position, the ball flies off the spring when it reaches its equilibrium position, and flies into the air.
Find the spring constant
Find the height the ball reaches.
The spring constant is 542 N/m.
The height the ball reaches is 37.5 m.
Angular speed of the ball
The angular speed of the ball is calculated as follows;
ω = 2π/T
ω = (2π) / (0.13)
ω = 48.33 rad/s
Spring constantThe spring constant is calculated as follows;
ω = √(k/m)
ω² = k/m
ω²m = k
(48.33² x 0.232) = k
542 N/m
Linear speed of ballv = ωL
v = 48.33 x 0.56 m
v = 27.1 m/s
Height reached by the ballh = v²/2g
h = (27.1²) / (2 x 9.8)
h = 37.5 m
Thus, the spring constant is 542 N/m.
The height the ball reaches is 37.5 m.
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Can you please help me with this!?
To determine how classroom temperature affected test performance of students an experiment was conducted with each group of students in hot room, cold room and a room with normal temperature.
• Dependent variable- Test performance
• Independent variable- Room temperature
• Control variables/Constants - Group of students
• Control group – Students in the room with normal temperature
Test performance depends on the temperature of the room.
Room temperature is an independent variable that does not depend on any factor
Students were the constants in the experiment
Among the students, students in normal temperature room is the control group as they were placed just to check the correctness of the experiment.
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A fighter hits a punching bag and brings it from rest up to a speed of 40 m/s in 0.08 s. What is the force of impact on the punching bag if its mass is 100 kg?
if a fighter hits a punching bag and brings it from rest up to a speed of 40 m/s in 0.08 s, Then the force of impact on the punching bag if its mass is 100 kg would be 50000 Newtons,
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The impact of the force on the punching bag = momentum/time
=100×40 / 0.08
=5000 Newtons
Thus, the force of impact on the punching bag would be 50000 Newtons.
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For the vectors shown in the figure, determine
(Figure 1)
Figure
B (B=26.5)
56.0%
Ā (A = 44.0)
28.0°
C(C=31.0)
< 1 of 1 >
X
the magnitude of B-3A
Express your answer using three significant figures.
|B-3A| =
The magnitude of the given vectors for B - 3A expression is determined as 105.5 m.
What is magnitude of vectors?The magnitude of a vector is the length of the vector. The magnitude of the vector a is denoted as |a|.
The magnitude of a vector represents the absolute value of the given vector.
Magnitude of B - 3AThe magnitude of the expression B - 3A is calculated as follows;
B - 3A = 26.5 - 3(44)
B - 3A = 26.5 - 132
B - 3A = -105.5
|B - 3A| = 105.5
Thus, the magnitude of the given vectors for B - 3A expression is determined as 105.5 m.
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Point of View 10:Question 5
Read the sentences below to answer the question.
Zoe glared at her soccer opponent from across the field. She had practiced all week, but still, she had to conceal the growing lump of fear inside. Was she good enough to defend Star, her greatest rival? Meanwhile, Star kept her focus on the soccer ball, visualizing her first play and identifying the path she would take to the goal.
The narration style in the writing above is..
Select one:
first person
third person omniscient
third person limited
second person
The narration style in the para is third person omniscient
As it narrates the whole incident which is going on.
What is third person omniscient?
The most flexible and open POV available to writers is third person omniscient. An omniscient narrator is one who has all knowledge and all sight, as the name suggests.
The narrator may occasionally access the consciousness of a few or many different characters while the narration is taking place outside of any one particular character.
Some authors employ this viewpoint to build a more "godlike" or purposefully "authorial" persona that enables them to offer dispassionate commentary on the action. Detailed location descriptions that contribute to the mood or atmosphere of a scene may be an example of this, as well as philosophical tangents that serve to develop concepts that only loosely link to the action of the story.
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Question 3: Vectors (13 points)
a. Draw the two vectors below added together. Then draw the sum of the two
vectors. (1 point)
The sum of the vectors is shown in the image attached to this answer.
What is a vector?A vector quantity is a quantity that has both magnitude and direction. In effect, as we try to obtain the combination of the vector we also have to consider the direction. The vectors are often shown by the use of a bold face or by the use of an arrow over the sign of the vector.
Now looking at this vectors, we know that the sum of the vectors can only be obtained geometrically but the arrows of the vectors must have to point in the appropriate directions for the correct sum to be obtained.
Thus the sum of the vectors is shown in the image attached to this answer.
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1. Based on the mc free-body diagram, type an expression for the horizontal acceleration of the cart only in terms of T , mh , mc , μk , and g .
2.Based on the mh free-body diagram, type an expression for the vertical acceleration of the hanging mass.
3. As shown in the first figure, the horizontal acceleration of the cart to the right must be equal to the downward vertical acceleration of the hanging mass if the string does not stretch. Given that both the cart and the hanging mass have the same acceleration, eliminate the tension force ( T ) from your answers to Q1 and Q2 to find an expression for the acceleration only in terms of mh , mc , μk , and g .
(a) The expression for the horizontal acceleration of the cart is
a = (T - μN)/Mc.
(b) The expression for the vertical acceleration of the hanging mass is
a = (T - Mhg)/Mh.
(c) The expression for the acceleration of both cart and the hanging mass is a = (Mhg - μN) / (Mc - Mh).
Horizontal acceleration of the cart
The horizontal acceleration of the cart is calculated as follows;
The horizontal acceleration of the cart is determined from the net horizontal force acting on the system.
T - μN = Mca
where;
Mc is mass of the carta is the acceleration of the carta = (T - μN)/Mc
Vertical acceleration of the hanging massT - Mhg = Mha
where;
Mh is the mass of the hanging massa = (T - Mhg)/Mh
Acceleration of both objectsIf the acceleration of the cart and the hanging mass are equal, our final equation becomes;
From first equation;
a = (T - μN)/Mc
Mca = T - μN
Mca + μN = T
From second equation;
a = (T - Mhg)/Mh
Mha = T - Mhg
Mha + Mhg = T
Solve the two equation together;
Mca + μN = Mha + Mhg
Mca - Mha = Mhg - μN
a(Mc - Mh) = Mhg - μN
a = (Mhg - μN) / (Mc - Mh)
Thus, the expression for the acceleration of both cart and the hanging mass is a = (Mhg - μN) / (Mc - Mh).
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Most doctoral programs in psychology require extensive study
of:
A master's thesis and a dissertation are typically required for clinical psychology programs. Each of these typically takes one to two years.
Psychology doctoral degrees provide students with the training they need to pursue careers in academic research, professional practice, or both. The most common academic degrees awarded are the Doctor of Philosophy (PhD) or the Doctor of Psychology (PsyD). There are notable disparities between the types of training and professional goals of those with these degrees, even though each is intended to engage students in deep knowledge and abilities within an area of psychology. Understanding these variations is the first step in determining which curriculum is the greatest fit for a particular student.
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in a hockey game, player A passes the puck to player B, who is standing on the blue line, as shown in the diagram. The puck travels distance d1=24.1m on its way to player B, making an angle = 52.5 degrees with the x axis. Player B then passes the puck so that it moves d2=7.9m on the blue line in the negative x direction. A) What is the magnitude of the total displacement in meters? B) What angle, in degrees, does the total displacement make with the x axis?
The magnitude of the total displacement is 20.28 m.
The angle of the total displacement with the x axis is 70.5⁰.
Total displacement
The total displacement of the player is calculated as follows.
Apply cosine rule as shown below;
d² = d₁² + d₂² - 2d₁d₂ cos(θ)
d² = (24.1)² + (7.9²) - (2 x 24.1 x 7.9) cos(52.5)
d² = 411.42
d = √411.42
d = 20.28 m
Angle of the displacement with horizontalApply sine rule as shown below;
d/sinD = d₂/sinD₂
20.28/sin(52.5) = 7.9/sinD₂
25.562 = 7.9/sinD₂
sinD₂ = 7.9/25.562
sinD₂ = 0.309
D₂ = sin⁻¹(0.309)
D₂ = 18⁰
angle with x axis = 18⁰ + θ
= 18⁰ + 52.5⁰
= 70.5⁰
Thus, the magnitude of the total displacement is 20.28 m.
The angle of the total displacement with the x axis is 70.5⁰.
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Which of the following is a form of identity fraud?
A. Chipping
B. Skimming
C. Chirping
D. Skipping
An arrow is shot vertically upward and then 1.87 s later passes the top of a tree 39.9 m high. How much longer will the arrow travel upward, how high will it go?
Time :
Height:
In order to determine the amount of time it would take the arrow to travel upward, we would have to first determine its initial velocity by using the second equation of motion.
Note: Since the arrow was projected upward, the acceleration due to gravity would be negative because it indicates deceleration.
From the second equation of motion, we have:
S = ut - ½gt²
39.9 = u(1.87) - ½ × (-10) × 1.87²
39.9 = 1.87u + 17.49
1.87u = 39.9 - 17.49
1.87u = 22.41
u = 22.41/1.87
Initial velocity, u = 11.98 m/s.
Now, we can calculate the amount of time it would take the arrow to travel upward by applying the first equation of motion:
V = u + at
0 = 11.98 + (-10)t
10t = 11.98
t = 11.98/10
Time, t = 1.198 seconds.
How to calculate the maximum height?In order to calculate the maximum height, we would apply the second equation of motion:
S = ut + ½gt²
S = 11.98(1.198) + ½ × (-10) × 1.198²
S = 14.35 - 7.18
Maximum height, S = 7.17 meters.
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What equation is used to determine the total power consumption in a series circuit?
Answer:
PN=P1+P2+P3.......................PN
The full moon subtends about 1/2 of an angular degree. How large is that in units of archminutes? Of arcseconds?
The correct answer is to describe an object's perceived size and describing its position in space. Degrees (°) are used to express angles. A complete circle has 360 °, whereas a straight angle has 90 °. For instance, there is a 90° angle between the horizontal direction (toward the horizon) and the vertical direction (directly above you). The full moon's angular diameter in the sky is around 1/ 2°.
Triangle Units
Divide a complete circle into 360 degrees. Divide a degree into 60 arcminutes, also known as minutes of arc (abbreviated as 60 arcmins or 60'). Divide an arcminute into 60 arcseconds, also known as seconds of arc (abbreviated as 60 arcsec or 60).
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List the octal and hexadecimal numbers from 16 to 32. using A and B for the last two digits, list the numbers from 8 to 28 in base 12
The correct answer is :
In octal,
Decimal 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32
Octal 20 21 22 23 24 25 26 27 30 31 32 33 34 35 36 37 40
Hexadecimal 10 11 12 13 14 15 16 17 18 19 1A 1A 1C 1D 1E 1F 20
Decimal 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28
Base13 8 9 A B C 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 20 21 22
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A cart accelerates at 2m/s² when a force of 60 N is applied. What is the mass of the cart (Formula:F=ma)
The mass of the cart is 30kg
Using Newton's formula which states that Force is given as product of mass and acceleration.
The force is given to be 60N
The acceleration is given to be 2 m/s^2
Using the formula
F=ma
Putting the values of formula,
60 = m x 2
m = 30 kg
Hence the mass of the cart is 30kg
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A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center, as shown in the figure below. (Figure 1)The linear speed of a passenger on the rim is constant and equal to 6.00 m/s .
The centripetal acceleration of the Ferris wheel with radius of 14.0 m is determined as 2.57 m/s².
What is centripetal acceleration?Centripetal acceleration, is the acceleration of a body moving a circular path.
The centripetal acceleration of the Ferris wheel is calculated as follows;
a = v²/r
where;
v is the linear speedr is the radius of the circular patha = (6²) / (14)
a = 2.57 m/s²
Thus, the centripetal acceleration of the Ferris wheel is determined as 2.57 m/s².
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The complete question is below:
A Ferris wheel has a radius of 14 m, the linear speed of a passenger on the rim is 6 m/s .Find the centripetal acceleration of the Ferris wheel.
A 0.25 kg length of aluminum wire is warmed 10.0°C by an electric current. How much heat was generated by the current?
2,302.74 J is the heat generated.
Current electricity is the electricity produced by the movement of electrons. Static electricity is the electricity that accumulates on a substance's surface. Power plants and batteries are used to produce the current electricity.
Electric current in a wire, where electrons serve as the charge carriers, is a measurement of the amount of charge that moves through any point of the wire in a given amount of time.
The mass of the aluminum is m = 0.25 kg.
The difference in temperature is T=10 C.
The following is a list of aluminum's specific heat capacities:
c=921.096 J/kg∘C
Therefore, we apply the following formula in this instance:
Q=mcΔT
We replace with:
Q=(0.25kg)(921.096J/kg∘C)(10∘C)
Thus, we will receive the heat produced:
Q=2,302.74 J
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Which term does 10 m/s to the north
describe?
O time
O acceleration
O position
O velocity
Physics students in a laboratory experiment use a Free-Fall apparatus to determine the acceleration of the gravity, g (as in Fig (a)). The student applies one of the kinematic equations: s=ut+1/2gt2 (where the acceleration, a=g) and decides to rearrange the equation such that in his experiment, he alters the values of the falling distance s (in m) and records the corresponding falling times t (in seconds). In his approach, he decides to plot (on y−axis) 2s/t against t and obtains the following graph (as in Fig (b).) Which of the following best represents the value of the y−intercept (indicated in Fig (b).)?
Select one:
A.
ut
B.
2ut
C.
2s
D.
2u
Answer:
I think it's B but I'm not 100% sure
Abby throws a ball straight up and times it. She sees that the ball goes by the top of a flagpole after 0.50 s and reaches the level of the top of the pole after a total elapsed time of 4.1 s. What was the speed of the ball at launch? Neglect air resistance
The speed of the ball at launch is 23m/s.
After 0.5 seconds, the ball initially passed the pole.
Then it will again reach the top of the pole after 4.1 seconds.
Consequently, the ball's travel time above the pole is
Δt = 4.1 - 0.5 = 3.6sec
Now the time it will take to reach the highest point from the top of the pole is given as t = Δt/2 = 1.8sec.
Now the total time to reach the top from the bottom is given as 2.3sec.
After 0.5 seconds, the ball initially passed the pole.
Consequently, the ball's travel time above the pole is
[tex]v_{f} - v_{i} = at[/tex]
[tex]v_{i}=22.54m/s[/tex]
also the speed after 0.5 s is
[tex]v_{f} = 17.64m/s[/tex]
So, the speed of the ball at launch is 23m/s.
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4. Invalid experiments sometimes result from scientists influencing them
unfairly. This is called:
O Bias
O Scientific Method
O Controlled Experiment
Hypothesis
Answer: Bias
Explanation:
which best describes savanna’s error
Answer:
The FM carrier waves should have different frequencies than the carrier waves, not different amplitudes.
Explanation:
The label at the top of the diagram should be “FM Radio,” not “Cell Phone.
A 1.2kg stone is tied to string and swung in a vertical circle with a radius of 0.85 m. The string can withstand a tension of 40.0 N. At the maximum speed can the stone move at the bottom of its path without the string breaking
The maximum speed of the stone tied to the string is 5.32 m/s.
The mass of the stone is m = 1.2 kg.
The mass is tied to a string and it swung in a vertical radius of r = 0.85 cm.
The tension on the string is T = 40 N.
The centripetal force of a body moving in a circle of radius r is given as:
T = ( mv² / r )
Where T is the tension, m is the mass of the body and r is the radius of the circle.
Then,
v² = ( T × r ) / m
v = √ [ T × r / m ]
v = √ [ 40 × 0.85 / 1.2 ]
v = √ [ 34 / 1.2 ]
v = √28.3
v = 5.32 m/s
The maximum speed of the stone before the string breaks is 5.32 m/s.
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what are the defining characteristics of matter
A Mass and time
B Mass and volume
C Mass and space
D volume and motion
I need help with part B plsss !!
The time taken for the object to travel the given height is determined as 12.48 seconds.
What is time of motion?
Time of motion of an object is the total time taken by the object to travel a given height or distance.
Time taken for the boulder to reach the groundThe time of motion of the boulder is calculated as follows;
h = vt + ¹/₂gt²
where;
h is the height of fallv is the initial velocityt is the time of motiong is acceleration due to gravity1300 = 43t + 0.5(9.8)t²
1300 = 43t + 4.9t²
4.9t² + 43t - 1300 = 0
solve the quadratic equation using formula method as shown below;
a = 4.9, b = 43, c = -1300
t = 12.48 seconds
Thus, the time taken for the object to travel the given height is determined as 12.48 seconds.
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Layla jogs with an average velocity of 2.4 m/s east. What is her displacement after 46 seconds?
Answer:
[tex]{ \tt{displacement = velocity \times time }} \\ { \tt{ = 2.4 \times 46}} \\ { \tt{ = 110.4 \: m}}[/tex]
The precise way a researcher measures and defines a variable is know as the
The precise way a researcher measures and defines a variable is known as the operational definition.
The researcher measures the dependent variable and the independent variable is manipulated and controlled by the researcher ( Experimenter ). The concept of operational definition is applied in various fields such as Philosophy, Science, Business, computing etc.
To explain this clearly, let's consider an example in which the researcher tries to define sleep deprivation. In this sleep deprivation is the independent variable and factors causing sleep deprivation such as food, lifestyle, etc are dependent variables.
Therefore, the precise way a researcher measures and defines a variable is known as the operational definition.
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A ball is dropped. Assuming free fall, what is its initial speed?
For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.
The supplied problem informs us that a ball was dropped and is supposed to be falling freely. Since the problem does not specify whether any other forces were present to influence the ball's motion, we must assume that the initial speed is v0=0 m/s.
Free-falling accelerates at a rate of 9.8 m/s2, which is referred to as the acceleration owing to gravity because it is being drawn towards the center of the earth. This indicates that a=9.8m/s2 is the value of the initial and final accelerations.
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How does the mass of an object affect the potential and kinetic energy?
Answer:
The more mass the more kinetic energy it has
Explanation:
like a plastic ball and a metal one the metal one will fall faster.
hope this helps